最近,我一直试图从这个网站学习c++。不幸的是,每当我试图运行其中一个代码示例时,我看到该程序打开了大约半秒钟,然后立即关闭。有没有办法阻止程序立即关闭,以便我能看到我的努力的成果?


当前回答

简单的

#include <cstdio>

    int main(){
        // code...
        std::getchar();
        std::getchar();
        return 0;
    }

for some reason there is usually 1 character possible to read with getchar already in stdin when you run a program. so the first getchar reads this character, and the second getchar waits for user (your) input before exiting the program. And after a program exits most of terminals, especially on Windows close terminal immediately. so what we aim to is a simple way of preventing a program from finishing after it outputs everything. Of course there are more complex and clean ways to solve this, but this is the simplest.

其他回答

包括conio.h,在代码的末尾,在返回0之前,写入_getch();

调用cin.get ();2次:

    //...
    cin.get();
    cin.get();
    return 0
}

我在程序的最后一个返回0处设置了断点。它工作得很好。

只需在程序的末尾添加以下内容。它将尝试捕获某种形式的用户输入,从而阻止控制台自动关闭。

cin.get();

如果你正在运行Windows,那么你可以执行system("pause >nul");或系统(“暂停”);。它执行一个控制台命令来暂停程序,直到您按下一个键。>nul阻止它说按任意键继续....