如何找到本地IP地址(即192.168.x。x或10.0.x.x)在Python平台独立,只使用标准库?
当前回答
简单而甜蜜!
def getip():
import socket
hostname= socket.gethostname()
ip=socket.gethostbyname(hostname)
return(ip)
其他回答
Socket API方法
参见https://stackoverflow.com/a/28950776/711085
缺点:
Not cross-platform. Requires more fallback code, tied to existence of particular addresses on the internet This will also not work if you're behind a NAT Probably creates a UDP connection, not independent of (usually ISP's) DNS availability (see other answers for ideas like using 8.8.8.8: Google's (coincidentally also DNS) server) Make sure you make the destination address UNREACHABLE, like a numeric IP address that is spec-guaranteed to be unused. Do NOT use some domain like fakesubdomain.google.com or somefakewebsite.com; you'll still be spamming that party (now or in the future), and spamming your own network boxes as well in the process.
反射器方法
(请注意,这并没有回答OP的本地IP地址问题,例如192.168…;它会给你你的公共IP地址,根据用例,这可能更可取。)
你可以查询一些网站,如whatismyip.com(但有一个API),例如:
from urllib.request import urlopen
import re
def getPublicIp():
data = str(urlopen('http://checkip.dyndns.com/').read())
# data = '<html><head><title>Current IP Check</title></head><body>Current IP Address: 65.96.168.198</body></html>\r\n'
return re.compile(r'Address: (\d+\.\d+\.\d+\.\d+)').search(data).group(1)
或者如果使用python2:
from urllib import urlopen
import re
def getPublicIp():
data = str(urlopen('http://checkip.dyndns.com/').read())
# data = '<html><head><title>Current IP Check</title></head><body>Current IP Address: 65.96.168.198</body></html>\r\n'
return re.compile(r'Address: (\d+\.\d+\.\d+\.\d+)').search(data).group(1)
优点:
这种方法的一个优点是它是跨平台的 它从丑陋的nat(例如你的家用路由器)后面工作。
缺点(和变通方法):
要求网站正常运行,格式不变(几乎肯定不会),DNS服务器正常工作。在失败的情况下,还可以通过查询其他第三方IP地址反射器来缓解这个问题。 如果您不查询多个反射器(以防止一个受损害的反射器告诉您您的地址不是某个东西),或者如果您不使用HTTPS(以防止假装是服务器的中间人攻击),则可能的攻击向量
edit: Though initially I thought these methods were really bad (unless you use many fallbacks, the code may be irrelevant many years from now), it does pose the question "what is the internet?". A computer may have many interfaces pointing to many different networks. For a more thorough description of the topic, google for gateways and routes. A computer may be able to access an internal network via an internal gateway, or access the world-wide web via a gateway on for example a router (usually the case). The local IP address that the OP asks about is only well-defined with respect to a single link layer, so you have to specify that ("is it the network card, or the ethernet cable, which we're talking about?"). There may be multiple non-unique answers to this question as posed. However the global IP address on the world-wide web is probably well-defined (in the absence of massive network fragmentation): probably the return path via the gateway which can access the TLDs.
好吧,这是Windows特定的,需要安装python WMI模块,但这似乎比不断尝试调用外部服务器要简单得多。这只是另一种选择,因为已经有很多好的选择,但它可能非常适合您的项目。
Import WMI
def getlocalip():
local = wmi.WMI()
for interface in local.Win32_NetworkAdapterConfiguration(IPEnabled=1):
for ip_address in interface.IPAddress:
if ip_address != '0.0.0.0':
localip = ip_address
return localip
>>>getlocalip()
u'xxx.xxx.xxx.xxx'
>>>
顺便说一下,WMI非常强大……如果你正在做任何窗口机器的远程管理,你一定要看看它能做什么。
对于linux,你可以使用hostname -I system命令的check_output,就像这样:
from subprocess import check_output
check_output(['hostname', '-I'])
在Linux上:
>>> import socket, struct, fcntl
>>> sock = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
>>> sockfd = sock.fileno()
>>> SIOCGIFADDR = 0x8915
>>>
>>> def get_ip(iface = 'eth0'):
... ifreq = struct.pack('16sH14s', iface, socket.AF_INET, '\x00'*14)
... try:
... res = fcntl.ioctl(sockfd, SIOCGIFADDR, ifreq)
... except:
... return None
... ip = struct.unpack('16sH2x4s8x', res)[2]
... return socket.inet_ntoa(ip)
...
>>> get_ip('eth0')
'10.80.40.234'
>>>
import socket
print(socket.gethostbyname(socket.getfqdn()))
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