你可以这样做:

export enum GoalProgressMeasurements {
    Percentage = 1,
    Numeric_Target = 2,
    Completed_Tasks = 3,
    Average_Milestone_Progress = 4,
    Not_Measured = 5
}

export class GoalProgressMeasurement {
    constructor(public goalProgressMeasurement: GoalProgressMeasurements, public name: string) {
    }
}

export var goalProgressMeasurements: { [key: number]: GoalProgressMeasurement } = {
    1: new GoalProgressMeasurement(GoalProgressMeasurements.Percentage, "Percentage"),
    2: new GoalProgressMeasurement(GoalProgressMeasurements.Numeric_Target, "Numeric Target"),
    3: new GoalProgressMeasurement(GoalProgressMeasurements.Completed_Tasks, "Completed Tasks"),
    4: new GoalProgressMeasurement(GoalProgressMeasurements.Average_Milestone_Progress, "Average Milestone Progress"),
    5: new GoalProgressMeasurement(GoalProgressMeasurements.Not_Measured, "Not Measured"),
}

你可以这样使用它:

var gpm: GoalProgressMeasurement = goalProgressMeasurements[GoalProgressMeasurements.Percentage];
var gpmName: string = gpm.name;

var myProgressId: number = 1; // the value can come out of drop down selected value or from back-end , so you can imagine the way of using
var gpm2: GoalProgressMeasurement = goalProgressMeasurements[myProgressId];
var gpmName: string = gpm.name;

您可以根据需要使用对象的附加属性扩展GoalProgressMeasurement。我将这种方法用于每个应该是包含多个值的对象的枚举。

简单的解决方案。您可以使用以下函数将Enum转换为对象数组。

 buildGoalProgressMeasurementsArray(): Object[] {

    return Object.keys(GoalProgressMeasurements)
              .map(key => ({ id: GoalProgressMeasurements[key], name: key }))
 }

如果你需要去掉下划线，我们可以像下面这样使用regex:

buildGoalProgressMeasurementsArray(): Object[] {

    return Object.keys(GoalProgressMeasurements)
              .map(key => ({ id: GoalProgressMeasurements[key], name: key.replace(/_/g, ' ') }))
 }

我已经解出来了。 假设您有一个如下所示的枚举

export enum UnitEnum {
  GRAM = 'gm',
  KILOGRAM = 'kg',
  LITRE = 'lt',
  CENTIMETER = 'cm',
  INCH = 'in',
  METER = 'mt',
  KILOMETER = 'km',
}

你有这样一门课，

export interface Unit {
  Name: string;
  Symbol: string;
}

然后，您可以创建一个如下所示的函数，将异构枚举映射到某个类型的对象，

export function getDefaultUnits() {
  const myUnits = Object.entries(UnitEnum).map(x => {
    return { Name: x[0], Symbol: x[1] } as Unit
  })

  console.log(myUnits);

  return myUnits;
}

我不认为顺序是可以保证的，否则就很容易切片Object的后半部分。条目的结果和映射来自那里。

上述答案的唯一(非常小的)问题是

字符串和数字之间有很多不必要的类型转换。 当一次迭代同样干净有效时，条目将迭代两次。

type StandardEnum = { [id: string]: number | string; [nu: number]: string;}

function enumToList<T extends StandardEnum> (enm: T) : { id: number; description: string }[] {
    return Object.entries(enm).reduce((accum, kv) => {
        if (typeof kv[1] === 'number') {
            accum.push({ id: kv[1], description: kv[0] })
        }
        return accum
    }, []) // if enum is huge, perhaps pre-allocate with new Array(entries.length / 2), however then push won't work, so tracking an index would also be required
}

 this worked for me :

    export enum FeedBackType {
    FEEDBACK1= 'FEEDBACK1',
    FEEDBACK2= 'FEEDBACK2',
    FEEDBACK3= 'FEEDBACK3',
    }

----------------------------------------------------------------- 
    export function getTypeFeedBackList() {
    let feedbackList: FeedBackType[] = [];
    Object.keys(FeedBackType).map((key) => {
    let strEnum = key as unknown as FeedBackType;
    feedbackList.push(strEnum);
    });
    return feedbackList;
    }
---------------------------------------------------------------- 
declare this :

    public feedbackList: FeedBackType[] = [];

and after call your function in  :

    ngOnInit(): void {
    this.feedbackList = getTypeFeedBackList();
    console.log(this.feedbackList); 
    }

Happy coding ;) 

我是这样解的

        const listKeys = Object.keys(TripStatus); //TripStatus is enum type
        const numOfItem = listKeys.length/2;
        for(let i=0; i<numOfItem; i++){
          this.listStatus.push({
            id: listKeys[i],
            name: listKeys[numOfItem+i]
          })
        }