样本

var yourString = "first line \n second line \n third line"

以防您发现+运算符不合适

下面是一个代码片段，用n个字符分隔字符串:

//: A UIKit based Playground for presenting user interface

import UIKit
import PlaygroundSupport

class MyViewController : UIViewController {
    override func loadView() {

        let str = String(charsPerLine: 5, "Hello World!")
        print(str) // "Hello\n Worl\nd!\n"

    }
}

extension String {

    init(charsPerLine:Int, _ str:String){

        self = ""
        var idx = 0
        for char in str {
            self += "\(char)"
            idx = idx + 1
            if idx == charsPerLine {
                self += "\n"
                idx = 0
            }
        }

    }
}

另一种方法是，如果你想使用带有预定义文本的字符串变量，

var textFieldData:String = "John"
myTextField.text = NSString(format: "Hello User, \n %@",textFieldData) as String
myTextField.numberOfLines = 0

Swift 4通过提供多行字符串文字支持解决了这个问题。要开始字符串字面量，添加三个双引号(" " " ")并按回车键，按回车键后开始写带有任何变量的字符串，换行符和双引号，就像你在记事本或任何文本编辑器中写的那样。要结束多行字符串文字再次写入(" " ")在新行。

参见下面的例子

     let multiLineStringLiteral = """
    This is one of the best feature add in Swift 4
    It let’s you write “Double Quotes” without any escaping
    and new lines without need of “\n”
    """

print(multiLineStringLiteral)

加上@Connor的回答，也需要有\n。以下是修改后的代码:

var text:String = "This is some text \n" +
                  "over multiple lines"

你可以使用unicode equals for enter或\n并在你的字符串中实现它们。例如:\u{0085}。