如何在Python中连接两个列表?
例子:
listone = [1, 2, 3]
listtwo = [4, 5, 6]
预期结果:
>>> joinedlist
[1, 2, 3, 4, 5, 6]
如何在Python中连接两个列表?
例子:
listone = [1, 2, 3]
listtwo = [4, 5, 6]
预期结果:
>>> joinedlist
[1, 2, 3, 4, 5, 6]
当前回答
a = [1, 2, 3]
b = [4, 5, 6]
c = a + b
print(c)
输出
>>> [1, 2, 3, 4, 5, 6]
在上面的代码中,“+”运算符用于将两个列表连接成一个列表。
另一种解决方案
a = [1, 2, 3]
b = [4, 5, 6]
c = [] # Empty list in which we are going to append the values of list (a) and (b)
for i in a:
c.append(i)
for j in b:
c.append(j)
print(c)
输出
>>> [1, 2, 3, 4, 5, 6]
其他回答
可以使用集合获取唯一值的合并列表
mergedlist = list(set(listone + listtwo))
如果使用的是NumPy,可以使用以下命令连接两个兼容维度的数组:
numpy.concatenate([a,b])
a = [1, 2, 3]
b = [4, 5, 6]
c = a + b
print(c)
输出
>>> [1, 2, 3, 4, 5, 6]
在上面的代码中,“+”运算符用于将两个列表连接成一个列表。
另一种解决方案
a = [1, 2, 3]
b = [4, 5, 6]
c = [] # Empty list in which we are going to append the values of list (a) and (b)
for i in a:
c.append(i)
for j in b:
c.append(j)
print(c)
输出
>>> [1, 2, 3, 4, 5, 6]
您可以使用在列表对象上定义的append()方法:
mergedlist =[]
for elem in listone:
mergedlist.append(elem)
for elem in listtwo:
mergedlist.append(elem)
list(set(listone) | set(listtwo))
上述代码不保留顺序,并从每个列表中删除重复项(但不从连接列表中删除)。