我在看Pluralsight关于React的课程,老师说道具不应该被改变。我现在正在读一篇关于道具vs.国家的文章(uberVU/react-guide),它说

道具和状态更改都会触发呈现更新。

文章后面说:

Props(属性的缩写)是组件的配置,如果可以的话,是它的选项。它们是从上面接收的,是不可变的。

所以道具可以改变,但它们应该是不可变的? 什么时候应该使用道具,什么时候应该使用状态? 如果你有一个React组件需要的数据,它应该通过道具或设置在React组件通过getInitialState?


当前回答

状态驻留在组件中,作为道具从父组件传递给子组件。 道具通常是不可变的。

class Parent extends React.Component {
    constructor() {
        super();
        this.state = {
            name : "John",
        }
    }
    render() {
        return (
            <Child name={this.state.name}>
        )
    }
}

class Child extends React.Component {
    constructor() {
        super();
    }

    render() {
        return(
            {this.props.name} 
        )
    }
}

在上面的代码中,我们有一个父类(parent),它的状态是name,它被传递给子组件(子类)作为道具,子组件使用{this.props.name}渲染它。

其他回答

“Props”是传递给组件(1)的外部输入,“state”是由组件(2)管理的内部私有数据。

Basically, props and state are two ways the component can know what and how to render. Which part of the application state belongs to state and which to some top-level store, is more related to your app design, than to how React works. The simplest way to decide, IMO, is to think, whether this particular piece of data is useful for application as a whole, or it's some local information. Also, it's important to not duplicate state, so if some piece of data can be calculated from props - it should calculated from props.

For example, let's say you have some dropdown control (which wraps standart HTML select for custom styling), which can a) select some value from list, and b) be opened or closed (i.e., the options list displayed or hidden). Now, let's say your app displays a list of items of some sort and your dropdown controls filter for list entries. Then, it would be best to pass active filter value as a prop, and keep opened/closed state local. Also, to make it functional, you would pass an onChange handler from parent component, which would be called inside dropdown element and send updated information (new selected filter) to the store immediately. On the other hand, opened/closed state can be kept inside dropdown component, because the rest of the application doesn't really care if the control is opened, until user actually changes it value.

下面的代码是不完全工作,它需要css和处理下拉单击/模糊/改变事件,但我想保持示例最小。希望这有助于理解其中的区别。

const _store = {
    items: [
    { id: 1, label: 'One' },
    { id: 2, label: 'Two' },
    { id: 3, label: 'Three', new: true },
    { id: 4, label: 'Four', new: true },
    { id: 5, label: 'Five', important: true },
    { id: 6, label: 'Six' },
    { id: 7, label: 'Seven', important: true },
    ],
  activeFilter: 'important',
  possibleFilters: [
    { key: 'all', label: 'All' },
    { key: 'new', label: 'New' },
    { key: 'important', label: 'Important' }
  ]
}

function getFilteredItems(items, filter) {
    switch (filter) {
    case 'all':
        return items;

    case 'new':
        return items.filter(function(item) { return Boolean(item.new); });

    case 'important':
        return items.filter(function(item) { return Boolean(item.important); });

    default:
        return items;
  }
}

const App = React.createClass({
  render: function() {
    return (
            <div>
            My list:

            <ItemList   items={this.props.listItems} />
          <div>
            <Dropdown 
              onFilterChange={function(e) {
                _store.activeFilter = e.currentTarget.value;
                console.log(_store); // in real life, some action would be dispatched here
              }}
              filterOptions={this.props.filterOptions}
              value={this.props.activeFilter}
              />
          </div>
        </div>
      );
  }
});

const ItemList = React.createClass({
  render: function() {
    return (
      <div>
        {this.props.items.map(function(item) {
          return <div key={item.id}>{item.id}: {item.label}</div>;
        })}
      </div>
    );
  }
});

const Dropdown = React.createClass({
    getInitialState: function() {
    return {
        isOpen: false
    };
  },

  render: function() {
    return (
        <div>
            <select 
            className="hidden-select" 
          onChange={this.props.onFilterChange}
          value={this.props.value}>
            {this.props.filterOptions.map(function(option) {
            return <option value={option.key} key={option.key}>{option.label}</option>
          })}
        </select>

        <div className={'custom-select' + (this.state.isOpen ? ' open' : '')} onClick={this.onClick}>
            <div className="selected-value">{this.props.activeFilter}</div>
          {this.props.filterOptions.map(function(option) {
            return <div data-value={option.key} key={option.key}>{option.label}</div>
          })}
        </div>
      </div>
    );
  },

  onClick: function(e) {
    this.setState({
        isOpen: !this.state.isOpen
    });
  }
});

ReactDOM.render(
  <App 
    listItems={getFilteredItems(_store.items, _store.activeFilter)} 
    filterOptions={_store.possibleFilters}
    activeFilter={_store.activeFilter}
    />,
  document.getElementById('root')
);

State是react中的一个特殊变量,用于在组件更新时重新渲染组件

状态对于组件本身是私有的。也就是说,它不能在组件外部被访问或修改。setState/用于更新状态的钩子。每当状态更新时,组件重新呈现

状态是可变的

道具是组件的输入,并使用道具数据呈现内容

道具是不可变的(Object。冻结= true)

用户在应用程序的某个地方输入了一些数据。

在其中输入数据的组件应该在其状态中拥有该数据,因为它需要在数据输入期间操作和更改它 在应用程序的其他任何地方,数据都应该作为道具传递给所有其他组件

所以,是的,道具是在变化的,但它们是从“源头”改变的,然后简单地从那里向下流动。所以道具在接收它们的组件的上下文中是不可变的。

例如,在一个参考数据屏幕上,用户编辑一个供应商列表将在状态下管理它,然后会有一个操作,导致更新的数据保存在ReferenceDataState中,它可能比AppState低一级,然后这个供应商列表将作为道具传递给所有需要使用它的组件。

道具和状态之间的关键区别在于,状态是内部的,由组件本身控制,而道具是外部的,由呈现组件的任何东西控制。