class EnumHelpers {

    static getNamesAndValues<T extends number>(e: any) {
        return EnumHelpers.getNames(e).map(n => ({ name: n, value: e[n] as T }));
    }

    static getNames(e: any) {
        return EnumHelpers.getObjValues(e).filter(v => typeof v === 'string') as string[];
    }

    static getValues<T extends number>(e: any) {
        return EnumHelpers.getObjValues(e).filter(v => typeof v === 'number') as T[];
    }

    static getSelectList<T extends number, U>(e: any, stringConverter: (arg: U) => string) {
        const selectList = new Map<T, string>();
        this.getValues(e).forEach(val => selectList.set(val as T, stringConverter(val as unknown as U)));
        return selectList;
    }

    static getSelectListAsArray<T extends number, U>(e: any, stringConverter: (arg: U) => string) {
        return Array.from(this.getSelectList(e, stringConverter), value => ({ value: value[0] as T, presentation: value[1] }));
    }

    private static getObjValues(e: any): (number | string)[] {
        return Object.keys(e).map(k => e[k]);
    }
}

export function enumKeys(E: any): string[] {
    return Object.keys(E).filter(k => isNaN(Number(k)));
}

export function enumValues(E: any): string[] | number[] {
    return enumKeys(E).map(k => E[k as any]);
}

两者都适用:

enum TestA {
    RED = "red",
    BLUE = "blue"
}

enum TestB {
    ONE = 1,
    TWO = 2
}

枚举是运行时存在的真实对象。所以你可以这样反向映射:

let value = GoalProgressMeasurements.Not_Measured;
console.log(GoalProgressMeasurements[value]);
// => Not_Measured

基于此，您可以使用以下代码:

export enum GoalProgressMeasurements {
    Percentage = 1,
    Numeric_Target = 2,
    Completed_Tasks = 3,
    Average_Milestone_Progress = 4,
    Not_Measured = 5
}

let map: {id: number; name: string}[] = [];

for(var n in GoalProgressMeasurements) {
    if (typeof GoalProgressMeasurements[n] === 'number') {
        map.push({id: <any>GoalProgressMeasurements[n], name: n});
    }
}

console.log(map);

参考:https://www.typescriptlang.org/docs/handbook/enums.html

我很惊讶，在一个TypeScript线程中，没有人给出支持类型的有效TypeScript函数。下面是@user8363解决方案的变化:

const isStringNumber = (value: string) => isNaN(Number(value)) === false;

function enumToArray<T extends {}>(givenEnum: T) {
  return (Object.keys(givenEnum).filter(isStringNumber) as (keyof T)[]).map(
    (key) => givenEnum[key]
  );
}

我从几个月前就了解了typescript，下面的解决方案对我来说很有效。希望它也能帮助到一些人

export enum ScheduleType {
  Basic = <any>'B',
  Consolidated = <any>'C',
}

scheduleTypes = Object.keys(ScheduleType)
.filter((k, i) => i % 2)
.map((key: any) => {
  return {
    systemValue: key,
    displayValue: ScheduleType[key],
  };
});

它给出了如下的结果- [{displayValue: "Basic"， systemValue: "B"}， {displayValue: "Consolidated"， systemValue: "C"}]

另一种方法是使用ES8 Object.entries

export enum Weeks {  
    MONDAY = 1,  
    TUESDAY= 2,  
    WEDNESDAY = 3,  
    THURSDAY = 4,  
    FRIDAY = 5,  
    SATURDAY=6,  
    SUNDAY=7,  
}


function convertEnumToArray(){
   const arrayObjects = []            
     // Retrieve key and values using Object.entries() method. 
     for (const [propertyKey, propertyValue] of Object.entries(Weeks)) { 

      // Ignore keys that are not numbers
      if (!Number.isNaN(Number(propertyKey))) {  
        continue;  
      }  

      // Add keys and values to array
      arrayObjects.push({ id: propertyValue, name: propertyKey });  
    }        

  console.log(arrayObjects); 
}

将产生以下内容:

[ 
  { id: 1, name: 'MONDAY' },  
  { id: 2, name: 'TUESDAY' },  
  { id: 3, name: 'WEDNESDAY' },  
  { id: 4, name: 'THURSDAY' },  
  { id: 5, name: 'FRIDAY' },  
  { id: 6, name: 'SATURDAY' },  
  { id: 7, name: 'SUNDAY' } 
] 

无耻地从这个博客偷来的