我有一个这样定义的枚举:

export enum GoalProgressMeasurements {
    Percentage = 1,
    Numeric_Target = 2,
    Completed_Tasks = 3,
    Average_Milestone_Progress = 4,
    Not_Measured = 5
}

然而,我希望它被表示为一个对象数组/列表从我们的API如下:

[{id: 1, name: 'Percentage'}, 
 {id: 2, name: 'Numeric Target'},
 {id: 3, name: 'Completed Tasks'},
 {id: 4, name: 'Average Milestone Progress'},
 {id: 5, name: 'Not Measured'}]

是否有简单和本地的方法来做到这一点,或者我必须构建一个函数,将枚举转换为int和字符串,并将对象构建为数组?


当前回答

我是这样解的

        const listKeys = Object.keys(TripStatus); //TripStatus is enum type
        const numOfItem = listKeys.length/2;
        for(let i=0; i<numOfItem; i++){
          this.listStatus.push({
            id: listKeys[i],
            name: listKeys[numOfItem+i]
          })
        }

其他回答

enum目标进度测量{ 百分比= 1, Numeric_Target = 2, Completed_Tasks = 3, average_milestone one_progress = 4, Not_Measured = 5 } Const数组= [] for (const [key, value] of Object.entries(GoalProgressMeasurements)) { if (!Number. isnan (Number(key)) { 继续; } 数组中。Push ({id:值,名称:键。Replace ('_', ")}); } console.log(数组);

 this worked for me :

    export enum FeedBackType {
    FEEDBACK1= 'FEEDBACK1',
    FEEDBACK2= 'FEEDBACK2',
    FEEDBACK3= 'FEEDBACK3',
    }

----------------------------------------------------------------- 
    export function getTypeFeedBackList() {
    let feedbackList: FeedBackType[] = [];
    Object.keys(FeedBackType).map((key) => {
    let strEnum = key as unknown as FeedBackType;
    feedbackList.push(strEnum);
    });
    return feedbackList;
    }
---------------------------------------------------------------- 
declare this :

    public feedbackList: FeedBackType[] = [];

and after call your function in  :

    ngOnInit(): void {
    this.feedbackList = getTypeFeedBackList();
    console.log(this.feedbackList); 
    }

Happy coding ;) 
function enumKeys(_enum) {
  const entries = Object.entries(_enum).filter(e => !isNaN(Number(e[0])));
  if (!entries.length) {
    // enum has string values so we can use Object.keys
    return Object.keys(_enum);
  }
  return entries.map(e => e[1]);
}

我从几个月前就了解了typescript,下面的解决方案对我来说很有效。希望它也能帮助到一些人

export enum ScheduleType {
  Basic = <any>'B',
  Consolidated = <any>'C',
}

scheduleTypes = Object.keys(ScheduleType)
.filter((k, i) => i % 2)
.map((key: any) => {
  return {
    systemValue: key,
    displayValue: ScheduleType[key],
  };
});

它给出了如下的结果- [{displayValue: "Basic", systemValue: "B"}, {displayValue: "Consolidated", systemValue: "C"}]

class EnumHelpers {

    static getNamesAndValues<T extends number>(e: any) {
        return EnumHelpers.getNames(e).map(n => ({ name: n, value: e[n] as T }));
    }

    static getNames(e: any) {
        return EnumHelpers.getObjValues(e).filter(v => typeof v === 'string') as string[];
    }

    static getValues<T extends number>(e: any) {
        return EnumHelpers.getObjValues(e).filter(v => typeof v === 'number') as T[];
    }

    static getSelectList<T extends number, U>(e: any, stringConverter: (arg: U) => string) {
        const selectList = new Map<T, string>();
        this.getValues(e).forEach(val => selectList.set(val as T, stringConverter(val as unknown as U)));
        return selectList;
    }

    static getSelectListAsArray<T extends number, U>(e: any, stringConverter: (arg: U) => string) {
        return Array.from(this.getSelectList(e, stringConverter), value => ({ value: value[0] as T, presentation: value[1] }));
    }

    private static getObjValues(e: any): (number | string)[] {
        return Object.keys(e).map(k => e[k]);
    }
}