将Throwable.getStackTrace()的结果转换为描述堆栈跟踪的字符串最简单的方法是什么?


当前回答

Scala版本

def stackTraceToString(e: Exception): String = {
  import java.io.PrintWriter
  val sw = new StringWriter()
  e.printStackTrace(new PrintWriter(sw))
  sw.toString
}

其他回答

这应该是有效的:

StringWriter sw = new StringWriter();
e.printStackTrace(new PrintWriter(sw));
String exceptionAsString = sw.toString();

将堆栈跟踪打印到PrintStream,然后将其转换为字符串:

// ...

catch (Exception e)
{
    ByteArrayOutputStream out = new ByteArrayOutputStream(); 
    e.printStackTrace(new PrintStream(out));
    String str = new String(out.toByteArray());

    System.out.println(str);
}
private String getCurrentStackTraceString() {
    StackTraceElement[] stackTrace = Thread.currentThread().getStackTrace();
    return Arrays.stream(stackTrace).map(StackTraceElement::toString)
            .collect(Collectors.joining("\n"));
}

我想知道为什么没有人提到ExceptionUtils.getStackFrames(exception)

对我来说,这是将堆栈跟踪及其所有原因转储到底的最方便方法:

String.join("\n", ExceptionUtils.getStackFrames(exception));

警告:不包括原因(通常是有用的位!)

public String stackTraceToString(Throwable e) {
    StringBuilder sb = new StringBuilder();
    for (StackTraceElement element : e.getStackTrace()) {
        sb.append(element.toString());
        sb.append("\n");
    }
    return sb.toString();
}