我试图从我的应用程序中打开画廊内置应用程序中的图像/图片。
我有一个图片的URI(图片位于SD卡上)。
你有什么建议吗?
我试图从我的应用程序中打开画廊内置应用程序中的图像/图片。
我有一个图片的URI(图片位于SD卡上)。
你有什么建议吗?
当前回答
以下是hcpl发布的优良代码的更新。但这适用于OI文件管理器,astro文件管理器和媒体库(测试)。所以我想它将适用于每个文件管理器(除了上面提到的这些,还有很多其他的吗?)修改了他写的代码。
public class BrowsePicture extends Activity {
//YOU CAN EDIT THIS TO WHATEVER YOU WANT
private static final int SELECT_PICTURE = 1;
private String selectedImagePath;
//ADDED
private String filemanagerstring;
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.main);
((Button) findViewById(R.id.Button01))
.setOnClickListener(new OnClickListener() {
public void onClick(View arg0) {
// in onCreate or any event where your want the user to
// select a file
Intent intent = new Intent();
intent.setType("image/*");
intent.setAction(Intent.ACTION_GET_CONTENT);
startActivityForResult(Intent.createChooser(intent,
"Select Picture"), SELECT_PICTURE);
}
});
}
//UPDATED
public void onActivityResult(int requestCode, int resultCode, Intent data) {
if (resultCode == RESULT_OK) {
if (requestCode == SELECT_PICTURE) {
Uri selectedImageUri = data.getData();
//OI FILE Manager
filemanagerstring = selectedImageUri.getPath();
//MEDIA GALLERY
selectedImagePath = getPath(selectedImageUri);
//DEBUG PURPOSE - you can delete this if you want
if(selectedImagePath!=null)
System.out.println(selectedImagePath);
else System.out.println("selectedImagePath is null");
if(filemanagerstring!=null)
System.out.println(filemanagerstring);
else System.out.println("filemanagerstring is null");
//NOW WE HAVE OUR WANTED STRING
if(selectedImagePath!=null)
System.out.println("selectedImagePath is the right one for you!");
else
System.out.println("filemanagerstring is the right one for you!");
}
}
}
//UPDATED!
public String getPath(Uri uri) {
String[] projection = { MediaStore.Images.Media.DATA };
Cursor cursor = managedQuery(uri, projection, null, null, null);
if(cursor!=null)
{
//HERE YOU WILL GET A NULLPOINTER IF CURSOR IS NULL
//THIS CAN BE, IF YOU USED OI FILE MANAGER FOR PICKING THE MEDIA
int column_index = cursor
.getColumnIndexOrThrow(MediaStore.Images.Media.DATA);
cursor.moveToFirst();
return cursor.getString(column_index);
}
else return null;
}
其他回答
除了前面的答案,如果你在获得正确的路径(如AndroZip)有问题,你可以使用这个:
public String getPath(Uri uri ,ContentResolver contentResolver) {
String[] projection = { MediaStore.MediaColumns.DATA};
Cursor cursor;
try{
cursor = contentResolver.query(uri, projection, null, null, null);
} catch (SecurityException e){
String path = uri.getPath();
String result = tryToGetStoragePath(path);
return result;
}
if(cursor != null) {
//HERE YOU WILL GET A NULLPOINTER IF CURSOR IS NULL
//THIS CAN BE, IF YOU USED OI FILE MANAGER FOR PICKING THE MEDIA
cursor.moveToFirst();
int columnIndex = cursor.getColumnIndexOrThrow(MediaStore.MediaColumns.DATA);
String filePath = cursor.getString(columnIndex);
cursor.close();
return filePath;
}
else
return uri.getPath(); // FOR OI/ASTRO/Dropbox etc
}
private String tryToGetStoragePath(String path) {
int actualPathStart = path.indexOf("//storage");
String result = path;
if(actualPathStart!= -1 && actualPathStart< path.length())
result = path.substring(actualPathStart+1 , path.length());
return result;
}
这是一个完整的解决方案。我刚刚用@mad在下面的答案中提供的信息更新了这个示例代码。还可以查看下面来自@Khobaib的解决方案,解释如何处理picasa图像。
更新
我刚刚回顾了我最初的答案,并创建了一个简单的Android Studio项目,您可以从github签出并直接导入到您的系统。
https://github.com/hanscappelle/SO-2169649
(注意多个文件选择仍然需要工作)
单张图片选择
感谢用户mad,支持来自文件探索者的图像。
public class BrowsePictureActivity extends Activity {
// this is the action code we use in our intent,
// this way we know we're looking at the response from our own action
private static final int SELECT_PICTURE = 1;
private String selectedImagePath;
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.main);
findViewById(R.id.Button01)
.setOnClickListener(new OnClickListener() {
public void onClick(View arg0) {
// in onCreate or any event where your want the user to
// select a file
Intent intent = new Intent();
intent.setType("image/*");
intent.setAction(Intent.ACTION_GET_CONTENT);
startActivityForResult(Intent.createChooser(intent,
"Select Picture"), SELECT_PICTURE);
}
});
}
public void onActivityResult(int requestCode, int resultCode, Intent data) {
if (resultCode == RESULT_OK) {
if (requestCode == SELECT_PICTURE) {
Uri selectedImageUri = data.getData();
selectedImagePath = getPath(selectedImageUri);
}
}
}
/**
* helper to retrieve the path of an image URI
*/
public String getPath(Uri uri) {
// just some safety built in
if( uri == null ) {
// TODO perform some logging or show user feedback
return null;
}
// try to retrieve the image from the media store first
// this will only work for images selected from gallery
String[] projection = { MediaStore.Images.Media.DATA };
Cursor cursor = managedQuery(uri, projection, null, null, null);
if( cursor != null ){
int column_index = cursor
.getColumnIndexOrThrow(MediaStore.Images.Media.DATA);
cursor.moveToFirst();
String path = cursor.getString(column_index);
cursor.close();
return path;
}
// this is our fallback here
return uri.getPath();
}
}
选择多张图片
因为有人在评论中要求这些信息,所以最好收集信息。
在intent上设置一个额外的参数EXTRA_ALLOW_MULTIPLE:
intent.putExtra(Intent.EXTRA_ALLOW_MULTIPLE, true);
在Result处理中检查该参数:
if (Intent.ACTION_SEND_MULTIPLE.equals(data.getAction()))
&& Intent.hasExtra(Intent.EXTRA_STREAM)) {
// retrieve a collection of selected images
ArrayList<Parcelable> list = intent.getParcelableArrayListExtra(Intent.EXTRA_STREAM);
// iterate over these images
if( list != null ) {
for (Parcelable parcel : list) {
Uri uri = (Uri) parcel;
// TODO handle the images one by one here
}
}
}
注意,只有API级别18+支持这一点。
万一有用的话;我这样做是为了得到位图:
InputStream is = context.getContentResolver().openInputStream(imageUri);
Bitmap bitmap = BitmapFactory.decodeStream(is);
以上答案正确。我遇到了一个不同的问题,在HTC M8中,我的应用程序在从图库中选择图像时崩溃。我得到的图像路径是空值。我用以下解决方案进行了修正和优化。onActivityResult方法
protected void onActivityResult(int requestCode, int resultCode, Intent data) {
super.onActivityResult(requestCode, resultCode, data);
if ((requestCode == RESULT_LOAD_IMAGE) && (resultCode == RESULT_OK)) {
if (data != null) {
Uri selectedImageUri = null;
selectedImageUri = data.getData();
String[] filePathColumn = { MediaStore.Images.Media.DATA };
Cursor imageCursor = mainActivity.getContentResolver().query(
selectedImageUri, filePathColumn, null, null, null);
if (imageCursor == null) {
return;
}
imageCursor.moveToFirst();
int columnIndex = imageCursor.getColumnIndex(filePathColumn[0]);
picturePath = imageCursor.getString(columnIndex);
if (picturePath == null) {
picturePath = selectedImageUri.getPath();
String wholeID = DocumentsContract
.getDocumentId(selectedImage);
// Split at colon, use second item in the array
String id = wholeID.split(":")[1];
String[] column = { MediaStore.Images.Media.DATA };
// where id is equal to
String sel = MediaStore.Images.Media._ID + "=?";
Cursor cursor = mainActivity.getContentResolver().query(
MediaStore.Images.Media.EXTERNAL_CONTENT_URI,
column, sel, new String[] { id }, null);
columnIndex = cursor.getColumnIndex(column[0]);
if (cursor.moveToFirst()) {
picturePath = cursor.getString(columnIndex);
}
cursor.close();
}
picturePathAbs = new File(picturePath).getAbsolutePath();
imageCursor.close();
}
}
假设在SD卡目录中有一个图像文件夹仅用于图像。
Intent intent = new Intent(Intent.ACTION_GET_CONTENT);
// tells your intent to get the contents
// opens the URI for your image directory on your sdcard
intent.setType("file:///sdcard/image/*");
startActivityForResult(intent, 1);
然后,您可以决定如何处理活动中的内容。
这是一个检索图像路径名称的示例,用您的代码进行测试,以确保您可以处理返回的结果。您可以根据需要更改代码以更好地满足您的需求。
protected final void onActivityResult(final int requestCode, final int
resultCode, final Intent i) {
super.onActivityResult(requestCode, resultCode, i);
// this matches the request code in the above call
if (requestCode == 1) {
Uri _uri = i.getData();
// this will be null if no image was selected...
if (_uri != null) {
// now we get the path to the image file
cursor = getContentResolver().query(_uri, null,
null, null, null);
cursor.moveToFirst();
String imageFilePath = cursor.getString(0);
cursor.close();
}
}
我的建议是尽量让检索图像工作正确,我认为问题是在存储卡上访问图像的内容。看一下在sd卡上显示图像。
如果您能够启动并运行它(可能通过示例提供正确的提供程序),那么您应该能够为您的代码找到一种变通方法。
通过更新这个问题来让我了解你的进展。祝你好运