我很难理解Ruby中的attr_accessor。 有人能给我解释一下吗?
当前回答
简单的解释,没有任何代码
以上大多数答案都使用代码。这个解释试图通过一个类比/故事来回答这个问题:
外界不能接触CIA内部机密
Let's imagine a really secret place: the CIA. Nobody knows what's happening in the CIA apart from the people inside the CIA. In other words, external people cannot access any information in the CIA. But because it's no good having an organisation that is completely secret, certain information is made available to the outside world - only things that the CIA wants everyone to know about of course: e.g. the Director of the CIA, how environmentally friendly this department is compared to all other government departments etc. Other information: e.g. who are its covert operatives in Iraq or Afghanistan - these types of things will probably remain a secret for the next 150 years. If you're outside the CIA you can only access the information that it has made available to the public. Or to use CIA parlance you can only access information that is "cleared". The information that the CIA wants to make available to the general public outside the CIA are called: attributes.
读写属性的含义:
In the case of the CIA, most attributes are "read only". This means if you are a party external to the CIA, you can ask: "who is the director of the CIA?" and you will get a straight answer. But what you cannot do with "read only" attributes is to make changes changes in the CIA. e.g. you cannot make a phone call and suddenly decide that you want Kim Kardashian to be the Director, or that you want Paris Hilton to be the Commander in Chief. If the attributes gave you "write" access, then you could make changes if you want to, even if you were outside. Otherwise, the only thing you can do is read. In other words accessors allow you to make inquiries, or to make changes, to organisations that otherwise do not let external people in, depending on whether the accessors are read or write accessors.
类中的对象可以很容易地相互访问
另一方面,如果你已经在中央情报局内部,那么你可以很容易地打电话给你在喀布尔的中央情报局特工,因为这些信息很容易获得,因为你已经在里面了。但如果你不在中情局之外,你根本就没有权限:你不能知道他们是谁(读权限),你也不能改变他们的任务(写权限)。
类也是如此,你可以访问其中的变量、属性和方法。HTH !任何问题,请问,我希望我能澄清。
其他回答
它只是一个为实例变量定义getter和setter方法的方法。一个示例实现如下:
def self.attr_accessor(*names)
names.each do |name|
define_method(name) {instance_variable_get("@#{name}")} # This is the getter
define_method("#{name}=") {|arg| instance_variable_set("@#{name}", arg)} # This is the setter
end
end
简单地说,它将为类定义setter和getter。
请注意,
attr_reader :v is equivalant to
def v
@v
end
attr_writer :v is equivalant to
def v=(value)
@v=value
end
So
attr_accessor :v which means
attr_reader :v; attr_writer :v
等效于为类定义setter和getter。
定义此模块的命名属性,其中名称为symbol。Id2name,创建实例变量(@name)和读取它的相应访问方法。还创建一个名为name=的方法来设置属性。
module Mod
attr_accessor(:one, :two)
end
Mod.instance_methods.sort #=> [:one, :one=, :two, :two=]
尽管已有大量的答案,但在我看来,没有一个能解释这里涉及的实际机制。它的元编程;它利用了以下两个事实:
您可以动态地修改模块/类 模块/类声明本身就是可执行代码
好吧,想象一下:
class Nameable
def self.named(whatvalue)
define_method :name do whatvalue end
end
end
我们声明了一个名为which的类方法,当用值调用时,创建一个名为name的实例方法,该实例方法返回该值。这就是元编程的部分。
现在我们将子类化这个类:
class Dog < Nameable
named "Fido"
end
我们刚才到底做了什么?在类声明中,可执行代码执行时引用了类。因此,简单的单词named实际上是对类方法named的调用,它继承自Nameable;我们传递字符串“Fido”作为参数。
命名的类方法是做什么的?它创建一个名为name的实例方法,该方法返回该值。现在,在幕后,Dog有一个这样的方法:
def name
"Fido"
end
不相信我?然后看这个小动作:
puts Dog.new.name #=> Fido
我为什么要告诉你这些?因为我刚才对Nameable所做的和attr_accessor对Module所做的几乎完全一样。当您使用attr_accessor时,您正在调用创建实例方法的类方法(继承自Module)。特别是,它为实例属性创建了一个getter和setter方法,实例属性的名称是您提供的参数,这样您就不必自己编写这些getter和setter方法。
Attr_accessor非常简单:
attr_accessor :foo
是以下操作的快捷方式:
def foo=(val)
@foo = val
end
def foo
@foo
end
它只不过是一个对象的getter/setter
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