我使用了这样的代码:

  String filePath=Environment.getExternalStorageDirectory()+"/test_image.jpg";
  BitmapFactory.Options options=new BitmapFactory.Options();
  InputStream is=new FileInputStream(filePath);
  BitmapFactory.decodeStream(is, null, options);
  is.close();
  is=new FileInputStream(filePath);
  // here w and h are the desired width and height
  options.inSampleSize=Math.max(options.outWidth/460, options.outHeight/288); //Max 460 x 288 is my desired...
  // bmp is the resized bitmap
  Bitmap bmp=BitmapFactory.decodeStream(is, null, options);
  is.close();
  Log.d(Constants.TAG, "Scaled bitmap bytes, "+bmp.getRowBytes()+", width:"+bmp.getWidth()+", height:"+bmp.getHeight());

我试过原始图像是1230 x 1230，得到的位图是330 x 330。 如果尝试2590 x 3849，我将得到OutOfMemoryError。

我跟踪了它，它仍然抛出OutOfMemoryError在行"BitmapFactory.decodeStream(is, null, options);"，如果原始位图太大…

这是“Mojo Risin”和“Ofir”解决方案的“结合”。这将给你一个按比例调整图像的最大宽度和最大高度的边界。

它只读取元数据以获得原始大小(选项。 它使用粗略的调整大小来节省内存(itmap.createScaledBitmap) 它使用了基于之前创建的粗糙Bitamp精确调整大小的图像。

对我来说，它在500万像素以下的图像上表现良好。

try
{
    int inWidth = 0;
    int inHeight = 0;

    InputStream in = new FileInputStream(pathOfInputImage);

    // decode image size (decode metadata only, not the whole image)
    BitmapFactory.Options options = new BitmapFactory.Options();
    options.inJustDecodeBounds = true;
    BitmapFactory.decodeStream(in, null, options);
    in.close();
    in = null;

    // save width and height
    inWidth = options.outWidth;
    inHeight = options.outHeight;

    // decode full image pre-resized
    in = new FileInputStream(pathOfInputImage);
    options = new BitmapFactory.Options();
    // calc rought re-size (this is no exact resize)
    options.inSampleSize = Math.max(inWidth/dstWidth, inHeight/dstHeight);
    // decode full image
    Bitmap roughBitmap = BitmapFactory.decodeStream(in, null, options);

    // calc exact destination size
    Matrix m = new Matrix();
    RectF inRect = new RectF(0, 0, roughBitmap.getWidth(), roughBitmap.getHeight());
    RectF outRect = new RectF(0, 0, dstWidth, dstHeight);
    m.setRectToRect(inRect, outRect, Matrix.ScaleToFit.CENTER);
    float[] values = new float[9];
    m.getValues(values);

    // resize bitmap
    Bitmap resizedBitmap = Bitmap.createScaledBitmap(roughBitmap, (int) (roughBitmap.getWidth() * values[0]), (int) (roughBitmap.getHeight() * values[4]), true);

    // save image
    try
    {
        FileOutputStream out = new FileOutputStream(pathOfOutputImage);
        resizedBitmap.compress(Bitmap.CompressFormat.JPEG, 80, out);
    }
    catch (Exception e)
    {
        Log.e("Image", e.getMessage(), e);
    }
}
catch (IOException e)
{
    Log.e("Image", e.getMessage(), e);
}

如果你想一步调整大小你可以加载整个位图如果 android:largeHeap = true，但正如你所看到的，这是不可取的。

From docs: android:largeHeap Whether your application's processes should be created with a large Dalvik heap. This applies to all processes created for the application. It only applies to the first application loaded into a process; if you're using a shared user ID to allow multiple applications to use a process, they all must use this option consistently or they will have unpredictable results. Most apps should not need this and should instead focus on reducing their overall memory usage for improved performance. Enabling this also does not guarantee a fixed increase in available memory, because some devices are constrained by their total available memory.

我不知道我的解决方案是否是最佳实践，但我通过使用inDensity和inTargetDensity选项实现了加载我所需缩放的位图。当不加载可绘制资源时，inDensity初始值为0，因此此方法用于加载非资源图像。

变量imageUri, maxImageSideLength和context是我的方法的参数。为了清晰起见，我只发布了方法实现，没有包装AsyncTask。

            ContentResolver resolver = context.getContentResolver();
            InputStream is;
            try {
                is = resolver.openInputStream(imageUri);
            } catch (FileNotFoundException e) {
                Log.e(TAG, "Image not found.", e);
                return null;
            }
            Options opts = new Options();
            opts.inJustDecodeBounds = true;
            BitmapFactory.decodeStream(is, null, opts);

            // scale the image
            float maxSideLength = maxImageSideLength;
            float scaleFactor = Math.min(maxSideLength / opts.outWidth, maxSideLength / opts.outHeight);
            // do not upscale!
            if (scaleFactor < 1) {
                opts.inDensity = 10000;
                opts.inTargetDensity = (int) ((float) opts.inDensity * scaleFactor);
            }
            opts.inJustDecodeBounds = false;

            try {
                is.close();
            } catch (IOException e) {
                // ignore
            }
            try {
                is = resolver.openInputStream(imageUri);
            } catch (FileNotFoundException e) {
                Log.e(TAG, "Image not found.", e);
                return null;
            }
            Bitmap bitmap = BitmapFactory.decodeStream(is, null, opts);
            try {
                is.close();
            } catch (IOException e) {
                // ignore
            }

            return bitmap;

当我有大位图，我想解码他们调整大小我使用以下

BitmapFactory.Options options = new BitmapFactory.Options();
InputStream is = null;
is = new FileInputStream(path_to_file);
BitmapFactory.decodeStream(is,null,options);
is.close();
is = new FileInputStream(path_to_file);
// here w and h are the desired width and height
options.inSampleSize = Math.max(options.outWidth/w, options.outHeight/h);
// bitmap is the resized bitmap
Bitmap bitmap = BitmapFactory.decodeStream(is,null,options);

不。我希望有人能纠正我，但我接受了你作为妥协尝试的加载/调整大小的方法。

下面是浏览网页的步骤:

计算最大可能的在samplesize仍然产生比你的目标更大的图像。 使用BitmapFactory.decodeFile(file, options)加载图像，传入samplesize作为选项。 使用Bitmap.createScaledBitmap()将大小调整到所需的尺寸。