我有下面的数组
cities = ["Kathmandu", "Pokhara", "", "Dharan", "Butwal"]
我想从数组中删除空白元素，并希望得到以下结果:
cities = ["Kathmandu", "Pokhara", "Dharan", "Butwal"]
有没有像compact这样不需要循环的方法?
当前回答
当我想整理一个这样的数组时，我使用:
["Kathmandu", "Pokhara", "", "Dharan", "Butwal"] - ["", nil]
这将删除所有空白或nil元素。
其他回答
最短路径城市。select(&:present?)
如果你的数组中有混合类型，下面是一个解决方案:
[nil,"some string here","",4,3,2]
解决方案:
[nil,"some string here","",4,3,2].compact.reject{|r| r.empty? if r.class == String}
输出:
=> ["some string here", 4, 3, 2]
已经有很多答案了，但如果你在Rails世界里，这里有另一种方法:
cities = ["Kathmandu", "Pokhara", "", "Dharan", "Butwal"].select &:present?
纯Ruby:
values = [1,2,3, " ", "", "", nil] - ["", " ", nil]
puts values # [1,2,3]
在我的项目中，我使用delete:
cities.delete("")
