在我的iPhone应用程序中，我用相机拍了一张照片，然后我想把它调整为290*390像素。我用这个方法来调整图像的大小:
UIImage *newImage = [image _imageScaledToSize:CGSizeMake(290, 390)
interpolationQuality:1];
它工作得很好，但它是一个没有记录的功能，所以我不能再在iPhone OS4上使用它了。
所以…调整UIImage大小最简单的方法是什么?
当前回答
正确的Swift 3.0 iOS 10+解决方案:使用ImageRenderer和闭包语法:
func imageWith(newSize: CGSize) -> UIImage {
let image = UIGraphicsImageRenderer(size: newSize).image { _ in
draw(in: CGRect(origin: .zero, size: newSize))
}
return image.withRenderingMode(renderingMode)
}
这是Objective-C版本:
@implementation UIImage (ResizeCategory)
- (UIImage *)imageWithSize:(CGSize)newSize
{
UIGraphicsImageRenderer *renderer = [[UIGraphicsImageRenderer alloc] initWithSize:newSize];
UIImage *image = [renderer imageWithActions:^(UIGraphicsImageRendererContext*_Nonnull myContext) {
[self drawInRect:(CGRect) {.origin = CGPointZero, .size = newSize}];
}];
return [image imageWithRenderingMode:self.renderingMode];
}
@end
其他回答
下面是iwasrob对上述类别的修改。它保持原始图像的纵横比，而不是扭曲它。
- (UIImage*)scaleToSizeKeepAspect:(CGSize)size {
UIGraphicsBeginImageContext(size);
CGFloat ws = size.width/self.size.width;
CGFloat hs = size.height/self.size.height;
if (ws > hs) {
ws = hs/ws;
hs = 1.0;
} else {
hs = ws/hs;
ws = 1.0;
}
CGContextRef context = UIGraphicsGetCurrentContext();
CGContextTranslateCTM(context, 0.0, size.height);
CGContextScaleCTM(context, 1.0, -1.0);
CGContextDrawImage(context, CGRectMake(size.width/2-(size.width*ws)/2,
size.height/2-(size.height*hs)/2, size.width*ws,
size.height*hs), self.CGImage);
UIImage* scaledImage = UIGraphicsGetImageFromCurrentImageContext();
UIGraphicsEndImageContext();
return scaledImage;
}
以下是斯威夫特版的保罗·林奇的回答
func imageWithImage(image:UIImage, scaledToSize newSize:CGSize) -> UIImage{
UIGraphicsBeginImageContextWithOptions(newSize, false, 0.0);
image.drawInRect(CGRectMake(0, 0, newSize.width, newSize.height))
let newImage:UIImage = UIGraphicsGetImageFromCurrentImageContext()
UIGraphicsEndImageContext()
return newImage
}
作为延伸:
public extension UIImage {
func copy(newSize: CGSize, retina: Bool = true) -> UIImage? {
// In next line, pass 0 to use the current device's pixel scaling factor (and thus account for Retina resolution).
// Pass 1 to force exact pixel size.
UIGraphicsBeginImageContextWithOptions(
/* size: */ newSize,
/* opaque: */ false,
/* scale: */ retina ? 0 : 1
)
defer { UIGraphicsEndImageContext() }
self.draw(in: CGRect(origin: .zero, size: newSize))
return UIGraphicsGetImageFromCurrentImageContext()
}
}
迅速回答:
func scaleDown(image: UIImage, withSize: CGSize) -> UIImage {
let scale = UIScreen.main.scale
UIGraphicsBeginImageContextWithOptions(withSize, false, scale)
image.draw(in: CGRect(x: 0, y: 0, width: withSize.width, height: withSize.height))
let newImage = UIGraphicsGetImageFromCurrentImageContext()
UIGraphicsEndImageContext()
return newImage!
}
如果你只想要一个更小的图像，不关心确切的大小:
+ (UIImage *)imageWithImage:(UIImage *)image scaledToScale:(CGFloat)scale
{
UIGraphicsBeginImageContextWithOptions(self.size, YES, scale);
CGContextRef context = UIGraphicsGetCurrentContext();
CGContextSetInterpolationQuality(context, kCGInterpolationHigh);
[self drawInRect:CGRectMake(0, 0, self.size.width, self.size.height)];
UIImage *newImage = UIGraphicsGetImageFromCurrentImageContext();
UIGraphicsEndImageContext();
return newImage;
}
将比例设置为0.25f将从800万相机中获得816 * 612的图像。
这里有一个UIImage+Scale的分类。
正确的Swift 3.0 iOS 10+解决方案:使用ImageRenderer和闭包语法:
func imageWith(newSize: CGSize) -> UIImage {
let image = UIGraphicsImageRenderer(size: newSize).image { _ in
draw(in: CGRect(origin: .zero, size: newSize))
}
return image.withRenderingMode(renderingMode)
}
这是Objective-C版本:
@implementation UIImage (ResizeCategory)
- (UIImage *)imageWithSize:(CGSize)newSize
{
UIGraphicsImageRenderer *renderer = [[UIGraphicsImageRenderer alloc] initWithSize:newSize];
UIImage *image = [renderer imageWithActions:^(UIGraphicsImageRendererContext*_Nonnull myContext) {
[self drawInRect:(CGRect) {.origin = CGPointZero, .size = newSize}];
}];
return [image imageWithRenderingMode:self.renderingMode];
}
@end
