在我的iPhone应用程序中，我用相机拍了一张照片，然后我想把它调整为290*390像素。我用这个方法来调整图像的大小:
UIImage *newImage = [image _imageScaledToSize:CGSizeMake(290, 390)
interpolationQuality:1];
它工作得很好，但它是一个没有记录的功能，所以我不能再在iPhone OS4上使用它了。
所以…调整UIImage大小最简单的方法是什么?
当前回答
为什么这么复杂?我认为使用系统API可以达到同样的效果:
UIImage *largeImage;
CGFloat ratio = 0.4; // you want to get a new image that is 40% the size of large image.
UIImage *newImage = [UIImage imageWithCGImage:largeImage.CGImage
scale:1/ratio
orientation:largeImage.imageOrientation];
// notice the second argument, it is 1/ratio, not ratio.
唯一的问题是你应该传递目标比率的倒数作为第二个参数，因为根据文档，第二个参数指定原始图像与新缩放图像的比率。
其他回答
@Paul Lynch的回答很好，但它会改变图像比例。 如果你不想改变图像比例，并且仍然希望新的图像适合新的大小，试试这个。
+ (UIImage *)imageWithImage:(UIImage *)image scaledToSize:(CGSize)newSize {
// calculate a new size which ratio is same to original image
CGFloat ratioW = image.size.width / newSize.width;
CGFloat ratioH = image.size.height / newSize.height;
CGFloat ratio = image.size.width / image.size.height;
CGSize showSize = CGSizeZero;
if (ratioW > 1 && ratioH > 1) {
if (ratioW > ratioH) {
showSize.width = newSize.width;
showSize.height = showSize.width / ratio;
} else {
showSize.height = newSize.height;
showSize.width = showSize.height * ratio;
}
} else if (ratioW > 1) {
showSize.width = showSize.width;
showSize.height = showSize.width / ratio;
} else if (ratioH > 1) {
showSize.height = showSize.height;
showSize.width = showSize.height * ratio;
}
//UIGraphicsBeginImageContext(newSize);
// In next line, pass 0.0 to use the current device's pixel scaling factor (and thus account for Retina resolution).
// Pass 1.0 to force exact pixel size.
UIGraphicsBeginImageContextWithOptions(showSize, NO, 0.0);
[image drawInRect:CGRectMake(0, 0, showSize.width, showSize.height)];
UIImage *newImage = UIGraphicsGetImageFromCurrentImageContext();
UIGraphicsEndImageContext();
return newImage;}
我在苹果自己的例子中找到了一个UIImage的类别，它做了同样的技巧。这是链接:https://developer.apple.com/library/ios/samplecode/sc2273/Listings/AirDropSample_UIImage_Resize_m.html。
你只需要改变电话号码:
UIGraphicsBeginImageContextWithOptions(newSize, YES, 2.0);
in imageWithImage:scaledToSize:inRect: with
UIGraphicsBeginImageContextWithOptions(newSize, NO, 2.0);
为了考虑图像中的alpha通道。
Swift 2.0:
let image = UIImage(named: "imageName")
let newSize = CGSize(width: 10, height: 10)
UIGraphicsBeginImageContextWithOptions(newSize, false, 0.0)
image?.drawInRect(CGRectMake(0, 0, newSize.width, newSize.height))
let imageResized = UIGraphicsGetImageFromCurrentImageContext()
UIGraphicsEndImageContext()
为什么这么复杂?我认为使用系统API可以达到同样的效果:
UIImage *largeImage;
CGFloat ratio = 0.4; // you want to get a new image that is 40% the size of large image.
UIImage *newImage = [UIImage imageWithCGImage:largeImage.CGImage
scale:1/ratio
orientation:largeImage.imageOrientation];
// notice the second argument, it is 1/ratio, not ratio.
唯一的问题是你应该传递目标比率的倒数作为第二个参数，因为根据文档，第二个参数指定原始图像与新缩放图像的比率。
下面是iwasrob对上述类别的修改。它保持原始图像的纵横比，而不是扭曲它。
- (UIImage*)scaleToSizeKeepAspect:(CGSize)size {
UIGraphicsBeginImageContext(size);
CGFloat ws = size.width/self.size.width;
CGFloat hs = size.height/self.size.height;
if (ws > hs) {
ws = hs/ws;
hs = 1.0;
} else {
hs = ws/hs;
ws = 1.0;
}
CGContextRef context = UIGraphicsGetCurrentContext();
CGContextTranslateCTM(context, 0.0, size.height);
CGContextScaleCTM(context, 1.0, -1.0);
CGContextDrawImage(context, CGRectMake(size.width/2-(size.width*ws)/2,
size.height/2-(size.height*hs)/2, size.width*ws,
size.height*hs), self.CGImage);
UIImage* scaledImage = UIGraphicsGetImageFromCurrentImageContext();
UIGraphicsEndImageContext();
return scaledImage;
}
