以下是斯威夫特版的保罗·林奇的回答

func imageWithImage(image:UIImage, scaledToSize newSize:CGSize) -> UIImage{
    UIGraphicsBeginImageContextWithOptions(newSize, false, 0.0);
    image.drawInRect(CGRectMake(0, 0, newSize.width, newSize.height))
    let newImage:UIImage = UIGraphicsGetImageFromCurrentImageContext()
    UIGraphicsEndImageContext()
    return newImage
}

作为延伸:

public extension UIImage {
    func copy(newSize: CGSize, retina: Bool = true) -> UIImage? {
        // In next line, pass 0 to use the current device's pixel scaling factor (and thus account for Retina resolution).
        // Pass 1 to force exact pixel size.
        UIGraphicsBeginImageContextWithOptions(
            /* size: */ newSize,
            /* opaque: */ false,
            /* scale: */ retina ? 0 : 1
        )
        defer { UIGraphicsEndImageContext() }

        self.draw(in: CGRect(origin: .zero, size: newSize))
        return UIGraphicsGetImageFromCurrentImageContext()
    }
}

我也见过这样做(我在UIButtons的正常和选定状态下使用，因为按钮不会调整大小来适应)。功劳归于原作者。

首先创建一个空的。h和。m文件，分别命名为uiimageresize .h和uiimageresize .m

// Put this in UIImageResizing.h
@interface UIImage (Resize)
- (UIImage*)scaleToSize:(CGSize)size;
@end

// Put this in UIImageResizing.m
@implementation UIImage (Resize)

- (UIImage*)scaleToSize:(CGSize)size {
UIGraphicsBeginImageContext(size);

CGContextRef context = UIGraphicsGetCurrentContext();
CGContextTranslateCTM(context, 0.0, size.height);
CGContextScaleCTM(context, 1.0, -1.0);

CGContextDrawImage(context, CGRectMake(0.0f, 0.0f, size.width, size.height), self.CGImage);

UIImage* scaledImage = UIGraphicsGetImageFromCurrentImageContext();

UIGraphicsEndImageContext();

return scaledImage;
}

@end

将.h文件包含在你将要使用该函数的.m文件中，然后像这样调用它:

UIImage* image = [UIImage imageNamed:@"largeImage.png"];
UIImage* smallImage = [image scaleToSize:CGSizeMake(100.0f,100.0f)];

Trevor Howard有一些UIImage类别，可以很好地处理大小调整。如果没有其他问题，您可以使用代码作为示例。

注意:从iOS 5.1开始，这个答案可能无效。见下面的评论。

有时你的图像的比例大于1，所以调整图像大小会使图像意想不到。这就是这种情况下的解。

extension UIImage {
    func resizeTo(newSize: CGSize) -> UIImage {
        // Important thing here
        let format = UIGraphicsImageRendererFormat()
        format.scale = 1
        
        let image = UIGraphicsImageRenderer(size: newSize, format: format).image { _ in
            draw(in: CGRect(origin: .zero, size: newSize))
        }
            
        return image.withRenderingMode(renderingMode)
    }
}

正确的Swift 3.0 iOS 10+解决方案:使用ImageRenderer和闭包语法:

func imageWith(newSize: CGSize) -> UIImage {
    let image = UIGraphicsImageRenderer(size: newSize).image { _ in
        draw(in: CGRect(origin: .zero, size: newSize))
    }
        
    return image.withRenderingMode(renderingMode)
}

这是Objective-C版本:

@implementation UIImage (ResizeCategory)
- (UIImage *)imageWithSize:(CGSize)newSize
{
    UIGraphicsImageRenderer *renderer = [[UIGraphicsImageRenderer alloc] initWithSize:newSize];
    UIImage *image = [renderer imageWithActions:^(UIGraphicsImageRendererContext*_Nonnull myContext) {
        [self drawInRect:(CGRect) {.origin = CGPointZero, .size = newSize}];
    }];
    return [image imageWithRenderingMode:self.renderingMode];
}
@end

为什么这么复杂?我认为使用系统API可以达到同样的效果:

UIImage *largeImage;
CGFloat ratio = 0.4; // you want to get a new image that is 40% the size of large image.
UIImage *newImage = [UIImage imageWithCGImage:largeImage.CGImage
                                        scale:1/ratio
                                  orientation:largeImage.imageOrientation];
// notice the second argument, it is 1/ratio, not ratio.

唯一的问题是你应该传递目标比率的倒数作为第二个参数，因为根据文档，第二个参数指定原始图像与新缩放图像的比率。