通过编程方式从Android内置的Gallery应用程序中获取/选择一张图像

我试图从我的应用程序中打开画廊内置应用程序中的图像/图片。

我有一个图片的URI(图片位于SD卡上)。

你有什么建议吗?

当前回答

这是我的例子，可能不完全是你的情况。

假设你从你的API提供者获得base64格式，给它一个文件名和文件扩展名，将它保存到文件系统中的某个位置。

public static void shownInBuiltInGallery(final Context ctx, String strBase64Image, final String strFileName, final String strFileExtension){

new AsyncTask<String, String, File>() {
    @Override
    protected File doInBackground(String... strBase64Image) {

        Bitmap bmpImage = convertBase64StringToBitmap(strBase64Image[0], Base64.NO_WRAP);

        if(bmpImage == null) {
            cancel(true);
            return null;
        }

        byte[] byImage = null;

        if(strFileExtension.compareToIgnoreCase(FILE_EXTENSION_JPG) == 0) {
            byImage = convertToJpgByte(bmpImage); // convert bitmap to binary for latter use
        } else if(strFileExtension.compareToIgnoreCase(FILE_EXTENSION_PNG) == 0){
            byImage = convertToPngByte(bmpImage); // convert bitmap to binary for latter use
        } else if(strFileExtension.compareToIgnoreCase(FILE_EXTENSION_BMP) == 0){
            byImage = convertToBmpByte(bmpImage); // convert bitmap to binary for latter use
        } else {
            cancel(true);
            return null;
        }

        if(byImage == null) {
            cancel(true);
            return null;
        }

        File imageFolder = ctx.getExternalCacheDir();

        if(imageFolder.exists() == false){
            if(imageFolder.mkdirs() == false){
                cancel(true);
                return null;
            }
        }

        File imageFile = null;

        try {
            imageFile = File.createTempFile(strFileName, strFileExtension, imageFolder);
        } catch (IOException e){
            e.printStackTrace();
        }

        if(imageFile == null){
            cancel(true);
            return null;
        }

        if (imageFile.exists() == true) {
            if(imageFile.delete() == false){
                cancel(true);
                return null;
            }
        }

        FileOutputStream fos = null;

        try {
            fos = new FileOutputStream(imageFile.getPath());
            fos.write(byImage);
            fos.flush();
            fos.close();
        } catch (java.io.IOException e) {
            e.printStackTrace();
        } finally {
            fos = null;
        }

        return imageFile;
    }

    @Override
    protected void onPostExecute(File file) {
        super.onPostExecute(file);

            String strAuthority = ctx.getPackageName() + ".provider";
            Uri uriImage = FileProvider.getUriForFile(ctx, strAuthority, file);

            Intent intent = new Intent(Intent.ACTION_VIEW);
            intent.setDataAndType(uriImage, "image/*");
            intent.setFlags(Intent.FLAG_GRANT_READ_URI_PERMISSION);
            ctx.startActivity(intent);

    }
}.execute(strBase64Image);}

不要忘记在AndroidManifest.xml中首先设置一个适当的文件提供程序

        <provider
        android:name="android.support.v4.content.FileProvider"
        android:authorities="${applicationId}.provider"
        android:exported="false"
        android:grantUriPermissions="true">

        <meta-data
            android:name="android.support.FILE_PROVIDER_PATHS"
            android:resource="@xml/file_paths"/>
    </provider>

文件路径是XML在…/res/ XML /file_path.xml

<?xml version="1.0" encoding="utf-8"?>

<external-files-path name="external_files" path="Accessory"/>

<external-path name="ex_Download" path="Download/" />
<external-path name="ex_Pictures" path="Pictures/" />

<external-files-path name="my_Download" path="Download/" />
<external-files-path name="my_Pictures" path="Pictures/" />
<external-cache-path name="my_cache" path="." />

<files-path name="private_Download" path="Download/" />
<files-path name="private_Pictures" path="Pictures/" />
<cache-path name="private_cache" path="." />

长话短说，首先准备好文件提供程序，将已知且可访问的图片源的Uri传递给Intent，否则，将图片保存在所需的位置，然后将位置(作为Uri)传递给Intent。

2020-03-09 10:31:17

其他回答

在上面代码的基础上，我反映了如下代码，可能它更适合:

public String getPath(Uri uri) {
    String selectedImagePath;
    //1:MEDIA GALLERY --- query from MediaStore.Images.Media.DATA
    String[] projection = { MediaStore.Images.Media.DATA };
    Cursor cursor = managedQuery(uri, projection, null, null, null);
    if(cursor != null){
        int column_index = cursor.getColumnIndexOrThrow(MediaStore.Images.Media.DATA);
        cursor.moveToFirst();
        selectedImagePath = cursor.getString(column_index);
    }else{
        selectedImagePath = null;
    }

    if(selectedImagePath == null){
        //2:OI FILE Manager --- call method: uri.getPath()
        selectedImagePath = uri.getPath();
    }
    return selectedImagePath;
}

2011-01-27 03:43:49

万一有用的话;我这样做是为了得到位图:

InputStream is = context.getContentResolver().openInputStream(imageUri);
Bitmap bitmap = BitmapFactory.decodeStream(is);

2013-11-16 16:54:14

public class BrowsePictureActivity extends Activity {

    // this is the action code we use in our intent, 
    // this way we know we're looking at the response from our own action
    private static final int SELECT_PICTURE = 1;

    private String selectedImagePath;

    public void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.main);

        ((Button) findViewById(R.id.Button01))
                .setOnClickListener(new OnClickListener() {

                    public void onClick(View arg0) {

                        // in onCreate or any event where your want the user to
                        // select a file
                        Intent intent = new Intent();
                        intent.setType("image/*");
                        intent.setAction(Intent.ACTION_GET_CONTENT);
                        startActivityForResult(Intent.createChooser(intent,
                                "Select Picture"), SELECT_PICTURE);
                    }
                });
    }

    public void onActivityResult(int requestCode, int resultCode, Intent data) {
        if (resultCode == RESULT_OK) {
            if (requestCode == SELECT_PICTURE) {
                Uri selectedImageUri = data.getData();
                selectedImagePath = getPath(selectedImageUri);
            }
        }
    }

    /**
     * helper to retrieve the path of an image URI
     */
    public String getPath(Uri uri) {
            // just some safety built in 
            if( uri == null ) {
                // TODO perform some logging or show user feedback
                return null;
            }
            // try to retrieve the image from the media store first
            // this will only work for images selected from gallery
            String[] projection = { MediaStore.Images.Media.DATA };
            Cursor cursor = managedQuery(uri, projection, null, null, null);
            if( cursor != null ){
                int column_index = cursor
                .getColumnIndexOrThrow(MediaStore.Images.Media.DATA);
                cursor.moveToFirst();
                return cursor.getString(column_index);
            }
            // this is our fallback here
            return uri.getPath();
    }

}

2014-02-21 12:06:43