对于Python 3.4+，使用新的统计模块中的mean()来计算平均值:

from statistics import mean
xs = [15, 18, 2, 36, 12, 78, 5, 6, 9]
mean(xs)

简单的解决方案是avmedii -lib

pip install avemedi_lib

而不是包括在你的剧本中

from avemedi_lib.functions import average, get_median, get_median_custom


test_even_array = [12, 32, 23, 43, 14, 44, 123, 15]
test_odd_array = [1, 2, 3, 4, 5, 6, 7, 8, 9]

# Getting average value of list items
print(average(test_even_array))  # 38.25

# Getting median value for ordered or unordered numbers list
print(get_median(test_even_array))  # 27.5
print(get_median(test_odd_array))  # 27.5

# You can use your own sorted and your count functions
a = sorted(test_even_array)
n = len(a)

print(get_median_custom(a, n))  # 27.5

享受。

当Python有一个完美的cromulent sum()函数时，为什么要使用reduce()呢?

print sum(l) / float(len(l))

(float()在Python 2中强制Python执行浮点除法是必需的。)

在列表中求平均值 通过使用以下PYTHON代码:

l = [15, 18, 2, 36, 12, 78, 5, 6, 9]
print(sum(l)//len(l))

试着简单一点。

使用numpy.mean:

xs = [15, 18, 2, 36, 12, 78, 5, 6, 9]

import numpy as np
print(np.mean(xs))

numbers = [0,1,2,3]

numbers[0] = input("Please enter a number")

numbers[1] = input("Please enter a second number")

numbers[2] = input("Please enter a third number")

numbers[3] = input("Please enter a fourth number")

print (numbers)

print ("Finding the Avarage")

avarage = int(numbers[0]) + int(numbers[1]) + int(numbers[2]) + int(numbers [3]) / 4

print (avarage)