我想创建一个随机字符串,由字母-数字字符组成。我希望能够指定字符串的长度。
如何在c++中做到这一点?
我想创建一个随机字符串,由字母-数字字符组成。我希望能够指定字符串的长度。
如何在c++中做到这一点?
当前回答
我刚刚测试了这个,它工作得很好,不需要查找表。Rand_alnum()在某种程度上强制输出字母数字,但因为它从可能的256个字符中选择62个,所以这不是什么大问题。
#include <cstdlib> // for rand()
#include <cctype> // for isalnum()
#include <algorithm> // for back_inserter
#include <string>
char
rand_alnum()
{
char c;
while (!std::isalnum(c = static_cast<char>(std::rand())))
;
return c;
}
std::string
rand_alnum_str (std::string::size_type sz)
{
std::string s;
s.reserve (sz);
generate_n (std::back_inserter(s), sz, rand_alnum);
return s;
}
其他回答
标准库中最合适的函数是std::sample:
#include <algorithm>
#include <iterator>
#include <random>
#include <string>
#include <iostream>
static const char charset[] =
"0123456789"
"ABCDEFGHIJKLMNOPQRSTUVWXYZ"
"abcdefghijklmnopqrstuvwxyz";
template<typename URBG>
std::string gen_string(std::size_t length, URBG&& g) {
std::string result;
result.resize(length);
std::sample(std::cbegin(charset),
std::cend(charset),
std::begin(result),
std::intptr_t(length),
std::forward<URBG>(g));
return result;
}
int main() {
std::mt19937 g;
std::cout << gen_string(10, g) << std::endl;
std::cout << gen_string(10, g) << std::endl;
}
随机数生成器的状态应该在调用之间保持在函数之外。
我希望这能帮助到一些人。
在https://www.codechef.com/ide上用c++ 4.9.2测试
#include <iostream>
#include <string>
#include <stdlib.h> /* srand, rand */
using namespace std;
string RandomString(int len)
{
string str = "0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz";
string newstr;
int pos;
while(newstr.size() != len) {
pos = ((rand() % (str.size() - 1)));
newstr += str.substr(pos,1);
}
return newstr;
}
int main()
{
srand(time(0));
string random_str = RandomString(100);
cout << "random_str : " << random_str << endl;
}
输出: random_str: DNAT1LAmbJYO0GvVo4LGqYpNcyK3eZ6t0IN3dYpHtRfwheSYipoZOf04gK7OwFIwXg2BHsSBMB84rceaTTCtBC0uZ8JWPdVxKXBd
随机字符串,每个运行文件=不同的字符串
auto randchar = []() -> char
{
const char charset[] =
"ABCDEFGHIJKLMNOPQRSTUVWXYZ"
"abcdefghijklmnopqrstuvwxyz";
const size_t max_index = (sizeof(charset) - 1);
return charset[randomGenerator(0, max_index)];
};
std::string custom_string;
size_t LENGTH_NAME = 6 // length of name
generate_n(custom_string.begin(), LENGTH_NAME, randchar);
//C++ Simple Code
#include <bits/stdc++.h>
using namespace std;
int main() {
vector<char> alphanum =
{'0','1','2','3','4',
'5','6','7','8','9',
'A','B','C','D','E','F',
'G','H','I','J','K',
'L','M','N','O','P',
'Q','R','S','T','U',
'V','W','X','Y','Z',
'a','b','c','d','e','f',
'g','h','i','j','k',
'l','m','n','o','p',
'q','r','s','t','u',
'v','w','x','y','z'
};
string s="";
int len=5;
srand(time(0));
for (int i = 0; i <len; i++) {
int t=alphanum.size()-1;
int idx=rand()%t;
s+= alphanum[idx];
}
cout<<s<<" ";
return 0;
}
这里有一个有趣的单句。需要ASCII。
void gen_random(char *s, int l) {
for (int c; c=rand()%62, *s++ = (c+"07="[(c+16)/26])*(l-->0););
}