IEnumerable扩展方法:

public static IEnumerable<T> Randomize<T>(this IEnumerable<T> source)
{
    Random rnd = new Random();
    return source.OrderBy<T, int>((item) => rnd.Next());
}

private List<GameObject> ShuffleList(List<GameObject> ActualList) {


    List<GameObject> newList = ActualList;
    List<GameObject> outList = new List<GameObject>();

    int count = newList.Count;

    while (newList.Count > 0) {

        int rando = Random.Range(0, newList.Count);

        outList.Add(newList[rando]);

        newList.RemoveAt(rando);

     

    }

    return (outList);

}

用法:

List<GameObject> GetShuffle = ShuffleList(ActualList);

如果您有一个固定的数字(75)，您可以创建一个包含75个元素的数组，然后枚举您的列表，将元素移动到数组中的随机位置。您可以使用Fisher-Yates shuffle生成列表号到数组索引的映射。

想法是获得匿名对象的项目和随机顺序，然后按此顺序重新排序项目，并返回值:

var result = items.Select(x => new { value = x, order = rnd.Next() })
            .OrderBy(x => x.order).Select(x => x.value).ToList()

您可以使用这个简单的扩展方法来实现这一点

public static class IEnumerableExtensions
{

    public static IEnumerable<t> Randomize<t>(this IEnumerable<t> target)
    {
        Random r = new Random();

        return target.OrderBy(x=>(r.Next()));
    }        
}

你可以通过下面的步骤来使用它

// use this on any collection that implements IEnumerable!
// List, Array, HashSet, Collection, etc

List<string> myList = new List<string> { "hello", "random", "world", "foo", "bar", "bat", "baz" };

foreach (string s in myList.Randomize())
{
    Console.WriteLine(s);
}

I'm bit surprised by all the clunky versions of this simple algorithm here. Fisher-Yates (or Knuth shuffle) is bit tricky but very compact. Why is it tricky? Because your need to pay attention to whether your random number generator r(a,b) returns value where b is inclusive or exclusive. I've also edited Wikipedia description so people don't blindly follow pseudocode there and create hard to detect bugs. For .Net, Random.Next(a,b) returns number exclusive of b so without further ado, here's how it can be implemented in C#/.Net:

public static void Shuffle<T>(this IList<T> list, Random rnd)
{
    for(var i=list.Count; i > 0; i--)
        list.Swap(0, rnd.Next(0, i));
}

public static void Swap<T>(this IList<T> list, int i, int j)
{
    var temp = list[i];
    list[i] = list[j];
    list[j] = temp;
}

试试这段代码。