假设我们创建一个名为test_args.sh的shell脚本，如下所示

#!/bin/sh
until [ $# -eq 0 ]
do
  name=${1:1}; shift;
  if [[ -z "$1" || $1 == -* ]] ; then eval "export $name=true"; else eval "export $name=$1"; shift; fi  
done
echo "year=$year month=$month day=$day flag=$flag"

运行以下命令后：

sh test_args.sh  -year 2017 -flag  -month 12 -day 22 

输出将是：

year=2017 month=12 day=22 flag=true

使用bash模块中的模块“参数”

例子：

#!/bin/bash
. import.sh log arguments

NAME="world"

parse_arguments "-n|--name)NAME;S" -- "$@" || {
  error "Cannot parse command line."
  exit 1
}

info "Hello, $NAME!"

当我尝试这个问题时，上面的答案似乎有点bug——这是我发现更强大的解决方案：

boolean_arg=""
arg_with_value=""

while [[ $# -gt 0 ]]
do
key="$1"
case $key in
    -b|--boolean-arg)
    boolean_arg=true
    shift
    ;;
    -a|--arg-with-value)
    arg_with_value="$2"
    shift
    shift
    ;;
    -*)
    echo "Unknown option: $1"
    exit 1
    ;;
    *)
    arg_num=$(( $arg_num + 1 ))
    case $arg_num in
        1)
        first_normal_arg="$1"
        shift
        ;;
        2)
        second_normal_arg="$1"
        shift
        ;;
        *)
        bad_args=TRUE
    esac
    ;;
esac
done

# Handy to have this here when adding arguments to
# see if they're working. Just edit the '0' to be '1'.
if [[ 0 == 1 ]]; then
    echo "first_normal_arg: $first_normal_arg"
    echo "second_normal_arg: $second_normal_arg"
    echo "boolean_arg: $boolean_arg"
    echo "arg_with_value: $arg_with_value"
    exit 0
fi

if [[ $bad_args == TRUE || $arg_num < 2 ]]; then
    echo "Usage: $(basename "$0") <first-normal-arg> <second-normal-arg> [--boolean-arg] [--arg-with-value VALUE]"
    exit 1
fi

另一个Shell参数分析器（ASAP）

符合POSIX，无getopt

我受到@bronson相对简单的回答的启发，并试图改进它（不增加太多复杂性）。结果如下：

使用-n[arg]、-abn[arg]，--name[arg]和--name=arg样式中的任意一种选项；参数可以按任何顺序出现，循环后$@中只留下位置参数；使用--强制将剩余的参数视为位置参数；检测无效选项和缺少的参数；不依赖于getopt或外部工具（一个功能使用简单的sed命令）；便携式，紧凑，可读性强，具有独立功能。

# Convenience functions.
usage_error () { echo >&2 "$(basename $0):  $1"; exit 2; }
assert_argument () { test "$1" != "$EOL" || usage_error "$2 requires an argument"; }

# One loop, nothing more.
if [ "$#" != 0 ]; then
  EOL=$(printf '\1\3\3\7')
  set -- "$@" "$EOL"
  while [ "$1" != "$EOL" ]; do
    opt="$1"; shift
    case "$opt" in

      # Your options go here.
      -f|--flag) flag='true';;
      -n|--name) assert_argument "$1" "$opt"; name="$1"; shift;;

      # Arguments processing. You may remove any unneeded line after the 1st.
      -|''|[!-]*) set -- "$@" "$opt";;                                          # positional argument, rotate to the end
      --*=*)      set -- "${opt%%=*}" "${opt#*=}" "$@";;                        # convert '--name=arg' to '--name' 'arg'
      -[!-]?*)    set -- $(echo "${opt#-}" | sed 's/\(.\)/ -\1/g') "$@";;       # convert '-abc' to '-a' '-b' '-c'
      --)         while [ "$1" != "$EOL" ]; do set -- "$@" "$1"; shift; done;;  # process remaining arguments as positional
      -*)         usage_error "unknown option: '$opt'";;                        # catch misspelled options
      *)          usage_error "this should NEVER happen ($opt)";;               # sanity test for previous patterns

    esac
  done
  shift  # $EOL
fi

# Do something cool with "$@"... \o/

注：我知道。。。二进制模式为0x01030307的参数可能会破坏逻辑。但是，如果有人在命令行中传递这样的参数，他们应该得到它。

根据这里的其他答案，这是我的版本：

#!/bin/bash
set -e

function parse() {
    for arg in "$@"; do # transform long options to short ones
        shift
        case "$arg" in
            "--name") set -- "$@" "-n" ;;
            "--verbose") set -- "$@" "-v" ;;
            *) set -- "$@" "$arg"
        esac
    done

    while getopts "n:v" optname  # left to ":" are flags that expect a value, right to the ":" are flags that expect nothing
    do
        case "$optname" in
            "n") name=${OPTARG} ;;
            "v") verbose=true ;;
        esac
    done
    shift "$((OPTIND-1))" # shift out all the already processed options
}


parse "$@"
echo "hello $name"
if [ ! -z $verbose ]; then echo 'nice to meet you!'; fi

用法：

$ ./parse.sh
hello
$ ./parse.sh -n YOUR_NAME
hello YOUR_NAME
$ ./parse.sh -n YOUR_NAME -v
hello YOUR_NAME
nice to meet you!
$ ./parse.sh -v -n YOUR_NAME
hello YOUR_NAME
nice to meet you!
$ ./parse.sh -v
hello 
nice to meet you!

# As long as there is at least one more argument, keep looping
while [[ $# -gt 0 ]]; do
    key="$1"
    case "$key" in
        # This is a flag type option. Will catch either -f or --foo
        -f|--foo)
        FOO=1
        ;;
        # Also a flag type option. Will catch either -b or --bar
        -b|--bar)
        BAR=1
        ;;
        # This is an arg value type option. Will catch -o value or --output-file value
        -o|--output-file)
        shift # past the key and to the value
        OUTPUTFILE="$1"
        ;;
        # This is an arg=value type option. Will catch -o=value or --output-file=value
        -o=*|--output-file=*)
        # No need to shift here since the value is part of the same string
        OUTPUTFILE="${key#*=}"
        ;;
        *)
        # Do whatever you want with extra options
        echo "Unknown option '$key'"
        ;;
    esac
    # Shift after checking all the cases to get the next option
    shift
done

这使您既可以使用空格分隔的选项/值，也可以使用相等的定义值。

因此，您可以使用以下命令运行脚本：

./myscript --foo -b -o /fizz/file.txt

以及：

./myscript -f --bar -o=/fizz/file.txt

并且两者应该具有相同的最终结果。

赞成的意见：

允许-arg=value和-arg-value适用于bash中可以使用的任何arg名称意思是-a或-arg或--arg或-ar-g或其他纯粹的狂欢。无需学习/使用getopt或getopts

欺骗：

无法组合参数意思是没有-abc。您必须执行-a-b-c