有时你的图像的比例大于1，所以调整图像大小会使图像意想不到。这就是这种情况下的解。

extension UIImage {
    func resizeTo(newSize: CGSize) -> UIImage {
        // Important thing here
        let format = UIGraphicsImageRendererFormat()
        format.scale = 1
        
        let image = UIGraphicsImageRenderer(size: newSize, format: format).image { _ in
            draw(in: CGRect(origin: .zero, size: newSize))
        }
            
        return image.withRenderingMode(renderingMode)
    }
}

下面是iwasrob对上述类别的修改。它保持原始图像的纵横比，而不是扭曲它。

- (UIImage*)scaleToSizeKeepAspect:(CGSize)size {
    UIGraphicsBeginImageContext(size);

    CGFloat ws = size.width/self.size.width;
    CGFloat hs = size.height/self.size.height;

    if (ws > hs) {
        ws = hs/ws;
        hs = 1.0;
    } else {
        hs = ws/hs;
        ws = 1.0;
    }

    CGContextRef context = UIGraphicsGetCurrentContext();
    CGContextTranslateCTM(context, 0.0, size.height);
    CGContextScaleCTM(context, 1.0, -1.0);

    CGContextDrawImage(context, CGRectMake(size.width/2-(size.width*ws)/2,
        size.height/2-(size.height*hs)/2, size.width*ws,
        size.height*hs), self.CGImage);

    UIImage* scaledImage = UIGraphicsGetImageFromCurrentImageContext();

    UIGraphicsEndImageContext();

    return scaledImage;
}

最简单的方法是设置UIImageView的框架，并将contentMode设置为其中一个调整大小的选项。

或者你可以使用这个实用工具方法，如果你真的需要调整图像的大小:

+ (UIImage *)imageWithImage:(UIImage *)image scaledToSize:(CGSize)newSize {
    //UIGraphicsBeginImageContext(newSize);
    // In next line, pass 0.0 to use the current device's pixel scaling factor (and thus account for Retina resolution).
    // Pass 1.0 to force exact pixel size.
    UIGraphicsBeginImageContextWithOptions(newSize, NO, 0.0);
    [image drawInRect:CGRectMake(0, 0, newSize.width, newSize.height)];
    UIImage *newImage = UIGraphicsGetImageFromCurrentImageContext();    
    UIGraphicsEndImageContext();
    return newImage;
}

使用示例:

#import "MYUtil.h"
…
UIImage *myIcon = [MYUtil imageWithImage:myUIImageInstance scaledToSize:CGSizeMake(20, 20)];

有效的方法，不拉伸图像Swift 4

// Method to resize image
func resize(image: UIImage, toScaleSize:CGSize) -> UIImage {
                UIGraphicsBeginImageContextWithOptions(toScaleSize, true, image.scale)
                        image.draw(in: CGRect(x: 0, y: 0, width: toScaleSize.width, height: toScaleSize.height))
                        let scaledImage = UIGraphicsGetImageFromCurrentImageContext()
                        UIGraphicsEndImageContext()
                        return scaledImage!
                }

//调用方法

    let resizedImage = self.resize(image: UIImage(named: "YourImageName")!, toScaleSize: CGSize(width: 290, height: 390))

我在苹果自己的例子中找到了一个UIImage的类别，它做了同样的技巧。这是链接:https://developer.apple.com/library/ios/samplecode/sc2273/Listings/AirDropSample_UIImage_Resize_m.html。

你只需要改变电话号码:

UIGraphicsBeginImageContextWithOptions(newSize, YES, 2.0);

in imageWithImage:scaledToSize:inRect: with

UIGraphicsBeginImageContextWithOptions(newSize, NO, 2.0);

为了考虑图像中的alpha通道。

为什么这么复杂?我认为使用系统API可以达到同样的效果:

UIImage *largeImage;
CGFloat ratio = 0.4; // you want to get a new image that is 40% the size of large image.
UIImage *newImage = [UIImage imageWithCGImage:largeImage.CGImage
                                        scale:1/ratio
                                  orientation:largeImage.imageOrientation];
// notice the second argument, it is 1/ratio, not ratio.

唯一的问题是你应该传递目标比率的倒数作为第二个参数，因为根据文档，第二个参数指定原始图像与新缩放图像的比率。