此解决方案可用于获取每个分区的TOP N最近行(在本例中，WHERE语句中的N为1,partition为doc_id):

SELECT T.doc_id, T.status, T.date_created FROM 
(
    SELECT a.*, ROW_NUMBER() OVER (PARTITION BY doc_id ORDER BY date_created DESC) AS rnk FROM doc a
) T
WHERE T.rnk = 1;

I've done some timings over the various recommendations here, and the results really depend on the size of the table involved, but the most consistent solution is using the CROSS APPLY These tests were run against SQL Server 2008-R2, using a table with 6,500 records, and another (identical schema) with 137 million records. The columns being queried are part of the primary key on the table, and the table width is very small (about 30 bytes). The times are reported by SQL Server from the actual execution plan.

Query                                  Time for 6500 (ms)    Time for 137M(ms)

CROSS APPLY                                    17.9                17.9
SELECT WHERE col = (SELECT MAX(COL)…)           6.6               854.4
DENSE_RANK() OVER PARTITION                     6.6               907.1

我认为真正令人惊讶的是，无论涉及的行数是多少，CROSS APPLY的时间都是如此一致。

SELECT o.*
FROM `DocumentStatusLogs` o                   
  LEFT JOIN `DocumentStatusLogs` b                   
  ON o.DocumentID = b.DocumentID AND o.DateCreated < b.DateCreated
 WHERE b.DocumentID is NULL ;

如果您只想按DateCreated返回最近的文档顺序，它将只按documententid返回前1个文档

这是一个相当老的话题，但我想我要发表我的意见，就像公认的答案对我来说并不是特别有效一样。我在一个大型数据集上尝试了gbn的解决方案，发现它非常慢(在SQL Server 2012中500多万条记录上>45秒)。看一下执行计划，很明显问题在于它需要一个SORT操作，这会大大降低速度。

下面是我从实体框架中提取的一个替代方案，它不需要SORT操作，只进行非聚集索引搜索。这将在前面提到的记录集中将执行时间减少到< 2秒。

SELECT 
[Limit1].[DocumentID] AS [DocumentID], 
[Limit1].[Status] AS [Status], 
[Limit1].[DateCreated] AS [DateCreated]
FROM   (SELECT DISTINCT [Extent1].[DocumentID] AS [DocumentID] FROM [dbo].[DocumentStatusLogs] AS [Extent1]) AS [Distinct1]
OUTER APPLY  (SELECT TOP (1) [Project2].[ID] AS [ID], [Project2].[DocumentID] AS [DocumentID], [Project2].[Status] AS [Status], [Project2].[DateCreated] AS [DateCreated]
    FROM (SELECT 
        [Extent2].[ID] AS [ID], 
        [Extent2].[DocumentID] AS [DocumentID], 
        [Extent2].[Status] AS [Status], 
        [Extent2].[DateCreated] AS [DateCreated]
        FROM [dbo].[DocumentStatusLogs] AS [Extent2]
        WHERE ([Distinct1].[DocumentID] = [Extent2].[DocumentID])
    )  AS [Project2]
    ORDER BY [Project2].[ID] DESC) AS [Limit1]

Now I'm assuming something that isn't entirely specified in the original question, but if your table design is such that your ID column is an auto-increment ID, and the DateCreated is set to the current date with each insert, then even without running with my query above you could actually get a sizable performance boost to gbn's solution (about half the execution time) just from ordering on ID instead of ordering on DateCreated as this will provide an identical sort order and it's a faster sort.

我知道这是一个旧的线程，但TOP 1与TIES解决方案是相当不错的，可能有助于阅读一些解决方案。

select top 1 with ties
   DocumentID
  ,Status
  ,DateCreated
from DocumentStatusLogs
order by row_number() over (partition by DocumentID order by DateCreated desc)

select top 1 with ties子句告诉SQL Server要返回每个组的第一行。但是SQL Server如何知道如何对数据进行分组呢?这就是按row_number()的顺序除以(按documententid分区的顺序除以DateCreated desc的顺序。分区后的列定义了SQL Server如何对数据进行分组。在每个组中，行将根据列的顺序进行排序。排序之后，查询中将返回每个组中的第一行。

关于TOP子句的更多信息可以在这里找到。

试试这个:

SELECT [DocumentID]
    ,[tmpRez].value('/x[2]', 'varchar(20)') AS [Status]
    ,[tmpRez].value('/x[3]', 'datetime') AS [DateCreated]
FROM (
    SELECT [DocumentID]
        ,cast('<x>' + max(cast([ID] AS VARCHAR(10)) + '</x><x>' + [Status] + '</x><x>' + cast([DateCreated] AS VARCHAR(20))) + '</x>' AS XML) AS [tmpRez]
    FROM DocumentStatusLogs
    GROUP BY DocumentID
    ) AS [tmpQry]