There is another option and this works if there are multiple items in the list of objects: copy the object using this.state.Obj to a variable (say temp), use filter() method to traverse through the object and grab the particular element you want to change into one object(name it updateObj) and the remaining list of object into another object(name this as restObj). Now edit the contents of object you want to update creating a new item (say newItem). Then call this.setUpdate() and use spread operators to assing new list of objects to the parent object.

this.state = {someProperty: { flag:true, }}


var temp=[...this.state.someProperty]
var restObj = temp.filter((item) => item.flag !== true);
var updateObj = temp.filter((item) => item.flag === true);

var newItem = {
  flag: false
};
this.setState({ someProperty: [...restObj, newItem] });

这是我的initialState

    const initialStateInput = {
        cabeceraFamilia: {
            familia: '',
            direccion: '',
            telefonos: '',
            email: ''
        },
        motivoConsulta: '',
        fechaHora: '',
        corresponsables: [],
    }

钩子或者你可以用状态(类组件)替换它

const [infoAgendamiento, setInfoAgendamiento] = useState(initialStateInput);

handleChange的方法

const actualizarState = e => {
    const nameObjects = e.target.name.split('.');
    const newState = setStateNested(infoAgendamiento, nameObjects, e.target.value);
    setInfoAgendamiento({...newState});
};

使用嵌套状态设置状态的方法

const setStateNested = (state, nameObjects, value) => {
    let i = 0;
    let operativeState = state;
    if(nameObjects.length > 1){
        for (i = 0; i < nameObjects.length - 1; i++) {
            operativeState = operativeState[nameObjects[i]];
        }
    }
    operativeState[nameObjects[i]] = value;
    return state;
}

最后这是我使用的输入

<input type="text" className="form-control" name="cabeceraFamilia.direccion" placeholder="Dirección" defaultValue={infoAgendamiento.cabeceraFamilia.direccion} onChange={actualizarState} />

我用了这个方法。

如果你有一个这样的嵌套状态:

   this.state = {
          formInputs:{
            friendName:{
              value:'',
              isValid:false,
              errorMsg:''
            },
            friendEmail:{
              value:'',
              isValid:false,
              errorMsg:''
            }
}

你可以声明handleChange函数来复制当前状态并重新赋值

handleChange(el) {
    let inputName = el.target.name;
    let inputValue = el.target.value;

    let statusCopy = Object.assign({}, this.state);
    statusCopy.formInputs[inputName].value = inputValue;

    this.setState(statusCopy);
  }

这里是带有事件侦听器的HTML

<input type="text" onChange={this.handleChange} " name="friendName" />

为了让事情变得通用，我研究了@ShubhamKhatri和@Qwerty的答案。

状态对象

this.state = {
  name: '',
  grandParent: {
    parent1: {
      child: ''
    },
    parent2: {
      child: ''
    }
  }
};

输入控件

<input
  value={this.state.name}
  onChange={this.updateState}
  type="text"
  name="name"
/>
<input
  value={this.state.grandParent.parent1.child}
  onChange={this.updateState}
  type="text"
  name="grandParent.parent1.child"
/>
<input
  value={this.state.grandParent.parent2.child}
  onChange={this.updateState}
  type="text"
  name="grandParent.parent2.child"
/>

updateState方法

setState作为@ShubhamKhatri的答案

updateState(event) {
  const path = event.target.name.split('.');
  const depth = path.length;
  const oldstate = this.state;
  const newstate = { ...oldstate };
  let newStateLevel = newstate;
  let oldStateLevel = oldstate;

  for (let i = 0; i < depth; i += 1) {
    if (i === depth - 1) {
      newStateLevel[path[i]] = event.target.value;
    } else {
      newStateLevel[path[i]] = { ...oldStateLevel[path[i]] };
      oldStateLevel = oldStateLevel[path[i]];
      newStateLevel = newStateLevel[path[i]];
    }
  }
  this.setState(newstate);
}

setState作为@Qwerty的答案

updateState(event) {
  const path = event.target.name.split('.');
  const depth = path.length;
  const state = { ...this.state };
  let ref = state;
  for (let i = 0; i < depth; i += 1) {
    if (i === depth - 1) {
      ref[path[i]] = event.target.value;
    } else {
      ref = ref[path[i]];
    }
  }
  this.setState(state);
}

注意:上述方法不适用于数组

尽管嵌套并不是处理组件状态的真正方式，但有时对于单层嵌套来说很容易。

对于这样一个州来说

state = {
 contact: {
  phone: '888-888-8888',
  email: 'test@test.com'
 }
 address: {
  street:''
 },
 occupation: {
 }
}

我使用的一个可重用的方法是这样的。

handleChange = (obj) => e => {
  let x = this.state[obj];
  x[e.target.name] = e.target.value;
  this.setState({ [obj]: x });
};

然后为你想要处理的每个嵌套传递obj名称…

<TextField
 name="street"
 onChange={handleChange('address')}
 />

setInputState((pre)=> ({...pre,[parentKey]: {...pre[parentKey], [childKey]: value}}));

我喜欢这个