如何从数组中删除空白元素?

我有下面的数组

cities = ["Kathmandu", "Pokhara", "", "Dharan", "Butwal"]

我想从数组中删除空白元素，并希望得到以下结果:

cities = ["Kathmandu", "Pokhara", "Dharan", "Butwal"]

有没有像compact这样不需要循环的方法?

当前回答

当我想整理一个这样的数组时，我使用:

["Kathmandu", "Pokhara", "", "Dharan", "Butwal"] - ["", nil]

这将删除所有空白或nil元素。

其他回答

cities.reject! { |c| c.blank? }

为什么要用空白?在空的吗?blank可以识别nil，空字符串和空白。例如:

cities = ["Kathmandu", "Pokhara", " ", nil, "", "Dharan", "Butwal"].reject { |c| c.blank? }

仍然会返回:

["Kathmandu", "Pokhara", "Dharan", "Butwal"]

叫空?On " "将返回false，您可能希望它为true。

注:空白?只能通过Rails访问，Ruby只支持空?

更新在拒绝和拒绝!

注意:我遇到了这个问题，并在irb控制台上用ruby-3.0.1检查了这些方法。我也检查了ruby文档，但没有提到这一点。我不确定从哪个ruby版本变化就在那里。非常感谢来自社区的任何帮助。

在ruby-3.0.1中，我们可以使用reject或reject!

cities = ["Kathmandu", "Pokhara", "", "Dharan", "Butwal"]
cities.reject{ |e| e.empty? }
=> ["Kathmandu", "Pokhara", "Dharan", "Butwal"]

或简写

cities.reject(&:empty?)
=> ["Kathmandu", "Pokhara", "Dharan", "Butwal"]

无论我们是否有一个空值，两者都会返回[]?

你可以试试这个

 cities.reject!(&:empty?)

 cities = ["Kathmandu", "Pokhara", "", "Dharan", "Butwal"].delete_if {|c| c.empty? }

1.9.3p194 :001 > ["", "A", "B", "C", ""].reject(&:empty?)

=> ["A", "B", "C"]

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