我有下面的数组

cities = ["Kathmandu", "Pokhara", "", "Dharan", "Butwal"]

我想从数组中删除空白元素,并希望得到以下结果:

cities = ["Kathmandu", "Pokhara", "Dharan", "Butwal"]

有没有像compact这样不需要循环的方法?


当前回答

1.9.3p194 :001 > ["", "A", "B", "C", ""].reject(&:empty?)

=> ["A", "B", "C"]

其他回答

 cities = ["Kathmandu", "Pokhara", "", "Dharan", "Butwal"].delete_if {|c| c.empty? } 

在我的项目中,我使用delete:

cities.delete("")

你可以试试这个

 cities.reject!(&:empty?)

以下是对我有效的方法:

[1, "", 2, "hello", nil].reject(&:blank?)

输出:

[1, 2, "hello"]

使用严格的join & split更新

cities = ["Kathmandu", "Pokhara", "", "Dharan", "Butwal"]
cities.join(' ').split

结果将是:

["Kathmandu", "Pokhara", "Dharan", "Butwal"]

注意:这对有空间的城市不起作用