比如,我有一个脚本,用这行代码调用:

./myscript -vfd ./foo/bar/someFile -o /fizz/someOtherFile

或者这个:

./myscript -v -f -d -o /fizz/someOtherFile ./foo/bar/someFile 

什么是公认的解析方式,以便在每种情况下(或两者的某种组合)$v、$f和$d都将设置为true,而$outFile将等于/fiz/someOtherFile?


当前回答

我使用前面的答案作为一个起点来整理我以前的即席参数解析。然后我重构了以下模板代码。它使用=或空格分隔的参数以及组合在一起的多个短参数来处理长参数和短参数。最后,它将所有非参数参数重新插入到$1,$2..变量中。

#!/usr/bin/env bash

# NOTICE: Uncomment if your script depends on bashisms.
#if [ -z "$BASH_VERSION" ]; then bash $0 $@ ; exit $? ; fi

echo "Before"
for i ; do echo - $i ; done


# Code template for parsing command line parameters using only portable shell
# code, while handling both long and short params, handling '-f file' and
# '-f=file' style param data and also capturing non-parameters to be inserted
# back into the shell positional parameters.

while [ -n "$1" ]; do
        # Copy so we can modify it (can't modify $1)
        OPT="$1"
        # Detect argument termination
        if [ x"$OPT" = x"--" ]; then
                shift
                for OPT ; do
                        REMAINS="$REMAINS \"$OPT\""
                done
                break
        fi
        # Parse current opt
        while [ x"$OPT" != x"-" ] ; do
                case "$OPT" in
                        # Handle --flag=value opts like this
                        -c=* | --config=* )
                                CONFIGFILE="${OPT#*=}"
                                shift
                                ;;
                        # and --flag value opts like this
                        -c* | --config )
                                CONFIGFILE="$2"
                                shift
                                ;;
                        -f* | --force )
                                FORCE=true
                                ;;
                        -r* | --retry )
                                RETRY=true
                                ;;
                        # Anything unknown is recorded for later
                        * )
                                REMAINS="$REMAINS \"$OPT\""
                                break
                                ;;
                esac
                # Check for multiple short options
                # NOTICE: be sure to update this pattern to match valid options
                NEXTOPT="${OPT#-[cfr]}" # try removing single short opt
                if [ x"$OPT" != x"$NEXTOPT" ] ; then
                        OPT="-$NEXTOPT"  # multiple short opts, keep going
                else
                        break  # long form, exit inner loop
                fi
        done
        # Done with that param. move to next
        shift
done
# Set the non-parameters back into the positional parameters ($1 $2 ..)
eval set -- $REMAINS


echo -e "After: \n configfile='$CONFIGFILE' \n force='$FORCE' \n retry='$RETRY' \n remains='$REMAINS'"
for i ; do echo - $i ; done

其他回答

这是我的方法-使用正则表达式。

无getopts它处理短参数块-qwerty它处理短参数-q-w-e它处理长选项--qwerty可以将属性传递给短选项或长选项(如果使用的是短选项块,则属性附加到最后一个选项)您可以使用空格或=来提供属性,但属性匹配,直到遇到连字符+空格“分隔符”,所以在--q=qwe ty中,qwe ty是一个属性它处理以上所有内容的混合,因此-o a-op attribute--option=att ribute--option att ribute有效

脚本:

#!/usr/bin/env sh

help_menu() {
  echo "Usage:

  ${0##*/} [-h][-l FILENAME][-d]

Options:

  -h, --help
    display this help and exit

  -l, --logfile=FILENAME
    filename

  -d, --debug
    enable debug
  "
}

parse_options() {
  case $opt in
    h|help)
      help_menu
      exit
     ;;
    l|logfile)
      logfile=${attr}
      ;;
    d|debug)
      debug=true
      ;;
    *)
      echo "Unknown option: ${opt}\nRun ${0##*/} -h for help.">&2
      exit 1
  esac
}
options=$@

until [ "$options" = "" ]; do
  if [[ $options =~ (^ *(--([a-zA-Z0-9-]+)|-([a-zA-Z0-9-]+))(( |=)(([\_\.\?\/\\a-zA-Z0-9]?[ -]?[\_\.\?a-zA-Z0-9]+)+))?(.*)|(.+)) ]]; then
    if [[ ${BASH_REMATCH[3]} ]]; then # for --option[=][attribute] or --option[=][attribute]
      opt=${BASH_REMATCH[3]}
      attr=${BASH_REMATCH[7]}
      options=${BASH_REMATCH[9]}
    elif [[ ${BASH_REMATCH[4]} ]]; then # for block options -qwert[=][attribute] or single short option -a[=][attribute]
      pile=${BASH_REMATCH[4]}
      while (( ${#pile} > 1 )); do
        opt=${pile:0:1}
        attr=""
        pile=${pile/${pile:0:1}/}
        parse_options
      done
      opt=$pile
      attr=${BASH_REMATCH[7]}
      options=${BASH_REMATCH[9]}
    else # leftovers that don't match
      opt=${BASH_REMATCH[10]}
      options=""
    fi
    parse_options
  fi
done

我最终实现了公认答案的dash(或/bin/sh)版本,基本上不使用数组:

while [[ $# -gt 0 ]]; do
    case "$1" in
    -v|--verbose) verbose=1; shift;;
    -o|--output) if [[ $# -gt 1 && "$2" != -* ]]; then
            file=$2; shift 2
        else
            echo "-o requires file-path" 1>&2; exit 1
        fi ;;
    --)
        while [[ $# -gt 0 ]]; do BACKUP="$BACKUP;$1"; shift; done
        break;;
    *)
        BACKUP="$BACKUP;$1"
        shift
        ;;
    esac
done
# Restore unused arguments.
while [ -n "$BACKUP" ] ; do
    [ ! -z "${BACKUP%%;*}" ] && set -- "$@" "${BACKUP%%;*}"
    [ "$BACKUP" = "${BACKUP/;/}" ] && break
    BACKUP="${BACKUP#*;}"
done

我使用前面的答案作为一个起点来整理我以前的即席参数解析。然后我重构了以下模板代码。它使用=或空格分隔的参数以及组合在一起的多个短参数来处理长参数和短参数。最后,它将所有非参数参数重新插入到$1,$2..变量中。

#!/usr/bin/env bash

# NOTICE: Uncomment if your script depends on bashisms.
#if [ -z "$BASH_VERSION" ]; then bash $0 $@ ; exit $? ; fi

echo "Before"
for i ; do echo - $i ; done


# Code template for parsing command line parameters using only portable shell
# code, while handling both long and short params, handling '-f file' and
# '-f=file' style param data and also capturing non-parameters to be inserted
# back into the shell positional parameters.

while [ -n "$1" ]; do
        # Copy so we can modify it (can't modify $1)
        OPT="$1"
        # Detect argument termination
        if [ x"$OPT" = x"--" ]; then
                shift
                for OPT ; do
                        REMAINS="$REMAINS \"$OPT\""
                done
                break
        fi
        # Parse current opt
        while [ x"$OPT" != x"-" ] ; do
                case "$OPT" in
                        # Handle --flag=value opts like this
                        -c=* | --config=* )
                                CONFIGFILE="${OPT#*=}"
                                shift
                                ;;
                        # and --flag value opts like this
                        -c* | --config )
                                CONFIGFILE="$2"
                                shift
                                ;;
                        -f* | --force )
                                FORCE=true
                                ;;
                        -r* | --retry )
                                RETRY=true
                                ;;
                        # Anything unknown is recorded for later
                        * )
                                REMAINS="$REMAINS \"$OPT\""
                                break
                                ;;
                esac
                # Check for multiple short options
                # NOTICE: be sure to update this pattern to match valid options
                NEXTOPT="${OPT#-[cfr]}" # try removing single short opt
                if [ x"$OPT" != x"$NEXTOPT" ] ; then
                        OPT="-$NEXTOPT"  # multiple short opts, keep going
                else
                        break  # long form, exit inner loop
                fi
        done
        # Done with that param. move to next
        shift
done
# Set the non-parameters back into the positional parameters ($1 $2 ..)
eval set -- $REMAINS


echo -e "After: \n configfile='$CONFIGFILE' \n force='$FORCE' \n retry='$RETRY' \n remains='$REMAINS'"
for i ; do echo - $i ; done

我使用它从末尾迭代key=>值。循环后捕获第一个可选参数。

用法为/script.sh可选的第一个参数-key value-key2 value2

#!/bin/sh

a=$(($#-1))
b=$(($#))
while [ $a -gt 0 ]; do
    eval 'key="$'$a'"; value="$'$b'"'
    echo "$key => $value"
    b=$(($b-2))
    a=$(($a-2))
done
unset a b key value

[ $(($#%2)) -ne 0 ] && echo "first_arg = $1"

当然,你可以从左到右做一些改变。

此代码段显示key=>值对和第一个参数(如果存在)。

#!/bin/sh

a=$((1+$#%2))
b=$((1+$a))

[ $(($#%2)) -ne 0 ] && echo "first_arg = $1"

while [ $a -lt $# ]; do
    eval 'key="$'$a'"; value="$'$b'"'
    echo "$key => $value"
    b=$(($b+2))
    a=$(($a+2))
done

unset a b key value

测试了100000个参数,速度很快。

您还可以从左到右迭代key=>value和第一个可选arg,而不使用eval:

#!/bin/sh

a=$(($#%2))
b=0

[ $a -eq 1 ] && echo "first_arg = $1"

for value; do
    if [ $b -gt $a -a $(($b%2)) -ne $a ]; then
        echo "$key => $value"
    fi
    key="$value"
    b=$((1+$b))
done

unset a b key value

另一个Shell参数分析器(ASAP)

符合POSIX,无getopt

我受到@bronson相对简单的回答的启发,并试图改进它(不增加太多复杂性)。结果如下:

使用-n[arg]、-abn[arg],--name[arg]和--name=arg样式中的任意一种选项;参数可以按任何顺序出现,循环后$@中只留下位置参数;使用--强制将剩余的参数视为位置参数;检测无效选项和缺少的参数;不依赖于getopt或外部工具(一个功能使用简单的sed命令);便携式,紧凑,可读性强,具有独立功能。

# Convenience functions.
usage_error () { echo >&2 "$(basename $0):  $1"; exit 2; }
assert_argument () { test "$1" != "$EOL" || usage_error "$2 requires an argument"; }

# One loop, nothing more.
if [ "$#" != 0 ]; then
  EOL=$(printf '\1\3\3\7')
  set -- "$@" "$EOL"
  while [ "$1" != "$EOL" ]; do
    opt="$1"; shift
    case "$opt" in

      # Your options go here.
      -f|--flag) flag='true';;
      -n|--name) assert_argument "$1" "$opt"; name="$1"; shift;;

      # Arguments processing. You may remove any unneeded line after the 1st.
      -|''|[!-]*) set -- "$@" "$opt";;                                          # positional argument, rotate to the end
      --*=*)      set -- "${opt%%=*}" "${opt#*=}" "$@";;                        # convert '--name=arg' to '--name' 'arg'
      -[!-]?*)    set -- $(echo "${opt#-}" | sed 's/\(.\)/ -\1/g') "$@";;       # convert '-abc' to '-a' '-b' '-c'
      --)         while [ "$1" != "$EOL" ]; do set -- "$@" "$1"; shift; done;;  # process remaining arguments as positional
      -*)         usage_error "unknown option: '$opt'";;                        # catch misspelled options
      *)          usage_error "this should NEVER happen ($opt)";;               # sanity test for previous patterns

    esac
  done
  shift  # $EOL
fi

# Do something cool with "$@"... \o/

注:我知道。。。二进制模式为0x01030307的参数可能会破坏逻辑。但是,如果有人在命令行中传递这样的参数,他们应该得到它。