该应用程序基本上通过输入初始和最终速度和时间来计算加速度,然后使用一个公式来计算加速度。但是,由于文本框中的值是字符串,我无法将它们转换为整数。

@IBOutlet var txtBox1 : UITextField
@IBOutlet var txtBox2 : UITextField
@IBOutlet var txtBox3 : UITextField
@IBOutlet var lblAnswer : UILabel


@IBAction func btn1(sender : AnyObject) {

    let answer1 = "The acceleration is"
    var answer2 = txtBox1
    var answer3 = txtBox2
    var answer4 = txtBox3

当前回答

编辑/更新:Xcode 11.4•Swift 5.2

请检查代码中的注释


IntegerField.swift文件内容:

import UIKit

class IntegerField: UITextField {

    // returns the textfield contents, removes non digit characters and converts the result to an integer value
    var value: Int { string.digits.integer ?? 0 }

    var maxValue: Int = 999_999_999
    private var lastValue: Int = 0

    override func willMove(toSuperview newSuperview: UIView?) {
        // adds a target to the textfield to monitor when the text changes
        addTarget(self, action: #selector(editingChanged), for: .editingChanged)
        // sets the keyboard type to digits only
        keyboardType = .numberPad
        // set the text alignment to right
        textAlignment = .right
        // sends an editingChanged action to force the textfield to be updated
        sendActions(for: .editingChanged)
    }
    // deletes the last digit of the text field
    override func deleteBackward() {
        // note that the field text property default value is an empty string so force unwrap its value is safe
        // note also that collection remove at requires a non empty collection which is true as well in this case so no need to check if the collection is not empty.
        text!.remove(at: text!.index(before: text!.endIndex))
        // sends an editingChanged action to force the textfield to be updated
        sendActions(for: .editingChanged)
    }
    @objc func editingChanged() {
        guard value <= maxValue else {
            text = Formatter.decimal.string(for: lastValue)
            return
        }
        // This will format the textfield respecting the user device locale and settings
        text = Formatter.decimal.string(for: value)
        print("Value:", value)
        lastValue = value
    }
}

您还需要将这些扩展添加到您的项目中:


扩展UITextField.swift文件内容:

import UIKit
extension UITextField {
    var string: String { text ?? "" }
}

Formatter.swift文件内容:

import Foundation
extension Formatter {
    static let decimal = NumberFormatter(numberStyle: .decimal)
}

扩展NumberFormatter.swift文件内容:

import Foundation
extension NumberFormatter {
    convenience init(numberStyle: Style) {
        self.init()
        self.numberStyle = numberStyle
    }
}

StringProtocol.swift文件内容:

extension StringProtocol where Self: RangeReplaceableCollection {
    var digits: Self { filter(\.isWholeNumber) }
    var integer: Int? { Int(self) }
}

示例项目

其他回答

斯威夫特,斯威夫特

有不同的情况下,从一个数据类型转换到另一个数据类型,这取决于输入。

如果输入数据类型是Any,我们必须像以前一样使用convert到实际的数据类型,然后转换为我们想要的数据类型。例如:

func justGetDummyString() -> Any {
  return "2000"
}
let dummyString: String = (justGetDummyString() as? String) ?? "" // output = "2000"
let dummyInt: Int = Int(dummyString) ?? 0 // output = 2000

至于swift 3,我必须强制我的#%@!字符串和int加上一个“!”否则它就不起作用。

例如:

let prefs = UserDefaults.standard
var counter: String!
counter = prefs.string(forKey:"counter")
print("counter: \(counter!)")


var counterInt = Int(counter!)
counterInt = counterInt! + 1
print("counterInt: \(counterInt!)")

OUTPUT:
counter: 1
counterInt: 2

为替代方案。您可以对本机类型使用扩展。你可以在操场上测试。

extension String {
    func add(a: Int) -> Int? {
        if let b = Int(self) {
            return b + a
        }
        else {
            return nil
        }
    }     
}

“2”阀门(1)

myString.toInt() -将字符串值转换为int。

快3.倍

如果你在字符串中隐藏了一个整数,你可以使用整数的构造函数进行转换,如下所示:

let myInt = Int(textField.text)

与其他数据类型(Float和Double)一样,你也可以使用NSString进行转换:

let myString = "556"
let myInt = (myString as NSString).integerValue

斯威夫特3.0

试试这个,你不需要检查任何条件,我已经做了一切,只是使用这个函数。发送任何字符串,数字,浮点数,双精度等。您将得到一个数字作为值,如果它无法转换您的值则为0

功能:

func getNumber(number: Any?) -> NSNumber {
    guard let statusNumber:NSNumber = number as? NSNumber else
    {
        guard let statString:String = number as? String else
        {
            return 0
        }
        if let myInteger = Int(statString)
        {
            return NSNumber(value:myInteger)
        }
        else{
            return 0
        }
    }
    return statusNumber
}

用法: 在代码中添加上述函数并转换使用 让myNumber = getNumber(number: myString) 如果myString包含数字或字符串,则返回数字,否则返回0

示例1:

let number:String = "9834"
print("printing number \(getNumber(number: number))")

输出:打印号9834

示例2:

let number:Double = 9834
print("printing number \(getNumber(number: number))")

输出:打印号9834

示例3:

let number = 9834
print("printing number \(getNumber(number: number))")

输出:打印号9834