在windows批处理脚本有点不同，

git rev-parse --verify <branch>

if %ERRORLEVEL% == 0  (
    echo "Yes"
) else (
    echo "No"
)

如果您能设法包括grep。

git branch | grep -q <branch>

git branch --list $branch_name | grep $branch_name

然后检查返回值是0还是1。

git show-branch <BRANCH-NAME> &>/dev/null && echo yes || echo no

git show-ref和git rev-parse都不能在我的情况下工作。

$ git --version
git version 2.21.0

$ git show-branch --list
* [master] mybranch commit

$ BRANCH_NAME=mybranch
$ git rev-parse --verify $BRANCH_NAME
fatal: Needed a single revision

$ git show-ref refs/heads/$BRANCH_NAME
<no otput>
$ [ $? == 0 ] && echo "$BRANCH_NAME exists" || echo "$BRANCH_NAME not exists"
mybranch not exists

最后得到了这个

$ BRANCH_NAME=mybranch
$ SHOW_ALL=`git show-branch --all | grep -w $BRANCH_NAME`
$ [ $? == 0 ] && echo "$BRANCH_NAME exists" || echo "$BRANCH_NAME not exists"
mybranch exists

您也可以使用脚本文件

#!/bin/sh
BRANCH_NAME=mybranch
if grep -Fqe $BRANCH_NAME << EOF
`git show-branch --all`
EOF
then
   echo "$BRANCH_NAME exists"
else
   echo "$BRANCH_NAME not exists"
fi

Git branch -l <branch-name>

如果分支存在，则返回分支名称;如果分支不存在，则返回none