看来应该由JEP来做这项工作

我想无论你用什么方法做这个都会涉及到很多条件命题。但是对于单个操作，比如在你的例子中，你可以将它限制为4个if语句

String math = "1+4";

if (math.split("+").length == 2) {
    //do calculation
} else if (math.split("-").length == 2) {
    //do calculation
} ...

当你想要处理像“4+5*6”这样的多个操作时，它会变得更加复杂。

如果你试图构建一个计算器，那么我建议分别传递计算的每个部分(每个数字或运算符)，而不是作为一个单一的字符串。

你也可以试试BeanShell解释器:

Interpreter interpreter = new Interpreter();
interpreter.eval("result = (7+21*6)/(32-27)");
System.out.println(interpreter.get("result"));

这样怎么样:

String st = "10+3";
int result;
for(int i=0;i<st.length();i++)
{
  if(st.charAt(i)=='+')
  {
    result=Integer.parseInt(st.substring(0, i))+Integer.parseInt(st.substring(i+1, st.length()));
    System.out.print(result);
  }         
}

并相应地对其他数学运算符做类似的事情。

package ExpressionCalculator.expressioncalculator;

import java.text.DecimalFormat;
import java.util.Scanner;

public class ExpressionCalculator {

private static String addSpaces(String exp){

    //Add space padding to operands.
    //https://regex101.com/r/sJ9gM7/73
    exp = exp.replaceAll("(?<=[0-9()])[\\/]", " / ");
    exp = exp.replaceAll("(?<=[0-9()])[\\^]", " ^ ");
    exp = exp.replaceAll("(?<=[0-9()])[\\*]", " * ");
    exp = exp.replaceAll("(?<=[0-9()])[+]", " + "); 
    exp = exp.replaceAll("(?<=[0-9()])[-]", " - ");

    //Keep replacing double spaces with single spaces until your string is properly formatted
    /*while(exp.indexOf("  ") != -1){
        exp = exp.replace("  ", " ");
     }*/
    exp = exp.replaceAll(" {2,}", " ");

       return exp;
}

public static Double evaluate(String expr){

    DecimalFormat df = new DecimalFormat("#.####");

    //Format the expression properly before performing operations
    String expression = addSpaces(expr);

    try {
        //We will evaluate using rule BDMAS, i.e. brackets, division, power, multiplication, addition and
        //subtraction will be processed in following order
        int indexClose = expression.indexOf(")");
        int indexOpen = -1;
        if (indexClose != -1) {
            String substring = expression.substring(0, indexClose);
            indexOpen = substring.lastIndexOf("(");
            substring = substring.substring(indexOpen + 1).trim();
            if(indexOpen != -1 && indexClose != -1) {
                Double result = evaluate(substring);
                expression = expression.substring(0, indexOpen).trim() + " " + result + " " + expression.substring(indexClose + 1).trim();
                return evaluate(expression.trim());
            }
        }

        String operation = "";
        if(expression.indexOf(" / ") != -1){
            operation = "/";
        }else if(expression.indexOf(" ^ ") != -1){
            operation = "^";
        } else if(expression.indexOf(" * ") != -1){
            operation = "*";
        } else if(expression.indexOf(" + ") != -1){
            operation = "+";
        } else if(expression.indexOf(" - ") != -1){ //Avoid negative numbers
            operation = "-";
        } else{
            return Double.parseDouble(expression);
        }

        int index = expression.indexOf(operation);
        if(index != -1){
            indexOpen = expression.lastIndexOf(" ", index - 2);
            indexOpen = (indexOpen == -1)?0:indexOpen;
            indexClose = expression.indexOf(" ", index + 2);
            indexClose = (indexClose == -1)?expression.length():indexClose;
            if(indexOpen != -1 && indexClose != -1) {
                Double lhs = Double.parseDouble(expression.substring(indexOpen, index));
                Double rhs = Double.parseDouble(expression.substring(index + 2, indexClose));
                Double result = null;
                switch (operation){
                    case "/":
                        //Prevent divide by 0 exception.
                        if(rhs == 0){
                            return null;
                        }
                        result = lhs / rhs;
                        break;
                    case "^":
                        result = Math.pow(lhs, rhs);
                        break;
                    case "*":
                        result = lhs * rhs;
                        break;
                    case "-":
                        result = lhs - rhs;
                        break;
                    case "+":
                        result = lhs + rhs;
                        break;
                    default:
                        break;
                }
                if(indexClose == expression.length()){
                    expression = expression.substring(0, indexOpen) + " " + result + " " + expression.substring(indexClose);
                }else{
                    expression = expression.substring(0, indexOpen) + " " + result + " " + expression.substring(indexClose + 1);
                }
                return Double.valueOf(df.format(evaluate(expression.trim())));
            }
        }
    }catch(Exception exp){
        exp.printStackTrace();
    }
    return 0.0;
}

public static void main(String args[]){

    Scanner scanner = new Scanner(System.in);
    System.out.print("Enter an Mathematical Expression to Evaluate: ");
    String input = scanner.nextLine();
    System.out.println(evaluate(input));
}

}

解决这个问题的正确方法是使用词法分析器和解析器。您可以自己编写这些页面的简单版本，或者这些页面还包含指向Java词法分析器和解析器的链接。

创建递归下降解析器是非常好的学习练习。