我能找到的最简单的方法是：

Path sampleOutputPath = Paths.get("/tmp/testfile")
try (BufferedWriter writer = Files.newBufferedWriter(sampleOutputPath)) {
    writer.write("Hello, world!");
}

它可能只适用于1.7+。

使用Google的Guava库，我们可以创建和写入文件容易地

package com.zetcode.writetofileex;

import com.google.common.io.Files;
import java.io.File;
import java.io.IOException;

public class WriteToFileEx {

    public static void main(String[] args) throws IOException {

        String fileName = "fruits.txt";
        File file = new File(fileName);

        String content = "banana, orange, lemon, apple, plum";

        Files.write(content.getBytes(), file);
    }
}

该示例在项目根目录中创建一个新的fruits.txt文件。

Java 7+值得一试：

 Files.write(Paths.get("./output.txt"), "Information string herer".getBytes());

看起来很有希望。。。

    public static void writefromFile(ArrayList<String> lines, String destPath) {
        FileWriter fw;
        try {
            fw = new FileWriter(destPath);
            for (String str : lines) {
                fw.write(str);
            }
            fw.close();
         } catch (IOException ex) {
            JOptionPane.showMessageDialog("ERROR: exception was: " + ex.toString());
        }
        File f = new File(destPath);
        f.setExecutable(true);
    }

只有一行！路径和行是字符串

import java.nio.file.Files;
import java.nio.file.Paths;

Files.write(Paths.get(path), lines.getBytes());

我认为这是最短的路：

FileWriter fr = new FileWriter("your_file_name.txt"); // After '.' write
// your file extention (".txt" in this case)
fr.write("Things you want to write into the file"); // Warning: this will REPLACE your old file content!
fr.close();