如何找到本地IP地址(即192.168.x。x或10.0.x.x)在Python平台独立,只使用标准库?


当前回答

这是UnkwnTech的答案的变体——它提供了一个get_local_addr()函数,该函数返回主机的主LAN ip地址。我发布它是因为这增加了一些东西:ipv6支持,错误处理,忽略localhost/linklocal地址,并使用TESTNET地址(rfc5737)来连接。

# imports
import errno
import socket
import logging

# localhost prefixes
_local_networks = ("127.", "0:0:0:0:0:0:0:1")

# ignore these prefixes -- localhost, unspecified, and link-local
_ignored_networks = _local_networks + ("0.", "0:0:0:0:0:0:0:0", "169.254.", "fe80:")

def detect_family(addr):
    if "." in addr:
        assert ":" not in addr
        return socket.AF_INET
    elif ":" in addr:
        return socket.AF_INET6
    else:
        raise ValueError("invalid ipv4/6 address: %r" % addr)

def expand_addr(addr):
    """convert address into canonical expanded form --
    no leading zeroes in groups, and for ipv6: lowercase hex, no collapsed groups.
    """
    family = detect_family(addr)
    addr = socket.inet_ntop(family, socket.inet_pton(family, addr))
    if "::" in addr:
        count = 8-addr.count(":")
        addr = addr.replace("::", (":0" * count) + ":")
        if addr.startswith(":"):
            addr = "0" + addr
    return addr

def _get_local_addr(family, remote):
    try:
        s = socket.socket(family, socket.SOCK_DGRAM)
        try:
            s.connect((remote, 9))
            return s.getsockname()[0]
        finally:
            s.close()
    except socket.error:
        # log.info("trapped error connecting to %r via %r", remote, family, exc_info=True)
        return None

def get_local_addr(remote=None, ipv6=True):
    """get LAN address of host

    :param remote:
        return  LAN address that host would use to access that specific remote address.
        by default, returns address it would use to access the public internet.

    :param ipv6:
        by default, attempts to find an ipv6 address first.
        if set to False, only checks ipv4.

    :returns:
        primary LAN address for host, or ``None`` if couldn't be determined.
    """
    if remote:
        family = detect_family(remote)
        local = _get_local_addr(family, remote)
        if not local:
            return None
        if family == socket.AF_INET6:
            # expand zero groups so the startswith() test works.
            local = expand_addr(local)
        if local.startswith(_local_networks):
            # border case where remote addr belongs to host
            return local
    else:
        # NOTE: the two addresses used here are TESTNET addresses,
        #       which should never exist in the real world.
        if ipv6:
            local = _get_local_addr(socket.AF_INET6, "2001:db8::1234")
            # expand zero groups so the startswith() test works.
            if local:
                local = expand_addr(local)
        else:
            local = None
        if not local:
            local = _get_local_addr(socket.AF_INET, "192.0.2.123")
            if not local:
                return None
    if local.startswith(_ignored_networks):
        return None
    return local

其他回答

要获取ip地址,可以直接在python中使用shell命令:

import socket, subprocess

def get_ip_and_hostname():
    hostname =  socket.gethostname()

    shell_cmd = "ifconfig | awk '/inet addr/{print substr($2,6)}'"
    proc = subprocess.Popen([shell_cmd], stdout=subprocess.PIPE, shell=True)
    (out, err) = proc.communicate()

    ip_list = out.split('\n')
    ip = ip_list[0]

    for _ip in ip_list:
        try:
            if _ip != "127.0.0.1" and _ip.split(".")[3] != "1":
                ip = _ip
        except:
            pass
    return ip, hostname

ip_addr, hostname = get_ip_and_hostname()

一个我不相信已经发布的版本。 我在Ubuntu 12.04上使用python 2.7进行测试。

找到这个解决方案:http://code.activestate.com/recipes/439094-get-the-ip-address-associated-with-a-network-inter/

import socket
import fcntl
import struct

def get_ip_address(ifname):
    s = socket.socket(socket.AF_INET, socket.SOCK_DGRAM)
    return socket.inet_ntoa(fcntl.ioctl(
        s.fileno(),
        0x8915,  # SIOCGIFADDR
        struct.pack('256s', ifname[:15])
    )[20:24])

结果示例:

>>> get_ip_address('eth0')
'38.113.228.130'

恐怕除了连接到另一台计算机并让它把你的IP地址发送给你之外,没有任何好的独立于平台的方法来做到这一点。例如:findmyipaddress。注意,如果你需要一个NAT后的IP地址,除非你所连接的计算机也是NAT后的IP地址,这是行不通的。

下面是一个适用于Linux的解决方案:获取与网络接口关联的IP地址。

我使用以下模块:

#!/usr/bin/python
# module for getting the lan ip address of the computer

import os
import socket

if os.name != "nt":
    import fcntl
    import struct
    def get_interface_ip(ifname):
        s = socket.socket(socket.AF_INET, socket.SOCK_DGRAM)
        return socket.inet_ntoa(fcntl.ioctl(
                s.fileno(),
                0x8915,  # SIOCGIFADDR
                struct.pack('256s', bytes(ifname[:15], 'utf-8'))
                # Python 2.7: remove the second argument for the bytes call
            )[20:24])

def get_lan_ip():
    ip = socket.gethostbyname(socket.gethostname())
    if ip.startswith("127.") and os.name != "nt":
        interfaces = ["eth0","eth1","eth2","wlan0","wlan1","wifi0","ath0","ath1","ppp0"]
        for ifname in interfaces:
            try:
                ip = get_interface_ip(ifname)
                break;
            except IOError:
                pass
    return ip

测试与windows和linux(和不需要额外的模块为那些) 用于在一个基于IPv4的局域网中的系统。

固定的接口名称列表不适用于最近的linux版本,这些版本已经采用了systemd v197关于可预测接口名称的更改,正如Alexander指出的那样。 在这种情况下,您需要手动使用系统上的接口名称替换该列表,或者使用其他解决方案,如netifaces。

这个答案是我个人试图解决获得LAN IP的问题,因为socket.gethostbyname(socket.gethostname())也返回127.0.0.1。这种方法不需要Internet,只需要一个局域网连接。代码是为Python 3编写的。X但是可以很容易地转换为2.x。使用UDP广播:

import select
import socket
import threading
from queue import Queue, Empty

def get_local_ip():
        def udp_listening_server():
            s = socket.socket(socket.AF_INET, socket.SOCK_DGRAM)
            s.bind(('<broadcast>', 8888))
            s.setblocking(0)
            while True:
                result = select.select([s],[],[])
                msg, address = result[0][0].recvfrom(1024)
                msg = str(msg, 'UTF-8')
                if msg == 'What is my LAN IP address?':
                    break
            queue.put(address)

        queue = Queue()
        thread = threading.Thread(target=udp_listening_server)
        thread.queue = queue
        thread.start()
        s2 = socket.socket(socket.AF_INET, socket.SOCK_DGRAM)
        s2.setsockopt(socket.SOL_SOCKET, socket.SO_BROADCAST, 1)
        waiting = True
        while waiting:
            s2.sendto(bytes('What is my LAN IP address?', 'UTF-8'), ('<broadcast>', 8888))
            try:
                address = queue.get(False)
            except Empty:
                pass
            else:
                waiting = False
        return address[0]

if __name__ == '__main__':
    print(get_local_ip())