如何在Python中连接两个列表?

例子:

listone = [1, 2, 3]
listtwo = [4, 5, 6]

预期结果:

>>> joinedlist
[1, 2, 3, 4, 5, 6]

当前回答

 a = [1, 2, 3]
 b = [4, 5, 6]
     
 c = a + b
 print(c)

输出

>>> [1, 2, 3, 4, 5, 6]

在上面的代码中,“+”运算符用于将两个列表连接成一个列表。

另一种解决方案

 a = [1, 2, 3]
 b = [4, 5, 6]
 c = [] # Empty list in which we are going to append the values of list (a) and (b)

 for i in a:
     c.append(i)
 for j in b:
     c.append(j)

 print(c)

输出

>>> [1, 2, 3, 4, 5, 6]

其他回答

可以使用集合获取唯一值的合并列表

mergedlist = list(set(listone + listtwo))

如果使用的是NumPy,可以使用以下命令连接两个兼容维度的数组:

numpy.concatenate([a,b])
 a = [1, 2, 3]
 b = [4, 5, 6]
     
 c = a + b
 print(c)

输出

>>> [1, 2, 3, 4, 5, 6]

在上面的代码中,“+”运算符用于将两个列表连接成一个列表。

另一种解决方案

 a = [1, 2, 3]
 b = [4, 5, 6]
 c = [] # Empty list in which we are going to append the values of list (a) and (b)

 for i in a:
     c.append(i)
 for j in b:
     c.append(j)

 print(c)

输出

>>> [1, 2, 3, 4, 5, 6]

您可以使用在列表对象上定义的append()方法:

mergedlist =[]
for elem in listone:
    mergedlist.append(elem)
for elem in listtwo:
    mergedlist.append(elem)
list(set(listone) | set(listtwo))

上述代码不保留顺序,并从每个列表中删除重复项(但不从连接列表中删除)。