我不认为顺序是可以保证的，否则就很容易切片Object的后半部分。条目的结果和映射来自那里。

上述答案的唯一(非常小的)问题是

字符串和数字之间有很多不必要的类型转换。 当一次迭代同样干净有效时，条目将迭代两次。

type StandardEnum = { [id: string]: number | string; [nu: number]: string;}

function enumToList<T extends StandardEnum> (enm: T) : { id: number; description: string }[] {
    return Object.entries(enm).reduce((accum, kv) => {
        if (typeof kv[1] === 'number') {
            accum.push({ id: kv[1], description: kv[0] })
        }
        return accum
    }, []) // if enum is huge, perhaps pre-allocate with new Array(entries.length / 2), however then push won't work, so tracking an index would also be required
}

枚举是运行时存在的真实对象。所以你可以这样反向映射:

let value = GoalProgressMeasurements.Not_Measured;
console.log(GoalProgressMeasurements[value]);
// => Not_Measured

基于此，您可以使用以下代码:

export enum GoalProgressMeasurements {
    Percentage = 1,
    Numeric_Target = 2,
    Completed_Tasks = 3,
    Average_Milestone_Progress = 4,
    Not_Measured = 5
}

let map: {id: number; name: string}[] = [];

for(var n in GoalProgressMeasurements) {
    if (typeof GoalProgressMeasurements[n] === 'number') {
        map.push({id: <any>GoalProgressMeasurements[n], name: n});
    }
}

console.log(map);

参考:https://www.typescriptlang.org/docs/handbook/enums.html

简单的解决方案。您可以使用以下函数将Enum转换为对象数组。

 buildGoalProgressMeasurementsArray(): Object[] {

    return Object.keys(GoalProgressMeasurements)
              .map(key => ({ id: GoalProgressMeasurements[key], name: key }))
 }

如果你需要去掉下划线，我们可以像下面这样使用regex:

buildGoalProgressMeasurementsArray(): Object[] {

    return Object.keys(GoalProgressMeasurements)
              .map(key => ({ id: GoalProgressMeasurements[key], name: key.replace(/_/g, ' ') }))
 }

另一种方法是使用ES8 Object.entries

export enum Weeks {  
    MONDAY = 1,  
    TUESDAY= 2,  
    WEDNESDAY = 3,  
    THURSDAY = 4,  
    FRIDAY = 5,  
    SATURDAY=6,  
    SUNDAY=7,  
}


function convertEnumToArray(){
   const arrayObjects = []            
     // Retrieve key and values using Object.entries() method. 
     for (const [propertyKey, propertyValue] of Object.entries(Weeks)) { 

      // Ignore keys that are not numbers
      if (!Number.isNaN(Number(propertyKey))) {  
        continue;  
      }  

      // Add keys and values to array
      arrayObjects.push({ id: propertyValue, name: propertyKey });  
    }        

  console.log(arrayObjects); 
}

将产生以下内容:

[ 
  { id: 1, name: 'MONDAY' },  
  { id: 2, name: 'TUESDAY' },  
  { id: 3, name: 'WEDNESDAY' },  
  { id: 4, name: 'THURSDAY' },  
  { id: 5, name: 'FRIDAY' },  
  { id: 6, name: 'SATURDAY' },  
  { id: 7, name: 'SUNDAY' } 
] 

无耻地从这个博客偷来的

该方法基于语句: enum的键不能是数字

export const isNumeric = (num?: Value | null): num is number => {
  if (num === undefined || num === null) {
    return false;
  } 
  
  const number = +num;

  if (number - number !== 0) {
    // Discard Infinity and NaN
    return false;
  }

  if (number === num) {
    return true;
  }

  if (typeof num === 'string') {
    return !(number === 0 && num.trim() === '');
  }
  return false;
};

enum En  {
  ewq1 = 1,
  we2 = 'ss',
  sad = 'sad',
}

type TEnum = {
    [id: string]: number | string;
}

export const getEnumValues = <T extends TEnum>(enumerable: T) =>
  Object.keys(enumerable)
    .filter((x) => !isNumeric(x))
    .map((key) => enumerable[key] as T[keyof T]) 

console.log(getEnumValues(En)) // [1, "ss", "sad"] 

 this worked for me :

    export enum FeedBackType {
    FEEDBACK1= 'FEEDBACK1',
    FEEDBACK2= 'FEEDBACK2',
    FEEDBACK3= 'FEEDBACK3',
    }

----------------------------------------------------------------- 
    export function getTypeFeedBackList() {
    let feedbackList: FeedBackType[] = [];
    Object.keys(FeedBackType).map((key) => {
    let strEnum = key as unknown as FeedBackType;
    feedbackList.push(strEnum);
    });
    return feedbackList;
    }
---------------------------------------------------------------- 
declare this :

    public feedbackList: FeedBackType[] = [];

and after call your function in  :

    ngOnInit(): void {
    this.feedbackList = getTypeFeedBackList();
    console.log(this.feedbackList); 
    }

Happy coding ;)