我有一个这样定义的枚举:
export enum GoalProgressMeasurements {
Percentage = 1,
Numeric_Target = 2,
Completed_Tasks = 3,
Average_Milestone_Progress = 4,
Not_Measured = 5
}
然而，我希望它被表示为一个对象数组/列表从我们的API如下:
[{id: 1, name: 'Percentage'},
{id: 2, name: 'Numeric Target'},
{id: 3, name: 'Completed Tasks'},
{id: 4, name: 'Average Milestone Progress'},
{id: 5, name: 'Not Measured'}]
是否有简单和本地的方法来做到这一点，或者我必须构建一个函数，将枚举转换为int和字符串，并将对象构建为数组?
当前回答
class EnumHelpers {
static getNamesAndValues<T extends number>(e: any) {
return EnumHelpers.getNames(e).map(n => ({ name: n, value: e[n] as T }));
}
static getNames(e: any) {
return EnumHelpers.getObjValues(e).filter(v => typeof v === 'string') as string[];
}
static getValues<T extends number>(e: any) {
return EnumHelpers.getObjValues(e).filter(v => typeof v === 'number') as T[];
}
static getSelectList<T extends number, U>(e: any, stringConverter: (arg: U) => string) {
const selectList = new Map<T, string>();
this.getValues(e).forEach(val => selectList.set(val as T, stringConverter(val as unknown as U)));
return selectList;
}
static getSelectListAsArray<T extends number, U>(e: any, stringConverter: (arg: U) => string) {
return Array.from(this.getSelectList(e, stringConverter), value => ({ value: value[0] as T, presentation: value[1] }));
}
private static getObjValues(e: any): (number | string)[] {
return Object.keys(e).map(k => e[k]);
}
}
其他回答
我不建议在需要枚举条目列表的情况下使用TS enum。
在运行时，Enum是作为对象实现的，但它只在这种情况下工作:
enum X {
Z = 'z',
F = 'f'
};
console.log(Object.values(X))
console.log(Object.keys(X))
>>>
[LOG]: ["z", "f"]
[LOG]: ["Z", "F"]
在这种情况下，它与陷阱一起工作(TS让你通过它的数值访问值):
enum X {
Z,
F
};
console.log(Object.values(X))
console.log(Object.keys(X))
>>>
[LOG]: ["Z", "F", 0, 1]
[LOG]: ["0", "1", "Z", "F"]
因此，根据Enum定义，任何你写在Enum上循环的函数都将工作/失败。这是…不好的。
我的结论是:Enum不是被设计用来作为对象的。如果你需要访问键和值集合，请使用const而不是enum:
const Enumed = {
X: 1,
Y: 2
}
Typescript将控制对象键的存在，你将能够使用object。钥匙等，以安全一致的方式。
一个棘手的地方是TypeScript会在触发对象中'double'映射enum，所以它可以通过键和值访问。
enum MyEnum {
Part1 = 0,
Part2 = 1
}
将以
{
Part1: 0,
Part2: 1,
0: 'Part1',
1: 'Part2'
}
所以你应该在映射之前先过滤对象。所以@Diullei的解决方案是正确的。这是我的实现:
// Helper
const StringIsNumber = value => isNaN(Number(value)) === false;
// Turn enum into array
function ToArray(enumme) {
return Object.keys(enumme)
.filter(StringIsNumber)
.map(key => enumme[key]);
}
像这样使用它:
export enum GoalProgressMeasurements {
Percentage,
Numeric_Target,
Completed_Tasks,
Average_Milestone_Progress,
Not_Measured
}
console.log(ToArray(GoalProgressMeasurements));
class EnumHelpers {
static getNamesAndValues<T extends number>(e: any) {
return EnumHelpers.getNames(e).map(n => ({ name: n, value: e[n] as T }));
}
static getNames(e: any) {
return EnumHelpers.getObjValues(e).filter(v => typeof v === 'string') as string[];
}
static getValues<T extends number>(e: any) {
return EnumHelpers.getObjValues(e).filter(v => typeof v === 'number') as T[];
}
static getSelectList<T extends number, U>(e: any, stringConverter: (arg: U) => string) {
const selectList = new Map<T, string>();
this.getValues(e).forEach(val => selectList.set(val as T, stringConverter(val as unknown as U)));
return selectList;
}
static getSelectListAsArray<T extends number, U>(e: any, stringConverter: (arg: U) => string) {
return Array.from(this.getSelectList(e, stringConverter), value => ({ value: value[0] as T, presentation: value[1] }));
}
private static getObjValues(e: any): (number | string)[] {
return Object.keys(e).map(k => e[k]);
}
}
设enum变量为:
enum EnumName {
A = 1,
B = 2
};
那么列表是:
const list = Object.keys(Enum)
.filter((value => isNaN(Number(value)) === false))
.map(key => ({ id: key, value: Enum[key] }));
list的值为
list = [
{ id:1 , value: A },
{ id:2 , value: B },
];
function enumKeys(_enum) {
const entries = Object.entries(_enum).filter(e => !isNaN(Number(e[0])));
if (!entries.length) {
// enum has string values so we can use Object.keys
return Object.keys(_enum);
}
return entries.map(e => e[1]);
}
