多亏了波尔科夫尼科夫。我终于能够找到一个解决方案，将工作的大多数用例。

问题的有效解

type Descripted<T> = {
    [K in keyof T]: {
        readonly id: T[K];
        readonly description: string;
    }
}[keyof T]

/**
 * Helper to produce an array of enum descriptors.
 * @param enumeration Enumeration object.
 * @param separatorRegex Regex that would catch the separator in your enum key.
 */
export function enumToDescriptedArray<T>(enumeration: T, separatorRegex: RegExp = /_/g): Descripted<T>[] {
    return (Object.keys(enumeration) as Array<keyof T>)
        .filter(key => isNaN(Number(key)))
        .filter(key => typeof enumeration[key] === "number" || typeof enumeration[key] === "string")
        .map(key => ({
            id: enumeration[key],
            description: String(key).replace(separatorRegex, ' '),
        }));
}

例子:

export enum GoalProgressMeasurements {
    Percentage = 1,
    Numeric_Target = 2,
    Completed_Tasks = 3,
    Average_Milestone_Progress = 4,
    Not_Measured = 5
}

console.log(enumToDescriptedArray(GoalProgressMeasurements))
// Produces:
/*
[
    {id: 1, description: "Percentage"},
    {id: 2, description: "Numeric Target"},
    {id: 3, description: "Completed Tasks"},
    {id: 4, description: "Average Milestone Progress"},
    {id: 5, description: "Not Measured"}
]
*/

此外，我还使用了一个有用的util函数来将枚举对象映射到它拥有的可用值数组:

该映射器

type NonFunctional<T> = T extends Function ? never : T;

/**
 * Helper to produce an array of enum values.
 * @param enumeration Enumeration object.
 */
export function enumToArray<T>(enumeration: T): NonFunctional<T[keyof T]>[] {
    return Object.keys(enumeration)
        .filter(key => isNaN(Number(key)))
        .map(key => enumeration[key])
        .filter(val => typeof val === "number" || typeof val === "string");
}

用例工作

数字枚举

enum Colors1 {
    WHITE = 0,
    BLACK = 1
}
console.log(Object.values(Colors1)); // ['WHITE', 'BLACK', 0, 1]
console.log(enumToArray(Colors1));   // [0, 1]

字符串枚举

enum Colors2 {
    WHITE = "white",
    BLACK = "black"
}
console.log(Object.values(Colors2)); // ['white', 'black']
console.log(enumToArray(Colors2));   // ['white', 'black']

异构枚举

enum Colors4 {
    WHITE = "white",
    BLACK = 0
}
console.log(Object.values(Colors4)); // ["BLACK", "white", 0]
console.log(enumToArray(Colors4));   // ["white", 0]

与具有导出函数的命名空间合并的Enum

enum Colors3 {
    WHITE = "white",
    BLACK = "black"
}
namespace Colors3 {
    export function fun() {}
}
console.log(Object.values(Colors3)); // ['white', 'black', Function]
console.log(enumToArray(Colors3));   // ['white', 'black']

class EnumHelpers {

    static getNamesAndValues<T extends number>(e: any) {
        return EnumHelpers.getNames(e).map(n => ({ name: n, value: e[n] as T }));
    }

    static getNames(e: any) {
        return EnumHelpers.getObjValues(e).filter(v => typeof v === 'string') as string[];
    }

    static getValues<T extends number>(e: any) {
        return EnumHelpers.getObjValues(e).filter(v => typeof v === 'number') as T[];
    }

    static getSelectList<T extends number, U>(e: any, stringConverter: (arg: U) => string) {
        const selectList = new Map<T, string>();
        this.getValues(e).forEach(val => selectList.set(val as T, stringConverter(val as unknown as U)));
        return selectList;
    }

    static getSelectListAsArray<T extends number, U>(e: any, stringConverter: (arg: U) => string) {
        return Array.from(this.getSelectList(e, stringConverter), value => ({ value: value[0] as T, presentation: value[1] }));
    }

    private static getObjValues(e: any): (number | string)[] {
        return Object.keys(e).map(k => e[k]);
    }
}

我很惊讶，在一个TypeScript线程中，没有人给出支持类型的有效TypeScript函数。下面是@user8363解决方案的变化:

const isStringNumber = (value: string) => isNaN(Number(value)) === false;

function enumToArray<T extends {}>(givenEnum: T) {
  return (Object.keys(givenEnum).filter(isStringNumber) as (keyof T)[]).map(
    (key) => givenEnum[key]
  );
}

function enumKeys(_enum) {
  const entries = Object.entries(_enum).filter(e => !isNaN(Number(e[0])));
  if (!entries.length) {
    // enum has string values so we can use Object.keys
    return Object.keys(_enum);
  }
  return entries.map(e => e[1]);
}

我不认为顺序是可以保证的，否则就很容易切片Object的后半部分。条目的结果和映射来自那里。

上述答案的唯一(非常小的)问题是

字符串和数字之间有很多不必要的类型转换。 当一次迭代同样干净有效时，条目将迭代两次。

type StandardEnum = { [id: string]: number | string; [nu: number]: string;}

function enumToList<T extends StandardEnum> (enm: T) : { id: number; description: string }[] {
    return Object.entries(enm).reduce((accum, kv) => {
        if (typeof kv[1] === 'number') {
            accum.push({ id: kv[1], description: kv[0] })
        }
        return accum
    }, []) // if enum is huge, perhaps pre-allocate with new Array(entries.length / 2), however then push won't work, so tracking an index would also be required
}

另一种方法是使用ES8 Object.entries

export enum Weeks {  
    MONDAY = 1,  
    TUESDAY= 2,  
    WEDNESDAY = 3,  
    THURSDAY = 4,  
    FRIDAY = 5,  
    SATURDAY=6,  
    SUNDAY=7,  
}


function convertEnumToArray(){
   const arrayObjects = []            
     // Retrieve key and values using Object.entries() method. 
     for (const [propertyKey, propertyValue] of Object.entries(Weeks)) { 

      // Ignore keys that are not numbers
      if (!Number.isNaN(Number(propertyKey))) {  
        continue;  
      }  

      // Add keys and values to array
      arrayObjects.push({ id: propertyValue, name: propertyKey });  
    }        

  console.log(arrayObjects); 
}

将产生以下内容:

[ 
  { id: 1, name: 'MONDAY' },  
  { id: 2, name: 'TUESDAY' },  
  { id: 3, name: 'WEDNESDAY' },  
  { id: 4, name: 'THURSDAY' },  
  { id: 5, name: 'FRIDAY' },  
  { id: 6, name: 'SATURDAY' },  
  { id: 7, name: 'SUNDAY' } 
] 

无耻地从这个博客偷来的