最近,我一直试图从这个网站学习c++。不幸的是,每当我试图运行其中一个代码示例时,我看到该程序打开了大约半秒钟,然后立即关闭。有没有办法阻止程序立即关闭,以便我能看到我的努力的成果?


当前回答

简单的

#include <cstdio>

    int main(){
        // code...
        std::getchar();
        std::getchar();
        return 0;
    }

for some reason there is usually 1 character possible to read with getchar already in stdin when you run a program. so the first getchar reads this character, and the second getchar waits for user (your) input before exiting the program. And after a program exits most of terminals, especially on Windows close terminal immediately. so what we aim to is a simple way of preventing a program from finishing after it outputs everything. Of course there are more complex and clean ways to solve this, but this is the simplest.

其他回答

简单的

#include <cstdio>

    int main(){
        // code...
        std::getchar();
        std::getchar();
        return 0;
    }

for some reason there is usually 1 character possible to read with getchar already in stdin when you run a program. so the first getchar reads this character, and the second getchar waits for user (your) input before exiting the program. And after a program exits most of terminals, especially on Windows close terminal immediately. so what we aim to is a simple way of preventing a program from finishing after it outputs everything. Of course there are more complex and clean ways to solve this, but this is the simplest.

对于Visual Studio(并且只有Visual Studio),下面的代码片段给了你一个'wait For keypress to continue'提示,它真正地等待用户显式地按下一个新键,首先刷新输入缓冲区:

#include <cstdio>
#include <tchar.h>
#include <conio.h>

_tprintf(_T("Press a key to continue "));
while( _kbhit() /* defined in conio.h */ ) _gettch();
_gettch();

注意,这里使用了tchar.h宏来兼容多个“字符集”(vc++称之为字符集)。

我只是这样做:

//clear buffer, wait for input to close program
std::cin.clear(); std::cin.ignore(INT_MAX, '\n');
std::cin.get();
return 0;

注意:只有在程序早期使用过cin时,才需要清除cin缓冲区。同样使用std::numeric_limits::max()可能比INT_MAX更好,但它有点啰嗦,通常没有必要。

如果您正在使用Visual Studio,并且正在从IDE启动控制台应用程序:

按CTRL-F5(启动而不调试)将启动应用程序并保持控制台窗口打开,直到按下任何键。

编辑:正如Charles Bailey在下面的评论中正确指出的那样,如果stdin中缓冲了字符,这将不起作用,而且真的没有好方法来解决这个问题。如果运行时附带调试器,John Dibling建议的解决方案可能是解决问题的最干净的解决方案。

也就是说,我把它留在这里,也许其他人会觉得它有用。在开发期间编写测试时,我经常使用它作为一种快速的方法。


在main函数的末尾,你可以调用std::getchar();

这将从stdin中获取单个字符,从而为您提供“按任意键继续”类型的行为(如果您确实想要“按任意键”消息,则必须自己打印一条)。

你需要为getchar添加#include <cstdio>。