我想创建一个随机字符串,由字母-数字字符组成。我希望能够指定字符串的长度。

如何在c++中做到这一点?


当前回答

我刚刚测试了这个,它工作得很好,不需要查找表。Rand_alnum()在某种程度上强制输出字母数字,但因为它从可能的256个字符中选择62个,所以这不是什么大问题。

#include <cstdlib>   // for rand()
#include <cctype>    // for isalnum()   
#include <algorithm> // for back_inserter
#include <string>

char 
rand_alnum()
{
    char c;
    while (!std::isalnum(c = static_cast<char>(std::rand())))
        ;
    return c;
}


std::string 
rand_alnum_str (std::string::size_type sz)
{
    std::string s;
    s.reserve  (sz);
    generate_n (std::back_inserter(s), sz, rand_alnum);
    return s;
}

其他回答

标准库中最合适的函数是std::sample:

#include <algorithm>
#include <iterator>
#include <random>
#include <string>
#include <iostream>

static const char charset[] = 
    "0123456789"
    "ABCDEFGHIJKLMNOPQRSTUVWXYZ"
    "abcdefghijklmnopqrstuvwxyz";

template<typename URBG>
std::string gen_string(std::size_t length, URBG&& g) {
    std::string result;
    result.resize(length);
    std::sample(std::cbegin(charset), 
                std::cend(charset),
                std::begin(result),
                std::intptr_t(length),
                std::forward<URBG>(g));
    return result;
}

int main() {
    std::mt19937 g;
    std::cout << gen_string(10, g) << std::endl;
    std::cout << gen_string(10, g) << std::endl;
}

随机数生成器的状态应该在调用之间保持在函数之外。

我希望这能帮助到一些人。

在https://www.codechef.com/ide上用c++ 4.9.2测试

#include <iostream>
#include <string>
#include <stdlib.h>     /* srand, rand */

using namespace std;

string RandomString(int len)
{
   string str = "0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz";
   string newstr;
   int pos;
   while(newstr.size() != len) {
    pos = ((rand() % (str.size() - 1)));
    newstr += str.substr(pos,1);
   }
   return newstr;
}

int main()
{
   srand(time(0));
   string random_str = RandomString(100);
   cout << "random_str : " << random_str << endl;
}

输出: random_str: DNAT1LAmbJYO0GvVo4LGqYpNcyK3eZ6t0IN3dYpHtRfwheSYipoZOf04gK7OwFIwXg2BHsSBMB84rceaTTCtBC0uZ8JWPdVxKXBd

随机字符串,每个运行文件=不同的字符串

        auto randchar = []() -> char
    {
        const char charset[] =
            "ABCDEFGHIJKLMNOPQRSTUVWXYZ"
            "abcdefghijklmnopqrstuvwxyz";

        const size_t max_index = (sizeof(charset) - 1);

        return charset[randomGenerator(0, max_index)];
    };
            std::string custom_string;
            size_t LENGTH_NAME = 6 // length of name
    generate_n(custom_string.begin(), LENGTH_NAME, randchar);
//C++ Simple Code
#include <bits/stdc++.h>
using namespace std;
int main() {
vector<char> alphanum =
    {'0','1','2','3','4',
'5','6','7','8','9',
'A','B','C','D','E','F',
'G','H','I','J','K',
'L','M','N','O','P',
'Q','R','S','T','U',
'V','W','X','Y','Z',
'a','b','c','d','e','f',
'g','h','i','j','k',
'l','m','n','o','p',
'q','r','s','t','u',
'v','w','x','y','z'
};
string s="";
int len=5;
srand(time(0)); 
for (int i = 0; i <len; i++) {
    int t=alphanum.size()-1;
    int idx=rand()%t;
    s+= alphanum[idx];
}
cout<<s<<" ";
return 0;
}

这里有一个有趣的单句。需要ASCII。

void gen_random(char *s, int l) {
    for (int c; c=rand()%62, *s++ = (c+"07="[(c+16)/26])*(l-->0););
}