我有下面的数组

cities = ["Kathmandu", "Pokhara", "", "Dharan", "Butwal"]

我想从数组中删除空白元素,并希望得到以下结果:

cities = ["Kathmandu", "Pokhara", "Dharan", "Butwal"]

有没有像compact这样不需要循环的方法?


当前回答

cities.reject! { |c| c.blank? }

为什么要用空白?在空的吗?blank可以识别nil,空字符串和空白。例如:

cities = ["Kathmandu", "Pokhara", " ", nil, "", "Dharan", "Butwal"].reject { |c| c.blank? }

仍然会返回:

["Kathmandu", "Pokhara", "Dharan", "Butwal"]

叫空?On " "将返回false,您可能希望它为true。

注:空白?只能通过Rails访问,Ruby只支持空?

其他回答

在我的项目中,我使用delete:

cities.delete("")

以下是对我有效的方法:

[1, "", 2, "hello", nil].reject(&:blank?)

输出:

[1, 2, "hello"]

已经有很多答案了,但如果你在Rails世界里,这里有另一种方法:

 cities = ["Kathmandu", "Pokhara", "", "Dharan", "Butwal"].select &:present?

使用严格的join & split更新

cities = ["Kathmandu", "Pokhara", "", "Dharan", "Butwal"]
cities.join(' ').split

结果将是:

["Kathmandu", "Pokhara", "Dharan", "Butwal"]

注意:这对有空间的城市不起作用

纯Ruby:

values = [1,2,3, " ", "", "", nil] - ["", " ", nil]
puts values # [1,2,3]