在我的iPhone应用程序中,我用相机拍了一张照片,然后我想把它调整为290*390像素。我用这个方法来调整图像的大小:

UIImage *newImage = [image _imageScaledToSize:CGSizeMake(290, 390)
                         interpolationQuality:1];    

它工作得很好,但它是一个没有记录的功能,所以我不能再在iPhone OS4上使用它了。

所以…调整UIImage大小最简单的方法是什么?


当前回答

为什么这么复杂?我认为使用系统API可以达到同样的效果:

UIImage *largeImage;
CGFloat ratio = 0.4; // you want to get a new image that is 40% the size of large image.
UIImage *newImage = [UIImage imageWithCGImage:largeImage.CGImage
                                        scale:1/ratio
                                  orientation:largeImage.imageOrientation];
// notice the second argument, it is 1/ratio, not ratio.

唯一的问题是你应该传递目标比率的倒数作为第二个参数,因为根据文档,第二个参数指定原始图像与新缩放图像的比率。

其他回答

如果你只想要一个更小的图像,不关心确切的大小:

+ (UIImage *)imageWithImage:(UIImage *)image scaledToScale:(CGFloat)scale
{
    UIGraphicsBeginImageContextWithOptions(self.size, YES, scale);
    CGContextRef context = UIGraphicsGetCurrentContext();
    CGContextSetInterpolationQuality(context, kCGInterpolationHigh);
    [self drawInRect:CGRectMake(0, 0, self.size.width, self.size.height)];
    UIImage *newImage = UIGraphicsGetImageFromCurrentImageContext();
    UIGraphicsEndImageContext();
    return newImage;
}

将比例设置为0.25f将从800万相机中获得816 * 612的图像。

这里有一个UIImage+Scale的分类。

对于Swift 5:

extension UIImage {
  func resized(to newSize: CGSize) -> UIImage? {
    UIGraphicsBeginImageContextWithOptions(newSize, false, 0)
    defer { UIGraphicsEndImageContext() }

    draw(in: CGRect(origin: .zero, size: newSize))
    return UIGraphicsGetImageFromCurrentImageContext()
  }
}

Swift 2.0:

let image = UIImage(named: "imageName")
let newSize = CGSize(width: 10, height: 10)

UIGraphicsBeginImageContextWithOptions(newSize, false, 0.0)
image?.drawInRect(CGRectMake(0, 0, newSize.width, newSize.height))
let imageResized = UIGraphicsGetImageFromCurrentImageContext()
UIGraphicsEndImageContext()

这是一个与Swift 3和Swift 4兼容的UIImage扩展,它可以将图像缩放到给定的大小

extension UIImage {

    func scaledImage(withSize size: CGSize) -> UIImage {
        UIGraphicsBeginImageContextWithOptions(size, false, 0.0)
        defer { UIGraphicsEndImageContext() }
        draw(in: CGRect(x: 0.0, y: 0.0, width: size.width, height: size.height))
        return UIGraphicsGetImageFromCurrentImageContext()!
    }

    func scaleImageToFitSize(size: CGSize) -> UIImage {
        let aspect = self.size.width / self.size.height
        if size.width / aspect <= size.height {
            return scaledImage(withSize: CGSize(width: size.width, height: size.width / aspect))
        } else {
            return scaledImage(withSize: CGSize(width: size.height * aspect, height: size.height))
        }
    }

}

示例使用

let image = UIImage(named: "apple")
let scaledImage = image.scaleImageToFitSize(size: CGSize(width: 45.0, height: 45.0))

为什么这么复杂?我认为使用系统API可以达到同样的效果:

UIImage *largeImage;
CGFloat ratio = 0.4; // you want to get a new image that is 40% the size of large image.
UIImage *newImage = [UIImage imageWithCGImage:largeImage.CGImage
                                        scale:1/ratio
                                  orientation:largeImage.imageOrientation];
// notice the second argument, it is 1/ratio, not ratio.

唯一的问题是你应该传递目标比率的倒数作为第二个参数,因为根据文档,第二个参数指定原始图像与新缩放图像的比率。