好问题。我来这里是希望能找到一些简单的方法来加快矢量测试的速度。结果跟我想象的不太一样!

优化有帮助，但这还不够。通过优化，我仍然看到UseArray和UseVector之间的2X性能差异。有趣的是，UseVector明显比没有优化的UseVectorPushBack慢。

# g++ -Wall -Wextra -pedantic -o vector vector.cpp
# ./vector
UseArray completed in 20.68 seconds
UseVector completed in 120.509 seconds
UseVectorPushBack completed in 37.654 seconds
The whole thing completed in 178.845 seconds
# g++ -Wall -Wextra -pedantic -O3 -o vector vector.cpp
# ./vector
UseArray completed in 3.09 seconds
UseVector completed in 6.09 seconds
UseVectorPushBack completed in 9.847 seconds
The whole thing completed in 19.028 seconds

想法1 -使用new[]代替malloc

我尝试在UseArray中将malloc()更改为new[]，以便构造对象。从单个字段分配到分配一个Pixel实例。哦，重命名内循环变量为j。

void UseArray()
{
    TestTimer t("UseArray");

    for(int i = 0; i < 1000; ++i)
    {   
        int dimension = 999;

        // Same speed as malloc().
        Pixel * pixels = new Pixel[dimension * dimension];

        for(int j = 0 ; j < dimension * dimension; ++j)
            pixels[j] = Pixel(255, 0, 0);

        delete[] pixels;
    }
}

令人惊讶的是(对我来说)，这些变化没有任何不同。甚至没有更改为new[]，这将默认构造所有的像素。看起来gcc在使用new[]时可以优化默认构造函数调用，但在使用vector时就不行。

想法#2 -删除重复的操作符[]调用

我还尝试摆脱三重运算符[]查找，并缓存对像素[j]的引用。这实际上降低了UseVector的速度!哦。

for(int j = 0; j < dimension * dimension; ++j)
{
    // Slower than accessing pixels[j] three times.
    Pixel &pixel = pixels[j];
    pixel.r = 255;
    pixel.g = 0;
    pixel.b = 0;
}

# ./vector 
UseArray completed in 3.226 seconds
UseVector completed in 7.54 seconds
UseVectorPushBack completed in 9.859 seconds
The whole thing completed in 20.626 seconds

想法#3 -删除构造函数

如果完全删除构造函数呢?然后，也许gcc可以在创建向量时优化所有对象的结构。如果我们把像素改为:

struct Pixel
{
    unsigned char r, g, b;
};

结果:大约快10%。还是比数组慢。嗯。

# ./vector 
UseArray completed in 3.239 seconds
UseVector completed in 5.567 seconds

想法4 -使用迭代器而不是循环索引

如何使用vector<Pixel>::iterator代替循环索引?

for (std::vector<Pixel>::iterator j = pixels.begin(); j != pixels.end(); ++j)
{
    j->r = 255;
    j->g = 0;
    j->b = 0;
}

结果:

# ./vector 
UseArray completed in 3.264 seconds
UseVector completed in 5.443 seconds

没有什么不同。至少没有变慢。我认为这将具有类似于#2的性能，其中我使用了Pixel&引用。

结论

即使一些聪明的cookie找到了如何使vector循环和数组循环一样快的方法，这也不能说明std::vector的默认行为。编译器足够聪明，可以优化所有c++特性，并使STL容器像原始数组一样快。

底线是，当使用std::vector时，编译器无法优化掉无操作的默认构造函数调用。如果你使用普通的new[]，它就能很好地优化它们。但不是std::vector。即使你可以重写你的代码，以消除构造函数调用，在这里的咒语:“编译器比你聪明。STL和普通c一样快，不用担心。”

GNU's STL (and others), given vector<T>(n), default constructs a prototypal object T() - the compiler will optimise away the empty constructor - but then a copy of whatever garbage happened to be in the memory addresses now reserved for the object is taken by the STL's __uninitialized_fill_n_aux, which loops populating copies of that object as the default values in the vector. So, "my" STL is not looping constructing, but constructing then loop/copying. It's counter intuitive, but I should have remembered as I commented on a recent stackoverflow question about this very point: the construct/copy can be more efficient for reference counted objects etc..

So:

vector<T> x(n);

or

vector<T> x;
x.resize(n);

是-在许多STL实现中-类似于:

T temp;
for (int i = 0; i < n; ++i)
    x[i] = temp;

The issue being that the current generation of compiler optimisers don't seem to work from the insight that temp is uninitialised garbage, and fail to optimise out the loop and default copy constructor invocations. You could credibly argue that compilers absolutely shouldn't optimise this away, as a programmer writing the above has a reasonable expectation that all the objects will be identical after the loop, even if garbage (usual caveats about 'identical'/operator== vs memcmp/operator= etc apply). The compiler can't be expected to have any extra insight into the larger context of std::vector<> or the later usage of the data that would suggest this optimisation safe.

这可以与更明显的直接实现形成对比:

for (int i = 0; i < n; ++i)
    x[i] = T();

我们可以期待一个编译器优化。

为了更明确地解释vector行为的这一方面，可以考虑:

std::vector<big_reference_counted_object> x(10000);

显然，如果我们创建10000个独立对象，而不是创建10000个引用相同数据的对象，这是一个很大的区别。有一种合理的观点认为，保护普通c++用户不意外地做一些如此昂贵的事情的好处超过了现实世界中难以优化的拷贝构造的非常小的成本。

原始答案(供参考/理解评论): 没有机会。Vector和数组一样快，至少如果你合理地保留空间. ...

好吧，因为vector::resize()比普通内存分配(由malloc)做更多的处理。

尝试在复制构造函数中设置断点(定义它以便可以设置断点!)，就会增加处理时间。

试试这个:

void UseVectorCtor()
{
    TestTimer t("UseConstructor");

    for(int i = 0; i < 1000; ++i)
    {
        int dimension = 999;

        std::vector<Pixel> pixels(dimension * dimension, Pixel(255, 0, 0));
    }
}

我得到了和数组几乎完全一样的性能。

The thing about vector is that it's a much more general tool than an array. And that means you have to consider how you use it. It can be used in a lot of different ways, providing functionality that an array doesn't even have. And if you use it "wrong" for your purpose, you incur a lot of overhead, but if you use it correctly, it is usually basically a zero-overhead data structure. In this case, the problem is that you separately initialized the vector (causing all elements to have their default ctor called), and then overwriting each element individually with the correct value. That is much harder for the compiler to optimize away than when you do the same thing with an array. Which is why the vector provides a constructor which lets you do exactly that: initialize N elements with value X.

当你使用它时，向量和数组一样快。

所以，你还没有打破性能神话。但是你已经证明了只有当你最优地使用向量时它才成立，这也是一个很好的观点。：）

好的一面是，它确实是最简单的用法，但却是最快的。如果您将我的代码片段(一行)与John Kugelman的答案进行对比，其中包含大量的调整和优化，但仍然不能完全消除性能差异，很明显，vector的设计非常巧妙。你不必费尽周折才能得到等于数组的速度。相反，您必须使用最简单的解决方案。

当我第一次看您的代码时，这很难说是一个公平的比较;我还以为你不是在比较苹果和苹果。所以我想，让构造函数和析构函数在所有测试中都被调用;然后比较。

const size_t dimension = 1000;

void UseArray() {
    TestTimer t("UseArray");
    for(size_t j = 0; j < dimension; ++j) {
        Pixel* pixels = new Pixel[dimension * dimension];
        for(size_t i = 0 ; i < dimension * dimension; ++i) {
            pixels[i].r = 255;
            pixels[i].g = 0;
            pixels[i].b = (unsigned char) (i % 255);
        }
        delete[] pixels;
    }
}

void UseVector() {
    TestTimer t("UseVector");
    for(size_t j = 0; j < dimension; ++j) {
        std::vector<Pixel> pixels(dimension * dimension);
        for(size_t i = 0; i < dimension * dimension; ++i) {
            pixels[i].r = 255;
            pixels[i].g = 0;
            pixels[i].b = (unsigned char) (i % 255);
        }
    }
}

int main() {
    TestTimer t1("The whole thing");

    UseArray();
    UseVector();

    return 0;
}

我的想法是，在这样的设置下，它们应该是完全相同的。事实证明，我错了。

UseArray completed in 3.06 seconds
UseVector completed in 4.087 seconds
The whole thing completed in 10.14 seconds

那么为什么会出现30%的性能损失呢?STL的所有内容都在头文件中，因此编译器应该能够理解所需的所有内容。

我的想法是，它是在循环如何初始化默认构造函数的所有值。所以我做了一个测试:

class Tester {
public:
    static int count;
    static int count2;
    Tester() { count++; }
    Tester(const Tester&) { count2++; }
};
int Tester::count = 0;
int Tester::count2 = 0;

int main() {
    std::vector<Tester> myvec(300);
    printf("Default Constructed: %i\nCopy Constructed: %i\n", Tester::count, Tester::count2);

    return 0;
}

结果如我所料:

Default Constructed: 1
Copy Constructed: 300

这显然是减速的根源，因为vector使用复制构造函数从默认构造的对象初始化元素。

这意味着，以下伪操作顺序发生在向量的构造过程中:

Pixel pixel;
for (auto i = 0; i < N; ++i) vector[i] = pixel;

由于编译器创建了隐式复制构造函数，扩展为:

Pixel pixel;
for (auto i = 0; i < N; ++i) {
    vector[i].r = pixel.r;
    vector[i].g = pixel.g;
    vector[i].b = pixel.b;
}

所以默认像素保持未初始化，而其余的初始化使用默认像素的未初始化值。

与New[]/Delete[]相比:

int main() {
    Tester* myvec = new Tester[300];

    printf("Default Constructed: %i\nCopy Constructed:%i\n", Tester::count, Tester::count2);

    delete[] myvec;

    return 0;
}

Default Constructed: 300
Copy Constructed: 0

它们都保留了未初始化的值，并且没有对序列进行两次迭代。

有了这些信息，我们如何进行测试呢?让我们试着重写隐式复制构造函数。

Pixel(const Pixel&) {}

结果呢?

UseArray completed in 2.617 seconds
UseVector completed in 2.682 seconds
The whole thing completed in 5.301 seconds

总而言之，如果你经常制作数百个向量:重新考虑你的算法。

在任何情况下，STL实现都不会因为某些未知的原因而变慢，它只是完全按照你的要求去做;希望你能明白。

一些分析器数据(像素对齐为32位):

g++ -msse3 -O3 -ftree-vectorize -g test.cpp -DNDEBUG && ./a.out
UseVector completed in 3.123 seconds
UseArray completed in 1.847 seconds
UseVectorPushBack completed in 9.186 seconds
The whole thing completed in 14.159 seconds

Blah

andrey@nv:~$ opannotate --source libcchem/src/a.out  | grep "Total samples for file" -A3
Overflow stats not available
 * Total samples for file : "/usr/include/c++/4.4/ext/new_allocator.h"
 *
 * 141008 52.5367
 */
--
 * Total samples for file : "/home/andrey/libcchem/src/test.cpp"
 *
 *  61556 22.9345
 */
--
 * Total samples for file : "/usr/include/c++/4.4/bits/stl_vector.h"
 *
 *  41956 15.6320
 */
--
 * Total samples for file : "/usr/include/c++/4.4/bits/stl_uninitialized.h"
 *
 *  20956  7.8078
 */
--
 * Total samples for file : "/usr/include/c++/4.4/bits/stl_construct.h"
 *
 *   2923  1.0891
 */

在分配器:

               :      // _GLIBCXX_RESOLVE_LIB_DEFECTS
               :      // 402. wrong new expression in [some_] allocator::construct
               :      void
               :      construct(pointer __p, const _Tp& __val)
141008 52.5367 :      { ::new((void *)__p) _Tp(__val); }

向量:

               :void UseVector()
               :{ /* UseVector() total:  60121 22.3999 */
...
               :
               :
 10790  4.0201 :        for (int i = 0; i < dimension * dimension; ++i) {
               :
   495  0.1844 :            pixels[i].r = 255;
               :
 12618  4.7012 :            pixels[i].g = 0;
               :
  2253  0.8394 :            pixels[i].b = 0;
               :
               :        }

数组

               :void UseArray()
               :{ /* UseArray() total:  35191 13.1114 */
               :
...
               :
   136  0.0507 :        for (int i = 0; i < dimension * dimension; ++i) {
               :
  9897  3.6874 :            pixels[i].r = 255;
               :
  3511  1.3081 :            pixels[i].g = 0;
               :
 21647  8.0652 :            pixels[i].b = 0;

大部分开销都在复制构造函数中。例如,

    std::vector < Pixel > pixels;//(dimension * dimension, Pixel());

    pixels.reserve(dimension * dimension);

    for (int i = 0; i < dimension * dimension; ++i) {

        pixels[i].r = 255;

        pixels[i].g = 0;

        pixels[i].b = 0;
    }

它具有与数组相同的性能。