另一种方法是

export const GoalNames = {
    [GoalProgressMeasurements.Percentage] = 'Percentage',
    [GoalProgressMeasurements.Numeric_Target] = 'Numeric Target',
    [GoalProgressMeasurements.Completed_Tasks] = 'Completed Tasks',
    [GoalProgressMeasurements.Average_Milestone_Progress] = 'Average Milestone Progress',
    [GoalProgressMeasurements.Not_Measured] = 'Not Measured'
}

你可以调用:

const name = GoalNames[goalEnumVal];

该方法基于语句: enum的键不能是数字

export const isNumeric = (num?: Value | null): num is number => {
  if (num === undefined || num === null) {
    return false;
  } 
  
  const number = +num;

  if (number - number !== 0) {
    // Discard Infinity and NaN
    return false;
  }

  if (number === num) {
    return true;
  }

  if (typeof num === 'string') {
    return !(number === 0 && num.trim() === '');
  }
  return false;
};

enum En  {
  ewq1 = 1,
  we2 = 'ss',
  sad = 'sad',
}

type TEnum = {
    [id: string]: number | string;
}

export const getEnumValues = <T extends TEnum>(enumerable: T) =>
  Object.keys(enumerable)
    .filter((x) => !isNumeric(x))
    .map((key) => enumerable[key] as T[keyof T]) 

console.log(getEnumValues(En)) // [1, "ss", "sad"] 

class EnumHelpers {

    static getNamesAndValues<T extends number>(e: any) {
        return EnumHelpers.getNames(e).map(n => ({ name: n, value: e[n] as T }));
    }

    static getNames(e: any) {
        return EnumHelpers.getObjValues(e).filter(v => typeof v === 'string') as string[];
    }

    static getValues<T extends number>(e: any) {
        return EnumHelpers.getObjValues(e).filter(v => typeof v === 'number') as T[];
    }

    static getSelectList<T extends number, U>(e: any, stringConverter: (arg: U) => string) {
        const selectList = new Map<T, string>();
        this.getValues(e).forEach(val => selectList.set(val as T, stringConverter(val as unknown as U)));
        return selectList;
    }

    static getSelectListAsArray<T extends number, U>(e: any, stringConverter: (arg: U) => string) {
        return Array.from(this.getSelectList(e, stringConverter), value => ({ value: value[0] as T, presentation: value[1] }));
    }

    private static getObjValues(e: any): (number | string)[] {
        return Object.keys(e).map(k => e[k]);
    }
}

有一个简单的解决方案，当你运行object。Keys (Enum)它会给你一个值和键的数组，在第一个slice Values中，在第二个slice key中，为什么我们不直接返回第二个slice，下面的代码对我来说是有用的。

enum Enum {
   ONE,
   TWO,
   THREE,
   FOUR,
   FIVE,
   SIX,
   SEVEN
}
const keys = Object.keys(Enum); 
console.log(keys.slice(keys.length / 2));

我不喜欢上面的答案，因为它们都不能正确地处理字符串/数字的混合，可以在TypeScript enum中作为值。

下面的函数遵循TypeScript枚举的语义，给出键到值的正确映射。从那里，获取一个对象数组或者仅仅是键或者仅仅是值是很简单的。

/**
 * Converts the given enum to a map of the keys to the values.
 * @param enumeration The enum to convert to a map.
 */
function enumToMap(enumeration: any): Map<string, string | number> {
  const map = new Map<string, string | number>();
  for (let key in enumeration) {
      //TypeScript does not allow enum keys to be numeric
      if (!isNaN(Number(key))) continue;

      const val = enumeration[key] as string | number;

      //TypeScript does not allow enum value to be null or undefined
      if (val !== undefined && val !== null)
          map.set(key, val);
  }

  return map;
}

使用示例:

enum Dog {
    Rover = 1,
    Lassie = "Collie",
    Fido = 3,
    Cody = "Mutt",
}

let map = enumToMap(Dog); //Map of keys to values

let objs = Array.from(map.entries()).map(m => ({id: m[1], name: m[0]})); //Objects as asked for in OP
let entries = Array.from(map.entries()); //Array of each entry
let keys = Array.from(map.keys()); //An array of keys
let values = Array.from(map.values()); //An array of values

我还要指出OP是逆向思考枚举的。枚举中的“键”在技术上是在左边，而值在右边。TypeScript允许你尽可能多地重复RHS上的值。

首先，我们得到这个枚举的键数组。然后，使用map()函数将数据转换为所需的格式。Id从键获取，name从enum通过相同的键获取。

const converted = Object.keys(GoalProgressMeasurements).map(key => {
        return {
            id: GoalProgressMeasurements[key],
            name: key,
        };
    });