如何在UITableView中改变section头的颜色?
编辑:DJ-S提供的答案应该适用于iOS 6及以上版本。公认的答案已经过时了。
如何在UITableView中改变section头的颜色?
编辑:DJ-S提供的答案应该适用于iOS 6及以上版本。公认的答案已经过时了。
当前回答
在UITableViewHeaderFooterView上设置背景色已弃用。请使用contentView。写成backgroundColor代替。
其他回答
希望UITableViewDelegate协议中的这个方法能让你开始:
objective - c:
- (UIView *) tableView:(UITableView *)tableView viewForHeaderInSection:(NSInteger)section
{
UIView *headerView = [[[UIView alloc] initWithFrame:CGRectMake(0, 0, tableView.bounds.size.width, 30)] autorelease];
if (section == integerRepresentingYourSectionOfInterest)
[headerView setBackgroundColor:[UIColor redColor]];
else
[headerView setBackgroundColor:[UIColor clearColor]];
return headerView;
}
迅速:
func tableView(_ tableView: UITableView!, viewForHeaderInSection section: Int) -> UIView!
{
let headerView = UIView(frame: CGRect(x: 0, y: 0, width: tableView.bounds.size.width, height: 30))
if (section == integerRepresentingYourSectionOfInterest) {
headerView.backgroundColor = UIColor.redColor()
} else {
headerView.backgroundColor = UIColor.clearColor()
}
return headerView
}
2017年更新:
斯威夫特3:
func tableView(_ tableView: UITableView, viewForHeaderInSection section: Int) -> UIView?
{
let headerView = UIView(frame: CGRect(x: 0, y: 0, width: tableView.bounds.size.width, height: 30))
if (section == integerRepresentingYourSectionOfInterest) {
headerView.backgroundColor = UIColor.red
} else {
headerView.backgroundColor = UIColor.clear
}
return headerView
}
替换[UIColor redColor]与任何你想要的UIColor。您可能还希望调整headerView的尺寸。
下面是如何在头视图中添加图像:
- (UIView *) tableView:(UITableView *)tableView viewForHeaderInSection:(NSInteger)section
{
UIView *headerView = [[[UIView alloc] initWithFrame:CGRectMake(0, 0, tableView.bounds.size.width, 30)] autorelease];
UIImageView *headerImage = [[[UIImageView alloc] initWithImage:[UIImage imageNamed:@"top-gery-bar.png"]] autorelease];
headerImage.frame = CGRectMake(0, 0, tableView.bounds.size.width, 30);
[headerView addSubview:headerImage];
return headerView;
}
In iOS 7.0.4 I created a custom header with it's own XIB. Nothing mentioned here before worked. It had to be the subclass of the UITableViewHeaderFooterView to work with the dequeueReusableHeaderFooterViewWithIdentifier: and it seems that class is very stubborn regarding the background color. So finally I added an UIView (you could do it either with code or IB) with name customBackgroudView, and then set it's backgroundColor property. In layoutSubviews: I set that view's frame to bounds. It work with iOS 7 and gives no glitches.
// in MyTableHeaderView.xib drop an UIView at top of the first child of the owner
// first child becomes contentView
// in MyTableHeaderView.h
@property (nonatomic, weak) IBOutlet UIView * customBackgroundView;
// in MyTableHeaderView.m
-(void)layoutSubviews;
{
[super layoutSubviews];
self.customBackgroundView.frame = self.bounds;
}
// if you don't have XIB / use IB, put in the initializer:
-(id)initWithReuseIdentifier:(NSString *)reuseIdentifier
{
...
UIView * customBackgroundView = [[UIView alloc] init];
[self.contentView addSubview:customBackgroundView];
_customBackgroundView = customBackgroundView;
...
}
// in MyTableViewController.m
-(UIView *)tableView:(UITableView *)tableView viewForHeaderInSection:(NSInteger)section
{
MyTableHeaderView * header = [self.tableView
dequeueReusableHeaderFooterViewWithIdentifier:@"MyTableHeaderView"];
header.customBackgroundView.backgroundColor = [UIColor redColor];
return header;
}
下面是如何更改文本颜色。
UILabel *label = [[[UILabel alloc] initWithFrame:CGRectMake(10, 3, tableView.bounds.size.width - 10, 18)] autorelease];
label.text = @"Section Header Text Here";
label.textColor = [UIColor colorWithRed:1.0 green:1.0 blue:1.0 alpha:0.75];
label.backgroundColor = [UIColor clearColor];
[headerView addSubview:label];
我有一个项目使用静态表视图单元格,在iOS 7.x。willDisplayHeaderView不会触发。但是,这个方法是可行的:
- (UIView *)tableView:(UITableView *)tableView viewForHeaderInSection:(NSInteger)section
{
NSLog(@"%s", __FUNCTION__);
CGRect headerFrame = CGRectMake(x, y, w, h);
UIView *headerView = [[UIView alloc] initWithFrame:headerFrame];
headerView.backgroundColor = [UIColor blackColor];