我只是寻找_sdk， _sdk_或sdk_，甚至只是sdk部分构建。产品:

if(Build.PRODUCT.matches(".*_?sdk_?.*")){
  //-- emulator --
}else{
  //-- other device --
}

上面建议的检查ANDROID_ID的解决方案对我来说很有效，直到我今天更新到Android 2.2发布的最新SDK工具。

因此，我目前切换到以下解决方案，到目前为止，缺点是你需要把PHONE_STATE读取权限(<uses-permission android:name="android.permission. read_phone_state "/>)

private void checkForDebugMode() {
    ISDEBUGMODE = false; //(Secure.getString(getApplicationContext().getContentResolver(), Secure.ANDROID_ID) == null);

    TelephonyManager man = (TelephonyManager) getApplicationContext().getSystemService(Context.TELEPHONY_SERVICE);
    if(man != null){
        String devId = man.getDeviceSoftwareVersion();
        ISDEBUGMODE = (devId == null);
    }
} 

用下面的代码来判断你的应用是否使用了调试键?它没有检测模拟器，但它可能为您的目的工作?

public void onCreate Bundle b ) {
   super.onCreate(savedInstanceState);
   if ( signedWithDebugKey(this,this.getClass()) ) {
     blah blah blah
   }

  blah 
    blah 
      blah

}

static final String DEBUGKEY = 
      "get the debug key from logcat after calling the function below once from the emulator";    


public static boolean signedWithDebugKey(Context context, Class<?> cls) 
{
    boolean result = false;
    try {
        ComponentName comp = new ComponentName(context, cls);
        PackageInfo pinfo = context.getPackageManager().getPackageInfo(comp.getPackageName(),PackageManager.GET_SIGNATURES);
        Signature sigs[] = pinfo.signatures;
        for ( int i = 0; i < sigs.length;i++)
        Log.d(TAG,sigs[i].toCharsString());
        if (DEBUGKEY.equals(sigs[0].toCharsString())) {
            result = true;
            Log.d(TAG,"package has been signed with the debug key");
        } else {
            Log.d(TAG,"package signed with a key other than the debug key");
        }

    } catch (android.content.pm.PackageManager.NameNotFoundException e) {
        return false;
    }

    return result;

} 

这个解决方案怎么样(SystemProperties的类实现在这里可用):

val isProbablyRunningOnEmulator: Boolean by lazy {
    // Android SDK emulator
    return@lazy ((Build.MANUFACTURER == "Google" && Build.BRAND == "google" &&
            ((Build.FINGERPRINT.startsWith("google/sdk_gphone_")
                    && Build.FINGERPRINT.endsWith(":user/release-keys")
                    && Build.PRODUCT.startsWith("sdk_gphone_")
                    && Build.MODEL.startsWith("sdk_gphone_"))
                    //alternative
                    || (Build.FINGERPRINT.startsWith("google/sdk_gphone64_")
                    && (Build.FINGERPRINT.endsWith(":userdebug/dev-keys") || Build.FINGERPRINT.endsWith(":user/release-keys"))
                    && Build.PRODUCT.startsWith("sdk_gphone64_")
                    && Build.MODEL.startsWith("sdk_gphone64_"))))
            //
            || Build.FINGERPRINT.startsWith("generic")
            || Build.FINGERPRINT.startsWith("unknown")
            || Build.MODEL.contains("google_sdk")
            || Build.MODEL.contains("Emulator")
            || Build.MODEL.contains("Android SDK built for x86")
            //bluestacks
            || "QC_Reference_Phone" == Build.BOARD && !"Xiaomi".equals(Build.MANUFACTURER, ignoreCase = true)
            //bluestacks
            || Build.MANUFACTURER.contains("Genymotion")
            || Build.HOST.startsWith("Build")
            //MSI App Player
            || Build.BRAND.startsWith("generic") && Build.DEVICE.startsWith("generic")
            || Build.PRODUCT == "google_sdk"
            // another Android SDK emulator check
            || SystemProperties.getProp("ro.kernel.qemu") == "1")
}

请注意，一些模拟器伪造真实设备的精确规格，因此可能无法检测到它。我已经添加了我能添加的东西，但我不认为有100%的方法来检测它是否真的是一个模拟器。

这里有一个你可以在APK中创建的小片段来展示关于它的各种事情，所以你可以添加自己的规则:

        textView.text = "FINGERPRINT:${Build.FINGERPRINT}\n" +
                "MODEL:${Build.MODEL}\n" +
                "MANUFACTURER:${Build.MANUFACTURER}\n" +
                "BRAND:${Build.BRAND}\n" +
                "DEVICE:${Build.DEVICE}\n" +
                "BOARD:${Build.BOARD}\n" +
                "HOST:${Build.HOST}\n" +
                "PRODUCT:${Build.PRODUCT}\n"

安卓id不适合我，我现在用的是:

"google_sdk".equals( Build.PRODUCT );

这对我来说是有效的，而不是startwith: Build.FINGERPRINT.contains("generic")

欲了解更多信息，请查看这个链接:https://gist.github.com/espinchi/168abf054425893d86d1