我有一长串这样的表格——
a = [[1.2,'abc',3],[1.2,'werew',4],........,[1.4,'qew',2]]
也就是说，列表中的值是不同类型的——float,int, strings。我如何将它写入csv文件，使我的输出csv文件看起来像这样
1.2,abc,3
1.2,werew,4
.
.
.
1.4,qew,2
当前回答
使用csv。在我庞大的列表中，作者花了相当长的时间。我决定使用熊猫，它更快，更容易控制和理解:
import pandas
yourlist = [[...],...,[...]]
pd = pandas.DataFrame(yourlist)
pd.to_csv("mylist.csv")
好的部分是你可以改变一些东西来创建一个更好的csv文件:
yourlist = [[...],...,[...]]
columns = ["abcd","bcde","cdef"] #a csv with 3 columns
index = [i[0] for i in yourlist] #first element of every list in yourlist
not_index_list = [i[1:] for i in yourlist]
pd = pandas.DataFrame(not_index_list, columns = columns, index = index)
#Now you have a csv with columns and index:
pd.to_csv("mylist.csv")
其他回答
使用csv。在我庞大的列表中，作者花了相当长的时间。我决定使用熊猫，它更快，更容易控制和理解:
import pandas
yourlist = [[...],...,[...]]
pd = pandas.DataFrame(yourlist)
pd.to_csv("mylist.csv")
好的部分是你可以改变一些东西来创建一个更好的csv文件:
yourlist = [[...],...,[...]]
columns = ["abcd","bcde","cdef"] #a csv with 3 columns
index = [i[0] for i in yourlist] #first element of every list in yourlist
not_index_list = [i[1:] for i in yourlist]
pd = pandas.DataFrame(not_index_list, columns = columns, index = index)
#Now you have a csv with columns and index:
pd.to_csv("mylist.csv")
import csv
with open(file_path, 'a') as outcsv:
#configure writer to write standard csv file
writer = csv.writer(outcsv, delimiter=',', quotechar='|', quoting=csv.QUOTE_MINIMAL, lineterminator='\n')
writer.writerow(['number', 'text', 'number'])
for item in list:
#Write item to outcsv
writer.writerow([item[0], item[1], item[2]])
官方文档:http://docs.python.org/2/library/csv.html
Python内置的CSV模块可以轻松处理:
import csv
with open("output.csv", "wb") as f:
writer = csv.writer(f)
writer.writerows(a)
这假设你的列表被定义为a，就像你的问题一样。您可以通过CSV .writer()的各种可选参数调整输出CSV的确切格式，如上面链接的库参考页中所记录的那样。
Python 3更新
import csv
with open("out.csv", "w", newline="") as f:
writer = csv.writer(f)
writer.writerows(a)
你可以用熊猫:
In [1]: import pandas as pd
In [2]: a = [[1.2,'abc',3],[1.2,'werew',4],[1.4,'qew',2]]
In [3]: my_df = pd.DataFrame(a)
In [4]: my_df.to_csv('my_csv.csv', index=False, header=False)
确保在创建写入器时指明lineterinator='\n';否则，当数据源来自其他CSV文件时，可能会在每个数据行后写入额外的空行…
以下是我的解决方案:
with open('csvfile', 'a') as csvfile:
spamwriter = csv.writer(csvfile, delimiter=' ',quotechar='|', quoting=csv.QUOTE_MINIMAL, lineterminator='\n')
for i in range(0, len(data)):
spamwriter.writerow(data[i])
