我在一个文件中有一个大的位图(比如3888x2592)。现在,我想将位图大小调整为800x533,并将其保存到另一个文件中。 我通常通过调用bitmap来缩放位图。createBitmap方法,但它需要一个源位图作为第一个参数,我不能提供,因为加载原始图像到位图对象当然会超过内存(例如,见这里)。

我也不能读取位图,例如,BitmapFactory.decodeFile(文件,选项),提供BitmapFactory.Options。inSampleSize,因为我想把它调整到精确的宽度和高度。使用inSampleSize将位图大小调整为972x648(如果我使用inSampleSize=4)或778x518(如果我使用inSampleSize=5,这甚至不是2的幂)。

我还希望避免在第一步中使用inSampleSize读取图像,例如,在第一步中使用972x648,然后在第二步中将其大小调整为800x533,因为与直接调整原始图像的大小相比,质量会较差。

总结一下我的问题: 是否有一种方法来读取一个10MP或更多的大图像文件,并将其保存到一个新的图像文件,调整到一个特定的新宽度和高度,而不得到OutOfMemory异常?

我还尝试了BitmapFactory.decodeFile(文件,选项)和设置选项。out theight and Options。outidth值手动为800和533,但它不是这样工作的。


当前回答

这可能对其他研究这个问题的人有用。我重写了Justin的代码,以允许该方法也接收所需的目标大小对象。这在使用Canvas时工作得非常好。所有的功劳都应该归于JUSTIN的出色的初始代码。

    private Bitmap getBitmap(int path, Canvas canvas) {

        Resources resource = null;
        try {
            final int IMAGE_MAX_SIZE = 1200000; // 1.2MP
            resource = getResources();

            // Decode image size
            BitmapFactory.Options options = new BitmapFactory.Options();
            options.inJustDecodeBounds = true;
            BitmapFactory.decodeResource(resource, path, options);

            int scale = 1;
            while ((options.outWidth * options.outHeight) * (1 / Math.pow(scale, 2)) > 
                  IMAGE_MAX_SIZE) {
               scale++;
            }
            Log.d("TAG", "scale = " + scale + ", orig-width: " + options.outWidth + ", orig-height: " + options.outHeight);

            Bitmap pic = null;
            if (scale > 1) {
                scale--;
                // scale to max possible inSampleSize that still yields an image
                // larger than target
                options = new BitmapFactory.Options();
                options.inSampleSize = scale;
                pic = BitmapFactory.decodeResource(resource, path, options);

                // resize to desired dimensions
                int height = canvas.getHeight();
                int width = canvas.getWidth();
                Log.d("TAG", "1th scale operation dimenions - width: " + width + ", height: " + height);

                double y = Math.sqrt(IMAGE_MAX_SIZE
                        / (((double) width) / height));
                double x = (y / height) * width;

                Bitmap scaledBitmap = Bitmap.createScaledBitmap(pic, (int) x, (int) y, true);
                pic.recycle();
                pic = scaledBitmap;

                System.gc();
            } else {
                pic = BitmapFactory.decodeResource(resource, path);
            }

            Log.d("TAG", "bitmap size - width: " +pic.getWidth() + ", height: " + pic.getHeight());
            return pic;
        } catch (Exception e) {
            Log.e("TAG", e.getMessage(),e);
            return null;
        }
    }

Justin的代码非常有效地减少了使用大型位图的开销。

其他回答

贾斯汀的答案翻译成代码(对我来说很完美):

private Bitmap getBitmap(String path) {

Uri uri = getImageUri(path);
InputStream in = null;
try {
    final int IMAGE_MAX_SIZE = 1200000; // 1.2MP
    in = mContentResolver.openInputStream(uri);

    // Decode image size
    BitmapFactory.Options options = new BitmapFactory.Options();
    options.inJustDecodeBounds = true;
    BitmapFactory.decodeStream(in, null, options);
    in.close();



    int scale = 1;
    while ((options.outWidth * options.outHeight) * (1 / Math.pow(scale, 2)) > 
          IMAGE_MAX_SIZE) {
       scale++;
    }
    Log.d(TAG, "scale = " + scale + ", orig-width: " + options.outWidth + ", 
       orig-height: " + options.outHeight);

    Bitmap resultBitmap = null;
    in = mContentResolver.openInputStream(uri);
    if (scale > 1) {
        scale--;
        // scale to max possible inSampleSize that still yields an image
        // larger than target
        options = new BitmapFactory.Options();
        options.inSampleSize = scale;
        resultBitmap = BitmapFactory.decodeStream(in, null, options);

        // resize to desired dimensions
        int height = resultBitmap.getHeight();
        int width = resultBitmap.getWidth();
        Log.d(TAG, "1th scale operation dimenions - width: " + width + ",
           height: " + height);

        double y = Math.sqrt(IMAGE_MAX_SIZE
                / (((double) width) / height));
        double x = (y / height) * width;

        Bitmap scaledBitmap = Bitmap.createScaledBitmap(resultBitmap, (int) x, 
           (int) y, true);
        resultBitmap.recycle();
        resultBitmap = scaledBitmap;

        System.gc();
    } else {
        resultBitmap = BitmapFactory.decodeStream(in);
    }
    in.close();

    Log.d(TAG, "bitmap size - width: " +resultBitmap.getWidth() + ", height: " + 
       resultBitmap.getHeight());
    return resultBitmap;
} catch (IOException e) {
    Log.e(TAG, e.getMessage(),e);
    return null;
}

我使用了这样的代码:

  String filePath=Environment.getExternalStorageDirectory()+"/test_image.jpg";
  BitmapFactory.Options options=new BitmapFactory.Options();
  InputStream is=new FileInputStream(filePath);
  BitmapFactory.decodeStream(is, null, options);
  is.close();
  is=new FileInputStream(filePath);
  // here w and h are the desired width and height
  options.inSampleSize=Math.max(options.outWidth/460, options.outHeight/288); //Max 460 x 288 is my desired...
  // bmp is the resized bitmap
  Bitmap bmp=BitmapFactory.decodeStream(is, null, options);
  is.close();
  Log.d(Constants.TAG, "Scaled bitmap bytes, "+bmp.getRowBytes()+", width:"+bmp.getWidth()+", height:"+bmp.getHeight());

我试过原始图像是1230 x 1230,得到的位图是330 x 330。 如果尝试2590 x 3849,我将得到OutOfMemoryError。

我跟踪了它,它仍然抛出OutOfMemoryError在行"BitmapFactory.decodeStream(is, null, options);",如果原始位图太大…

这可能对其他研究这个问题的人有用。我重写了Justin的代码,以允许该方法也接收所需的目标大小对象。这在使用Canvas时工作得非常好。所有的功劳都应该归于JUSTIN的出色的初始代码。

    private Bitmap getBitmap(int path, Canvas canvas) {

        Resources resource = null;
        try {
            final int IMAGE_MAX_SIZE = 1200000; // 1.2MP
            resource = getResources();

            // Decode image size
            BitmapFactory.Options options = new BitmapFactory.Options();
            options.inJustDecodeBounds = true;
            BitmapFactory.decodeResource(resource, path, options);

            int scale = 1;
            while ((options.outWidth * options.outHeight) * (1 / Math.pow(scale, 2)) > 
                  IMAGE_MAX_SIZE) {
               scale++;
            }
            Log.d("TAG", "scale = " + scale + ", orig-width: " + options.outWidth + ", orig-height: " + options.outHeight);

            Bitmap pic = null;
            if (scale > 1) {
                scale--;
                // scale to max possible inSampleSize that still yields an image
                // larger than target
                options = new BitmapFactory.Options();
                options.inSampleSize = scale;
                pic = BitmapFactory.decodeResource(resource, path, options);

                // resize to desired dimensions
                int height = canvas.getHeight();
                int width = canvas.getWidth();
                Log.d("TAG", "1th scale operation dimenions - width: " + width + ", height: " + height);

                double y = Math.sqrt(IMAGE_MAX_SIZE
                        / (((double) width) / height));
                double x = (y / height) * width;

                Bitmap scaledBitmap = Bitmap.createScaledBitmap(pic, (int) x, (int) y, true);
                pic.recycle();
                pic = scaledBitmap;

                System.gc();
            } else {
                pic = BitmapFactory.decodeResource(resource, path);
            }

            Log.d("TAG", "bitmap size - width: " +pic.getWidth() + ", height: " + pic.getHeight());
            return pic;
        } catch (Exception e) {
            Log.e("TAG", e.getMessage(),e);
            return null;
        }
    }

Justin的代码非常有效地减少了使用大型位图的开销。

我使用Integer。numberOfLeadingZeros计算最佳样本量,性能更好。

kotlin完整代码:

@Throws(IOException::class)
fun File.decodeBitmap(options: BitmapFactory.Options): Bitmap? {
    return inputStream().use {
        BitmapFactory.decodeStream(it, null, options)
    }
}

@Throws(IOException::class)
fun File.decodeBitmapAtLeast(
        @androidx.annotation.IntRange(from = 1) width: Int,
        @androidx.annotation.IntRange(from = 1) height: Int
): Bitmap? {
    val options = BitmapFactory.Options()

    options.inJustDecodeBounds = true
    decodeBitmap(options)

    val ow = options.outWidth
    val oh = options.outHeight

    if (ow == -1 || oh == -1) return null

    val w = ow / width
    val h = oh / height

    if (w > 1 && h > 1) {
        val p = 31 - maxOf(Integer.numberOfLeadingZeros(w), Integer.numberOfLeadingZeros(h))
        options.inSampleSize = 1 shl maxOf(0, p)
    }
    options.inJustDecodeBounds = false
    return decodeBitmap(options)
}

这对我很管用。该函数获取sd卡上文件的路径,并返回可显示的最大大小的位图。 代码是从Ofir与一些变化,如图像文件在sd代替资源和witdth和高度是从显示对象。

private Bitmap makeBitmap(String path) {

    try {
        final int IMAGE_MAX_SIZE = 1200000; // 1.2MP
        //resource = getResources();

        // Decode image size
        BitmapFactory.Options options = new BitmapFactory.Options();
        options.inJustDecodeBounds = true;
        BitmapFactory.decodeFile(path, options);

        int scale = 1;
        while ((options.outWidth * options.outHeight) * (1 / Math.pow(scale, 2)) >
                IMAGE_MAX_SIZE) {
            scale++;
        }
        Log.d("TAG", "scale = " + scale + ", orig-width: " + options.outWidth + ", orig-height: " + options.outHeight);

        Bitmap pic = null;
        if (scale > 1) {
            scale--;
            // scale to max possible inSampleSize that still yields an image
            // larger than target
            options = new BitmapFactory.Options();
            options.inSampleSize = scale;
            pic = BitmapFactory.decodeFile(path, options);

            // resize to desired dimensions

            Display display = getWindowManager().getDefaultDisplay();
            Point size = new Point();
            display.getSize(size);
            int width = size.y;
            int height = size.x;

            //int height = imageView.getHeight();
            //int width = imageView.getWidth();
            Log.d("TAG", "1th scale operation dimenions - width: " + width + ", height: " + height);

            double y = Math.sqrt(IMAGE_MAX_SIZE
                    / (((double) width) / height));
            double x = (y / height) * width;

            Bitmap scaledBitmap = Bitmap.createScaledBitmap(pic, (int) x, (int) y, true);
            pic.recycle();
            pic = scaledBitmap;

            System.gc();
        } else {
            pic = BitmapFactory.decodeFile(path);
        }

        Log.d("TAG", "bitmap size - width: " +pic.getWidth() + ", height: " + pic.getHeight());
        return pic;

    } catch (Exception e) {
        Log.e("TAG", e.getMessage(),e);
        return null;
    }

}