我不认为顺序是可以保证的，否则就很容易切片Object的后半部分。条目的结果和映射来自那里。

上述答案的唯一(非常小的)问题是

字符串和数字之间有很多不必要的类型转换。 当一次迭代同样干净有效时，条目将迭代两次。

type StandardEnum = { [id: string]: number | string; [nu: number]: string;}

function enumToList<T extends StandardEnum> (enm: T) : { id: number; description: string }[] {
    return Object.entries(enm).reduce((accum, kv) => {
        if (typeof kv[1] === 'number') {
            accum.push({ id: kv[1], description: kv[0] })
        }
        return accum
    }, []) // if enum is huge, perhaps pre-allocate with new Array(entries.length / 2), however then push won't work, so tracking an index would also be required
}

你可以这样做:

export enum GoalProgressMeasurements {
    Percentage = 1,
    Numeric_Target = 2,
    Completed_Tasks = 3,
    Average_Milestone_Progress = 4,
    Not_Measured = 5
}

export class GoalProgressMeasurement {
    constructor(public goalProgressMeasurement: GoalProgressMeasurements, public name: string) {
    }
}

export var goalProgressMeasurements: { [key: number]: GoalProgressMeasurement } = {
    1: new GoalProgressMeasurement(GoalProgressMeasurements.Percentage, "Percentage"),
    2: new GoalProgressMeasurement(GoalProgressMeasurements.Numeric_Target, "Numeric Target"),
    3: new GoalProgressMeasurement(GoalProgressMeasurements.Completed_Tasks, "Completed Tasks"),
    4: new GoalProgressMeasurement(GoalProgressMeasurements.Average_Milestone_Progress, "Average Milestone Progress"),
    5: new GoalProgressMeasurement(GoalProgressMeasurements.Not_Measured, "Not Measured"),
}

你可以这样使用它:

var gpm: GoalProgressMeasurement = goalProgressMeasurements[GoalProgressMeasurements.Percentage];
var gpmName: string = gpm.name;

var myProgressId: number = 1; // the value can come out of drop down selected value or from back-end , so you can imagine the way of using
var gpm2: GoalProgressMeasurement = goalProgressMeasurements[myProgressId];
var gpmName: string = gpm.name;

您可以根据需要使用对象的附加属性扩展GoalProgressMeasurement。我将这种方法用于每个应该是包含多个值的对象的枚举。

首先，我们得到这个枚举的键数组。然后，使用map()函数将数据转换为所需的格式。Id从键获取，name从enum通过相同的键获取。

const converted = Object.keys(GoalProgressMeasurements).map(key => {
        return {
            id: GoalProgressMeasurements[key],
            name: key,
        };
    });

简单的解决方案。您可以使用以下函数将Enum转换为对象数组。

 buildGoalProgressMeasurementsArray(): Object[] {

    return Object.keys(GoalProgressMeasurements)
              .map(key => ({ id: GoalProgressMeasurements[key], name: key }))
 }

如果你需要去掉下划线，我们可以像下面这样使用regex:

buildGoalProgressMeasurementsArray(): Object[] {

    return Object.keys(GoalProgressMeasurements)
              .map(key => ({ id: GoalProgressMeasurements[key], name: key.replace(/_/g, ' ') }))
 }

TS:

仅适用于短(<10个元素)enum

const keys = Object.keys(Enum).filter((el: string) => el.length > 1)
console.log(keys)

Object.keys()将返回一个包含['0'，'1'，'2'，'enumElement1'， 'enumElement2'， enumElement3']的数组 Filter()获取每个元素并检查其长度(因为字符串)，并从结果数组中排除所有数字

如果你使用的是ES8

只有在这种情况下，它才会工作得很好。它会给你给定枚举的值数组。

enum Colors {
  WHITE = 0,
  BLACK = 1,
  BLUE = 3
}

const colorValueArray = Object.values(Colors); //[ 'WHITE', 'BLACK', 'BLUE', 0, 1, 3 ]

你会得到这样的colorValueArray ['WHITE'， 'BLACK'， 'BLUE'， 0,1,3]。所有的键都在数组的前半部分，所有的值都在数组的后半部分。

甚至这种枚举也可以正常工作

enum Operation {
    READ,
    WRITE,
    EXECUTE
}

但是这种解决方案不适用于这样的异构枚举

enum BooleanLikeHeterogeneousEnum {
  No = 0,
  Yes = "YES",
}