在c#中随机化泛型列表顺序的最佳方法是什么?我在一个列表中有一个有限的75个数字集，我想随机分配一个顺序，以便为彩票类型的应用程序绘制它们。
当前回答
private List<GameObject> ShuffleList(List<GameObject> ActualList) {
List<GameObject> newList = ActualList;
List<GameObject> outList = new List<GameObject>();
int count = newList.Count;
while (newList.Count > 0) {
int rando = Random.Range(0, newList.Count);
outList.Add(newList[rando]);
newList.RemoveAt(rando);
}
return (outList);
}
用法:
List<GameObject> GetShuffle = ShuffleList(ActualList);
其他回答
这里有一个线程安全的方法来做到这一点:
public static class EnumerableExtension
{
private static Random globalRng = new Random();
[ThreadStatic]
private static Random _rng;
private static Random rng
{
get
{
if (_rng == null)
{
int seed;
lock (globalRng)
{
seed = globalRng.Next();
}
_rng = new Random(seed);
}
return _rng;
}
}
public static IEnumerable<T> Shuffle<T>(this IEnumerable<T> items)
{
return items.OrderBy (i => rng.Next());
}
}
如果你不介意使用两个list，那么这可能是最简单的方法，但可能不是最有效或最不可预测的方法:
List<int> xList = new List<int>() { 1, 2, 3, 4, 5 };
List<int> deck = new List<int>();
foreach (int xInt in xList)
deck.Insert(random.Next(0, deck.Count + 1), xInt);
想法是获得匿名对象的项目和随机顺序，然后按此顺序重新排序项目，并返回值:
var result = items.Select(x => new { value = x, order = rnd.Next() })
.OrderBy(x => x.order).Select(x => x.value).ToList()
public static List<T> Randomize<T>(List<T> list)
{
List<T> randomizedList = new List<T>();
Random rnd = new Random();
while (list.Count > 0)
{
int index = rnd.Next(0, list.Count); //pick a random item from the master list
randomizedList.Add(list[index]); //place it at the end of the randomized list
list.RemoveAt(index);
}
return randomizedList;
}
我在网上找到了一个有趣的解决办法。
礼貌:https://improveandrepeat.com/2018/08/a-simple-way-to-shuffle-your-lists-in-c/
var shuffled = myList。OrderBy(x => Guid.NewGuid()).ToList();
