将Throwable.getStackTrace()的结果转换为描述堆栈跟踪的字符串最简单的方法是什么?


当前回答

可以使用以下方法将异常堆栈跟踪转换为字符串。该类在Apache commons-lang中可用,这是许多流行开源中最常见的依赖库

org.apache.commons.lang.exception.ExceptionUtils.getStackTrace(可丢弃)

其他回答

 import java.io.PrintWriter;
import java.io.StringWriter;

public class PrintStackTrace {

    public static void main(String[] args) {

        try {
            int division = 0 / 0;
        } catch (ArithmeticException e) {
            StringWriter sw = new StringWriter();
            e.printStackTrace(new PrintWriter(sw));
            String exceptionAsString = sw.toString();
            System.out.println(exceptionAsString);
        }
    }
}

运行程序时,输出将类似:

java.lang.ArithmeticException: / by zero
at PrintStackTrace.main(PrintStackTrace.java:9)

使用Throwable.printStackTrace(PrintWriter pw)将堆栈跟踪发送到适当的编写器。

import java.io.StringWriter;
import java.io.PrintWriter;

// ...

StringWriter sw = new StringWriter();
PrintWriter pw = new PrintWriter(sw);
e.printStackTrace(pw);
String sStackTrace = sw.toString(); // stack trace as a string
System.out.println(sStackTrace);

解决方案是将数组的stackTrace转换为字符串数据类型。请参见以下示例:

import java.util.Arrays;

try{

}catch(Exception ex){
    String stack = Arrays.toString(ex.getStackTrace());
    System.out.println("stack "+ stack);
}

我想知道为什么没有人提到ExceptionUtils.getStackFrames(exception)

对我来说,这是将堆栈跟踪及其所有原因转储到底的最方便方法:

String.join("\n", ExceptionUtils.getStackFrames(exception));
public static String getStackTrace(Throwable t) {
    StringWriter sw = new StringWriter();
    t.printStackTrace(new PrintWriter(sw));
    return sw.toString();
}