我怎么能在多行分割字符串,如下面?
var text:String = "This is some text
over multiple lines"
我怎么能在多行分割字符串,如下面?
var text:String = "This is some text
over multiple lines"
当前回答
我在String上使用了一个扩展来实现多行字符串,同时避免编译器挂起的错误。它还允许您指定分隔符,以便您可以像使用Python的join函数一样使用它
extension String {
init(sep:String, _ lines:String...){
self = ""
for (idx, item) in lines.enumerated() {
self += "\(item)"
if idx < lines.count-1 {
self += sep
}
}
}
init(_ lines:String...){
self = ""
for (idx, item) in lines.enumerated() {
self += "\(item)"
if idx < lines.count-1 {
self += "\n"
}
}
}
}
print(
String(
"Hello",
"World!"
)
)
"Hello
World!"
print(
String(sep:", ",
"Hello",
"World!"
)
)
"Hello, World!"
其他回答
样本
var yourString = "first line \n second line \n third line"
以防您发现+运算符不合适
Swift 4通过提供多行字符串文字支持解决了这个问题。要开始字符串字面量,添加三个双引号(" " " ")并按回车键,按回车键后开始写带有任何变量的字符串,换行符和双引号,就像你在记事本或任何文本编辑器中写的那样。要结束多行字符串文字再次写入(" " ")在新行。
参见下面的例子
let multiLineStringLiteral = """
This is one of the best feature add in Swift 4
It let’s you write “Double Quotes” without any escaping
and new lines without need of “\n”
"""
print(multiLineStringLiteral)
你可以使用unicode equals for enter或\n并在你的字符串中实现它们。例如:\u{0085}。
另一种方法是,如果你想使用带有预定义文本的字符串变量,
var textFieldData:String = "John"
myTextField.text = NSString(format: "Hello User, \n %@",textFieldData) as String
myTextField.numberOfLines = 0
下面的例子描述了一个多行连续,使用圆括号作为一个简单的解决方法,以解决Xcode 6.2 Beta版本的Swift错误,它抱怨表达式太复杂,无法在合理的时间内解析,并考虑将其分解为更小的片段:
.
.
.
return String(format:"\n" +
(" part1: %d\n" +
" part2: %d\n" +
" part3: \"%@\"\n" +
" part4: \"%@\"\n" +
" part5: \"%@\"\n" +
" part6: \"%@\"\n") +
(" part7: \"%@\"\n" +
" part8: \"%@\"\n" +
" part9: \"%@\"\n" +
" part10: \"%@\"\n" +
" part12: \"%@\"\n") +
" part13: %f\n" +
" part14: %f\n\n",
part1, part2, part3, part4, part5, part6, part7, part8,
part9, part10, part11, part12, part13, part14)
.
.
.