还有一个选择:https://github.com/stefanhaustein/expressionparser

我已经实现了一个简单而灵活的选项，以允许两者:

即时处理(Calculator.java, SetDemo.java) 构建和处理解析树(TreeBuilder.java)

上面链接的TreeBuilder是进行符号推导的CAS演示包的一部分。还有一个BASIC解释器的例子，我已经开始使用它来构建一个TypeScript解释器。

我已经使用迭代解析和分流码算法，我真的很喜欢开发表达式求值器，你可以在这里找到所有的代码

https://github.com/nagaraj200788/JavaExpressionEvaluator

有73个测试用例，甚至工作于大整数，大小数

支持所有关系，算术表达式和两者的组合。 甚至支持三元运算符。

增加了增强，以支持有符号的数字，如-100+89，这是有趣的，详细信息请检查TokenReader.isUnaryOperator()方法，我已经更新了上面链接中的代码

解决这个问题的正确方法是使用词法分析器和解析器。您可以自己编写这些页面的简单版本，或者这些页面还包含指向Java词法分析器和解析器的链接。

创建递归下降解析器是非常好的学习练习。

package ExpressionCalculator.expressioncalculator;

import java.text.DecimalFormat;
import java.util.Scanner;

public class ExpressionCalculator {

private static String addSpaces(String exp){

    //Add space padding to operands.
    //https://regex101.com/r/sJ9gM7/73
    exp = exp.replaceAll("(?<=[0-9()])[\\/]", " / ");
    exp = exp.replaceAll("(?<=[0-9()])[\\^]", " ^ ");
    exp = exp.replaceAll("(?<=[0-9()])[\\*]", " * ");
    exp = exp.replaceAll("(?<=[0-9()])[+]", " + "); 
    exp = exp.replaceAll("(?<=[0-9()])[-]", " - ");

    //Keep replacing double spaces with single spaces until your string is properly formatted
    /*while(exp.indexOf("  ") != -1){
        exp = exp.replace("  ", " ");
     }*/
    exp = exp.replaceAll(" {2,}", " ");

       return exp;
}

public static Double evaluate(String expr){

    DecimalFormat df = new DecimalFormat("#.####");

    //Format the expression properly before performing operations
    String expression = addSpaces(expr);

    try {
        //We will evaluate using rule BDMAS, i.e. brackets, division, power, multiplication, addition and
        //subtraction will be processed in following order
        int indexClose = expression.indexOf(")");
        int indexOpen = -1;
        if (indexClose != -1) {
            String substring = expression.substring(0, indexClose);
            indexOpen = substring.lastIndexOf("(");
            substring = substring.substring(indexOpen + 1).trim();
            if(indexOpen != -1 && indexClose != -1) {
                Double result = evaluate(substring);
                expression = expression.substring(0, indexOpen).trim() + " " + result + " " + expression.substring(indexClose + 1).trim();
                return evaluate(expression.trim());
            }
        }

        String operation = "";
        if(expression.indexOf(" / ") != -1){
            operation = "/";
        }else if(expression.indexOf(" ^ ") != -1){
            operation = "^";
        } else if(expression.indexOf(" * ") != -1){
            operation = "*";
        } else if(expression.indexOf(" + ") != -1){
            operation = "+";
        } else if(expression.indexOf(" - ") != -1){ //Avoid negative numbers
            operation = "-";
        } else{
            return Double.parseDouble(expression);
        }

        int index = expression.indexOf(operation);
        if(index != -1){
            indexOpen = expression.lastIndexOf(" ", index - 2);
            indexOpen = (indexOpen == -1)?0:indexOpen;
            indexClose = expression.indexOf(" ", index + 2);
            indexClose = (indexClose == -1)?expression.length():indexClose;
            if(indexOpen != -1 && indexClose != -1) {
                Double lhs = Double.parseDouble(expression.substring(indexOpen, index));
                Double rhs = Double.parseDouble(expression.substring(index + 2, indexClose));
                Double result = null;
                switch (operation){
                    case "/":
                        //Prevent divide by 0 exception.
                        if(rhs == 0){
                            return null;
                        }
                        result = lhs / rhs;
                        break;
                    case "^":
                        result = Math.pow(lhs, rhs);
                        break;
                    case "*":
                        result = lhs * rhs;
                        break;
                    case "-":
                        result = lhs - rhs;
                        break;
                    case "+":
                        result = lhs + rhs;
                        break;
                    default:
                        break;
                }
                if(indexClose == expression.length()){
                    expression = expression.substring(0, indexOpen) + " " + result + " " + expression.substring(indexClose);
                }else{
                    expression = expression.substring(0, indexOpen) + " " + result + " " + expression.substring(indexClose + 1);
                }
                return Double.valueOf(df.format(evaluate(expression.trim())));
            }
        }
    }catch(Exception exp){
        exp.printStackTrace();
    }
    return 0.0;
}

public static void main(String args[]){

    Scanner scanner = new Scanner(System.in);
    System.out.print("Enter an Mathematical Expression to Evaluate: ");
    String input = scanner.nextLine();
    System.out.println(evaluate(input));
}

}

我写了算术表达式的eval方法来回答这个问题。它可以做加法、减法、乘法、除法、求幂(使用^符号)，以及一些基本函数，如平方根。它支持使用(…)进行分组，并获得正确的操作符优先级和结合规则。

public static double eval(final String str) {
    return new Object() {
        int pos = -1, ch;
        
        void nextChar() {
            ch = (++pos < str.length()) ? str.charAt(pos) : -1;
        }
        
        boolean eat(int charToEat) {
            while (ch == ' ') nextChar();
            if (ch == charToEat) {
                nextChar();
                return true;
            }
            return false;
        }
        
        double parse() {
            nextChar();
            double x = parseExpression();
            if (pos < str.length()) throw new RuntimeException("Unexpected: " + (char)ch);
            return x;
        }
        
        // Grammar:
        // expression = term | expression `+` term | expression `-` term
        // term = factor | term `*` factor | term `/` factor
        // factor = `+` factor | `-` factor | `(` expression `)` | number
        //        | functionName `(` expression `)` | functionName factor
        //        | factor `^` factor
        
        double parseExpression() {
            double x = parseTerm();
            for (;;) {
                if      (eat('+')) x += parseTerm(); // addition
                else if (eat('-')) x -= parseTerm(); // subtraction
                else return x;
            }
        }
        
        double parseTerm() {
            double x = parseFactor();
            for (;;) {
                if      (eat('*')) x *= parseFactor(); // multiplication
                else if (eat('/')) x /= parseFactor(); // division
                else return x;
            }
        }
        
        double parseFactor() {
            if (eat('+')) return +parseFactor(); // unary plus
            if (eat('-')) return -parseFactor(); // unary minus
            
            double x;
            int startPos = this.pos;
            if (eat('(')) { // parentheses
                x = parseExpression();
                if (!eat(')')) throw new RuntimeException("Missing ')'");
            } else if ((ch >= '0' && ch <= '9') || ch == '.') { // numbers
                while ((ch >= '0' && ch <= '9') || ch == '.') nextChar();
                x = Double.parseDouble(str.substring(startPos, this.pos));
            } else if (ch >= 'a' && ch <= 'z') { // functions
                while (ch >= 'a' && ch <= 'z') nextChar();
                String func = str.substring(startPos, this.pos);
                if (eat('(')) {
                    x = parseExpression();
                    if (!eat(')')) throw new RuntimeException("Missing ')' after argument to " + func);
                } else {
                    x = parseFactor();
                }
                if (func.equals("sqrt")) x = Math.sqrt(x);
                else if (func.equals("sin")) x = Math.sin(Math.toRadians(x));
                else if (func.equals("cos")) x = Math.cos(Math.toRadians(x));
                else if (func.equals("tan")) x = Math.tan(Math.toRadians(x));
                else throw new RuntimeException("Unknown function: " + func);
            } else {
                throw new RuntimeException("Unexpected: " + (char)ch);
            }
            
            if (eat('^')) x = Math.pow(x, parseFactor()); // exponentiation
            
            return x;
        }
    }.parse();
}

例子:

System.out.println(eval("((4 - 2^3 + 1) * -sqrt(3*3+4*4)) / 2"));

输出:7.5(正确)

该解析器是递归下降解析器，因此在内部为其语法中的每个操作符优先级使用单独的解析方法。我故意保持简短，但以下是一些你可能想要扩展的想法:

Variables: The bit of the parser that reads the names for functions can easily be changed to handle custom variables too, by looking up names in a variable table passed to the eval method, such as a Map<String,Double> variables. Separate compilation and evaluation: What if, having added support for variables, you wanted to evaluate the same expression millions of times with changed variables, without parsing it every time? It's possible. First define an interface to use to evaluate the precompiled expression: @FunctionalInterface interface Expression { double eval(); } Now to rework the original "eval" function into a "parse" function, change all the methods that return doubles, so instead they return an instance of that interface. Java 8's lambda syntax works well for this. Example of one of the changed methods: Expression parseExpression() { Expression x = parseTerm(); for (;;) { if (eat('+')) { // addition Expression a = x, b = parseTerm(); x = (() -> a.eval() + b.eval()); } else if (eat('-')) { // subtraction Expression a = x, b = parseTerm(); x = (() -> a.eval() - b.eval()); } else { return x; } } } That builds a recursive tree of Expression objects representing the compiled expression (an abstract syntax tree). Then you can compile it once and evaluate it repeatedly with different values: public static void main(String[] args) { Map<String,Double> variables = new HashMap<>(); Expression exp = parse("x^2 - x + 2", variables); for (double x = -20; x <= +20; x++) { variables.put("x", x); System.out.println(x + " => " + exp.eval()); } } Different datatypes: Instead of double, you could change the evaluator to use something more powerful like BigDecimal, or a class that implements complex numbers, or rational numbers (fractions). You could even use Object, allowing some mix of datatypes in expressions, just like a real programming language. :)

这个答案中的所有代码都已发布到公共领域。玩得开心!

我想无论你用什么方法做这个都会涉及到很多条件命题。但是对于单个操作，比如在你的例子中，你可以将它限制为4个if语句

String math = "1+4";

if (math.split("+").length == 2) {
    //do calculation
} else if (math.split("-").length == 2) {
    //do calculation
} ...

当你想要处理像“4+5*6”这样的多个操作时，它会变得更加复杂。

如果你试图构建一个计算器，那么我建议分别传递计算的每个部分(每个数字或运算符)，而不是作为一个单一的字符串。