如何找到本地IP地址(即192.168.x。x或10.0.x.x)在Python平台独立,只使用标准库?
当前回答
供您参考,我可以验证该方法:
import socket
addr = socket.gethostbyname(socket.gethostname())
适用于OS X (10.6,10.5), Windows XP和管理良好的RHEL部门服务器。它不能在一个非常小的CentOS虚拟机上工作,我只是做了一些内核黑客。因此,对于该实例,您可以检查127.0.0.1地址,在这种情况下,执行以下操作:
if addr == "127.0.0.1":
import commands
output = commands.getoutput("/sbin/ifconfig")
addr = parseaddress(output)
然后从输出中解析ip地址。应该注意的是,默认情况下ifconfig不在普通用户的PATH中,这就是为什么我在命令中给出完整的路径。我希望这能有所帮助。
其他回答
这不是很Pythonic,但它在Windows上可靠地工作。
def getWinIP(version = 'IPv4'):
import subprocess
if version not in ['IPv4', 'IPv6']:
print 'error - protocol version must be "IPv4" or "IPv6"'
return None
ipconfig = subprocess.check_output('ipconfig')
my_ip = []
for line in ipconfig.split('\n'):
if 'Address' in line and version in line:
my_ip.append(line.split(' : ')[1].strip())
return my_ip
print getWinIP()
是的,这是一种黑客行为,但有时我不想事后怀疑操作系统,直接使用内置的和有效的操作系统就行了。
我在我的ubuntu机器上使用这个:
import commands
commands.getoutput("/sbin/ifconfig").split("\n")[1].split()[1][5:]
这行不通。
Pyroute2是一个很棒的库,不仅可以用来获取IP地址,还可以用来获取网关信息和其他有用的信息。 下面的代码可以获取任意接口的ipv4地址。
from pyroute2 import IPRoute
ip = IPRoute()
def get_ipv4_address(intf):
return dict(ip.get_addr(label=intf)[0]['attrs'])['IFA_LOCAL']
print(get_ipv4_address('eth0'))
import socket
socket.gethostbyname(socket.gethostname())
这并不总是有效(在/etc/hosts主机名为127.0.0.1的机器上返回127.0.0.1),gimel显示的是一个缓和的方法,使用socket.getfqdn()代替。当然,您的机器需要一个可解析的主机名。
这是UnkwnTech的答案的变体——它提供了一个get_local_addr()函数,该函数返回主机的主LAN ip地址。我发布它是因为这增加了一些东西:ipv6支持,错误处理,忽略localhost/linklocal地址,并使用TESTNET地址(rfc5737)来连接。
# imports
import errno
import socket
import logging
# localhost prefixes
_local_networks = ("127.", "0:0:0:0:0:0:0:1")
# ignore these prefixes -- localhost, unspecified, and link-local
_ignored_networks = _local_networks + ("0.", "0:0:0:0:0:0:0:0", "169.254.", "fe80:")
def detect_family(addr):
if "." in addr:
assert ":" not in addr
return socket.AF_INET
elif ":" in addr:
return socket.AF_INET6
else:
raise ValueError("invalid ipv4/6 address: %r" % addr)
def expand_addr(addr):
"""convert address into canonical expanded form --
no leading zeroes in groups, and for ipv6: lowercase hex, no collapsed groups.
"""
family = detect_family(addr)
addr = socket.inet_ntop(family, socket.inet_pton(family, addr))
if "::" in addr:
count = 8-addr.count(":")
addr = addr.replace("::", (":0" * count) + ":")
if addr.startswith(":"):
addr = "0" + addr
return addr
def _get_local_addr(family, remote):
try:
s = socket.socket(family, socket.SOCK_DGRAM)
try:
s.connect((remote, 9))
return s.getsockname()[0]
finally:
s.close()
except socket.error:
# log.info("trapped error connecting to %r via %r", remote, family, exc_info=True)
return None
def get_local_addr(remote=None, ipv6=True):
"""get LAN address of host
:param remote:
return LAN address that host would use to access that specific remote address.
by default, returns address it would use to access the public internet.
:param ipv6:
by default, attempts to find an ipv6 address first.
if set to False, only checks ipv4.
:returns:
primary LAN address for host, or ``None`` if couldn't be determined.
"""
if remote:
family = detect_family(remote)
local = _get_local_addr(family, remote)
if not local:
return None
if family == socket.AF_INET6:
# expand zero groups so the startswith() test works.
local = expand_addr(local)
if local.startswith(_local_networks):
# border case where remote addr belongs to host
return local
else:
# NOTE: the two addresses used here are TESTNET addresses,
# which should never exist in the real world.
if ipv6:
local = _get_local_addr(socket.AF_INET6, "2001:db8::1234")
# expand zero groups so the startswith() test works.
if local:
local = expand_addr(local)
else:
local = None
if not local:
local = _get_local_addr(socket.AF_INET, "192.0.2.123")
if not local:
return None
if local.startswith(_ignored_networks):
return None
return local
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