给定以下代码(不起作用):

while True:
    # Snip: print out current state
    while True:
        ok = get_input("Is this ok? (y/n)")
        if ok.lower() == "y": break 2 # This doesn't work :(
        if ok.lower() == "n": break

    # Do more processing with menus and stuff

有办法解决这个问题吗?还是我必须先检查一次,跳出输入循环,然后再检查一次,如果用户满意,再跳出外部循环?


当前回答

keeplooping = True
while keeplooping:
    # Do stuff
    while keeplooping:
          # Do some other stuff
          if finisheddoingstuff():
              keeplooping = False

或者类似的东西。

您可以在内部循环中设置一个变量,并在内部循环退出后立即在外部循环中检查它,如果合适的话可以中断。我有点喜欢GOTO方法,前提是你不介意使用愚人节的笑话模块——它不是python的,但它确实有意义。

其他回答

通过使用函数:

def myloop():
    for i in range(1,6,1):  # 1st loop
        print('i:',i)
        for j in range(1,11,2):  # 2nd loop
            print('   i, j:' ,i, j)
            for k in range(1,21,4):  # 3rd loop
                print('      i,j,k:', i,j,k)
                if i%3==0 and j%3==0 and k%3==0:
                    return  # getting out of all loops

myloop()

尝试通过注释掉返回值来运行上面的代码。

不使用任何函数:

done = False
for i in range(1,6,1):  # 1st loop
    print('i:', i)
    for j in range(1,11,2):  # 2nd loop
        print('   i, j:' ,i, j)
        for k in range(1,21,4):  # 3rd loop
            print('      i,j,k:', i,j,k)
            if i%3==0 and j%3==0 and k%3==0:
                done = True
                break  # breaking from 3rd loop
        if done: break # breaking from 2nd loop
    if done: break     # breaking from 1st loop

现在,首先按原样运行上面的代码,然后尝试从底部注释掉包含break的每一行。

引入一个新变量作为“循环打破器”。首先给它赋值(False,0等),然后,在外层循环中,在终止它之前,将值更改为其他值(True,1,…)。一旦循环退出,让“父”循环检查该值。让我来演示一下:

breaker = False #our mighty loop exiter!
while True:
    while True:
        if conditionMet:
            #insert code here...
            breaker = True 
            break
    if breaker: # the interesting part!
        break   # <--- !

如果你有一个无限循环,这是唯一的出路;对于其他循环,执行速度要快得多。如果你有很多嵌套循环,这也适用。你可以退出全部,也可以只退出一部分。无尽的可能性!希望这对你有所帮助!

Break for外层和内部while循环:

while True:
    while True:
        print('Breaks inner "while" loop')
        break # Here
    print('Breaks outer "while" loop')
    break # Here

或者,用if语句中断外部和内部while循环:

while True:
    while True:
        if True:
            print('Breaks inner "while" loop')
            break # Here
    print('Breaks outer "while" loop')
    break # Here

输出:

Breaks inner "while" loop
Breaks outer "while" loop

Break for outer和inner for循环:

for _ in iter(int, 1):
    for _ in iter(int, 1):
        print('Breaks inner "for" loop')
        break # Here
    print('Breaks outer "for" loop')
    break # Here

或者,用if语句打破外部和内部for循环:

for _ in iter(int, 1):
    for _ in iter(int, 1):
        if True:
            print('Breaks inner "for" loop')
            break # Here
    print('Breaks outer "for" loop')
    break # Here

输出:

Breaks inner "for" loop
Breaks outer "for" loop

我倾向于认为重构到函数中通常是这种情况的最佳方法,但是当您确实需要打破嵌套循环时,这里有一个有趣的异常引发方法的变体@S。洛特。它使用Python的with语句使异常引发看起来更好一些。定义一个新的上下文管理器(你只需要这样做一次):

from contextlib import contextmanager
@contextmanager
def nested_break():
    class NestedBreakException(Exception):
        pass
    try:
        yield NestedBreakException
    except NestedBreakException:
        pass

现在你可以像下面这样使用这个上下文管理器:

with nested_break() as mylabel:
    while True:
        print "current state"
        while True:
            ok = raw_input("Is this ok? (y/n)")
            if ok == "y" or ok == "Y": raise mylabel
            if ok == "n" or ok == "N": break
        print "more processing"

优点:(1)它稍微干净一些(没有显式的try-except块),并且(2)每次使用nested_break你都会得到一个定制的Exception子类;不需要每次都声明自己的Exception子类。

希望这能有所帮助:

x = True
y = True
while x == True:
    while y == True:
         ok = get_input("Is this ok? (y/n)") 
         if ok == "y" or ok == "Y":
             x,y = False,False #breaks from both loops
         if ok == "n" or ok == "N": 
             break #breaks from just one