将Throwable.getStackTrace()的结果转换为描述堆栈跟踪的字符串最简单的方法是什么?


当前回答

使用Throwable.printStackTrace(PrintWriter pw)将堆栈跟踪发送到适当的编写器。

import java.io.StringWriter;
import java.io.PrintWriter;

// ...

StringWriter sw = new StringWriter();
PrintWriter pw = new PrintWriter(sw);
e.printStackTrace(pw);
String sStackTrace = sw.toString(); // stack trace as a string
System.out.println(sStackTrace);

其他回答

 import java.io.PrintWriter;
import java.io.StringWriter;

public class PrintStackTrace {

    public static void main(String[] args) {

        try {
            int division = 0 / 0;
        } catch (ArithmeticException e) {
            StringWriter sw = new StringWriter();
            e.printStackTrace(new PrintWriter(sw));
            String exceptionAsString = sw.toString();
            System.out.println(exceptionAsString);
        }
    }
}

运行程序时,输出将类似:

java.lang.ArithmeticException: / by zero
at PrintStackTrace.main(PrintStackTrace.java:9)

警告:不包括原因(通常是有用的位!)

public String stackTraceToString(Throwable e) {
    StringBuilder sb = new StringBuilder();
    for (StackTraceElement element : e.getStackTrace()) {
        sb.append(element.toString());
        sb.append("\n");
    }
    return sb.toString();
}

对我来说,最干净、最简单的方法是:

import java.util.Arrays;
Arrays.toString(e.getStackTrace());

警告:这可能有点离题,但哦,好吧…;)

我不知道最初的海报是什么原因让堆栈跟踪成为字符串。当堆栈跟踪应该以SLF4J/Logback LOG结尾,但没有或应该抛出异常时,我会这样做:

public void remove(List<String> ids) {
    if(ids == null || ids.isEmpty()) {
        LOG.warn(
            "An empty list (or null) was passed to {}.remove(List). " +
            "Clearly, this call is unneccessary, the caller should " + 
            "avoid making it. A stacktrace follows.", 
            getClass().getName(),
            new Throwable ("Stacktrace")
        );

        return;
    }

    // actual work, remove stuff
}

我喜欢它,因为它不需要外部库(当然,除了您的日志后端,它大部分时间都会在那里)。

选项很少

StringWriter sw=新StringWriter();e.printStackTrace(新的PrintWriter(sw));字符串异常AsString=sw.toString();使用Google Guava libString stackTrace=Throwables.getStackTraceAsString(myException);org.apache.commons.lang.exception.ExceptionUtils.getStackTrace(可丢弃)