我有一个表,我想获得每组的最新条目。下面是表格:
DocumentStatusLogs表
|ID| DocumentID | Status | DateCreated |
| 2| 1 | S1 | 7/29/2011 |
| 3| 1 | S2 | 7/30/2011 |
| 6| 1 | S1 | 8/02/2011 |
| 1| 2 | S1 | 7/28/2011 |
| 4| 2 | S2 | 7/30/2011 |
| 5| 2 | S3 | 8/01/2011 |
| 6| 3 | S1 | 8/02/2011 |
该表将按documententid分组,并按DateCreated降序排序。对于每个documententid,我希望获得最新的状态。
我的首选输出:
| DocumentID | Status | DateCreated |
| 1 | S1 | 8/02/2011 |
| 2 | S3 | 8/01/2011 |
| 3 | S1 | 8/02/2011 |
Is there any aggregate function to get only the top from each group? See pseudo-code GetOnlyTheTop below:
SELECT
DocumentID,
GetOnlyTheTop(Status),
GetOnlyTheTop(DateCreated)
FROM DocumentStatusLogs
GROUP BY DocumentID
ORDER BY DateCreated DESC
If such function doesn't exist, is there any way I can achieve the output I want?
Or at the first place, could this be caused by unnormalized database? I'm thinking, since what I'm looking for is just one row, should that status also be located in the parent table?
更多信息请参见父表:
当前文档表
| DocumentID | Title | Content | DateCreated |
| 1 | TitleA | ... | ... |
| 2 | TitleB | ... | ... |
| 3 | TitleC | ... | ... |
父表应该是这样的,以便我可以轻松地访问它的状态吗?
| DocumentID | Title | Content | DateCreated | CurrentStatus |
| 1 | TitleA | ... | ... | s1 |
| 2 | TitleB | ... | ... | s3 |
| 3 | TitleC | ... | ... | s1 |
更新
我刚刚学会了如何使用“apply”,它可以更容易地解决这类问题。
在你想避免使用row_count()的场景中,你也可以使用左连接:
select ds.DocumentID, ds.Status, ds.DateCreated
from DocumentStatusLogs ds
left join DocumentStatusLogs filter
ON ds.DocumentID = filter.DocumentID
-- Match any row that has another row that was created after it.
AND ds.DateCreated < filter.DateCreated
-- then filter out any rows that matched
where filter.DocumentID is null
对于示例模式,你也可以使用"not in subquery",它通常编译到与左连接相同的输出:
select ds.DocumentID, ds.Status, ds.DateCreated
from DocumentStatusLogs ds
WHERE ds.ID NOT IN (
SELECT filter.ID
FROM DocumentStatusLogs filter
WHERE ds.DocumentID = filter.DocumentID
AND ds.DateCreated < filter.DateCreated)
注意,如果表没有至少一个单列唯一键/约束/索引(在本例中是主键“Id”),那么子查询模式将无法工作。
这两个查询往往比row_count()查询(由query Analyzer衡量)更“昂贵”。但是,您可能会遇到它们更快地返回结果或启用其他优化的情况。
这是一个相当老的话题,但我想我要发表我的意见,就像公认的答案对我来说并不是特别有效一样。我在一个大型数据集上尝试了gbn的解决方案,发现它非常慢(在SQL Server 2012中500多万条记录上>45秒)。看一下执行计划,很明显问题在于它需要一个SORT操作,这会大大降低速度。
下面是我从实体框架中提取的一个替代方案,它不需要SORT操作,只进行非聚集索引搜索。这将在前面提到的记录集中将执行时间减少到< 2秒。
SELECT
[Limit1].[DocumentID] AS [DocumentID],
[Limit1].[Status] AS [Status],
[Limit1].[DateCreated] AS [DateCreated]
FROM (SELECT DISTINCT [Extent1].[DocumentID] AS [DocumentID] FROM [dbo].[DocumentStatusLogs] AS [Extent1]) AS [Distinct1]
OUTER APPLY (SELECT TOP (1) [Project2].[ID] AS [ID], [Project2].[DocumentID] AS [DocumentID], [Project2].[Status] AS [Status], [Project2].[DateCreated] AS [DateCreated]
FROM (SELECT
[Extent2].[ID] AS [ID],
[Extent2].[DocumentID] AS [DocumentID],
[Extent2].[Status] AS [Status],
[Extent2].[DateCreated] AS [DateCreated]
FROM [dbo].[DocumentStatusLogs] AS [Extent2]
WHERE ([Distinct1].[DocumentID] = [Extent2].[DocumentID])
) AS [Project2]
ORDER BY [Project2].[ID] DESC) AS [Limit1]
Now I'm assuming something that isn't entirely specified in the original question, but if your table design is such that your ID column is an auto-increment ID, and the DateCreated is set to the current date with each insert, then even without running with my query above you could actually get a sizable performance boost to gbn's solution (about half the execution time) just from ordering on ID instead of ordering on DateCreated as this will provide an identical sort order and it's a faster sort.
一些数据库引擎*开始支持允许过滤窗口函数结果的qualifier子句(接受的答案使用该子句)。
所以公认的答案可以变成
SELECT *, ROW_NUMBER() OVER (PARTITION BY DocumentID ORDER BY DateCreated DESC) AS rn
FROM DocumentStatusLogs
QUALIFY rn = 1
查看这篇文章以获得更深入的解释:https://jrandrews.net/the-joy-of-qualify
您可以使用此工具查看哪个数据库支持此子句:https://www.jooq.org/translate/
当目标方言不支持qualifier子句时,可以选择转换它。
*Teradata, BigQuery, H2, Snowflake…