无法恢复md5密码。(任何语言)

但是你可以:

给用户一个新的。

找个彩虹表，也许能找回旧的。

要做到这一点并不容易。这就是首先对密码进行哈希的意义。:)

你应该做的一件事是手动为他们设置一个临时密码，并将其发送给他们。

我不愿提及这一点，因为这是一个坏主意(而且也不能保证一定有效)，但您可以尝试在彩虹表(如milw0rm)中查找散列，看看是否可以通过这种方式恢复旧密码。

在寻找哈希函数的逆函数方面，没有办法“恢复”哈希函数。如前所述，这就是哈希函数的意义所在。它不应该是可逆的，它应该允许快速哈希值计算。因此，找到产生给定哈希值的输入字符串的唯一方法是尝试所有可能的组合。这就是所谓的蛮力攻击。

尝试所有可能的组合需要花费大量时间，这也是为什么使用哈希值以相对安全的方式存储密码的原因。如果攻击者能够访问您的数据库，其中包含所有用户密码，那么无论如何您都会失败。如果您有哈希值和(理想地说)强密码，那么攻击者将很难从哈希值中获取密码。

存储哈希值也没有性能问题，因为计算哈希值相对较快。因此，大多数系统所做的是计算用户输入的密码的哈希值(这很快)，然后将其与用户数据库中存储的哈希值进行比较。

不，不可能反转诸如MD5这样的哈希函数:给定输出哈希值，除非已知关于输入消息的足够信息，否则不可能找到输入消息。

解密不是为哈希函数定义的函数;加密和解密是CBC模式下AES等密码的功能;哈希函数不加密也不解密。哈希函数用于摘要输入消息。顾名思义，没有反向算法可以设计。

MD5 has been designed as a cryptographically secure, one-way hash function. It is now easy to generate collisions for MD5 - even if a large part of the input message is pre-determined. So MD5 is officially broken and MD5 should not be considered a cryptographically secure hash anymore. It is however still impossible to find an input message that leads to a hash value: find X when only H(X) is known (and X doesn't have a pre-computed structure with at least one 128 byte block of precomputed data). There are no known pre-image attacks against MD5.

It is generally also possible to guess passwords using brute force or (augmented) dictionary attacks, to compare databases or to try and find password hashes in so called rainbow tables. If a match is found then it is computationally certain that the input has been found. Hash functions are also secure against collision attacks: finding X' so that H(X') = H(X) given H(X). So if an X is found it is computationally certain that it was indeed the input message. Otherwise you would have performed a collision attack after all. Rainbow tables can be used to speed up the attacks and there are specialized internet resources out there that will help you find a password given a specific hash.

It is of course possible to re-use the hash value H(X) to verify passwords that were generated on other systems. The only thing that the receiving system has to do is to store the result of a deterministic function F that takes H(X) as input. When X is given to the system then H(X) and therefore F can be recalculated and the results can be compared. In other words, it is not required to decrypt the hash value to just verify that a password is correct, and you can still store the hash as a different value.

重要的是使用密码哈希或PBKDF(基于密码的密钥派生函数)来代替MD5。这样的函数指定如何将盐和散列一起使用。这样就不会为相同的密码(来自其他用户或其他数据库)生成相同的散列。由于这个原因，密码哈希也不允许使用彩虹表，只要盐足够大并且正确随机。

Password hashes also contain a work factor (sometimes configured using an iteration count) that can significantly slow down attacks that try to find the password given the salt and hash value. This is important as the database with salts and hash values could be stolen. Finally, the password hash may also be memory-hard so that a significant amount of memory is required to calculate the hash. This makes it impossible to use special hardware (GPU's, ASIC's, FPGA's etc.) to allow an attacker to speed up the search. Other inputs or configuration options such as a pepper or the amount of parallelization may also be available to a password hash.

然而，它仍然允许任何人验证给定H(X)的密码，即使H(X)是密码哈希。密码哈希仍然是确定的，所以如果有人知道所有的输入和哈希算法本身，那么X可以用来计算H(X)，并且-再说一次-结果可以进行比较。

常用的密码散列有bcrypt、scrypt和PBKDF2。还有各种形式的Argon2，它是最近密码哈希竞赛的赢家。在CrackStation上有一篇很好的关于密码安全的博文。

可以使对手无法执行哈希计算来验证密码是否正确。为此，可以使用胡椒作为密码散列的输入。或者，哈希值当然可以使用AES等密码和CBC或GCM等操作模式进行加密。然而，这需要独立存储秘密/密钥，并且比密码哈希有更高的访问要求。

It is not yet possible to put in a hash of a password into an algorithm and get the password back in plain text because hashing is a one way thing. But what people have done is to generate hashes and store it in a big table so that when you enter a particular hash, it checks the table for the password that matches the hash and returns that password to you. An example of a site that does that is http://www.md5online.org/ . Modern password storage system counters this by using a salting algorithm such that when you enter the same password into a password box during registration different hashes are generated.

唯一可以工作的是(如果我们提到密码只是散列，没有添加任何类型的盐来防止重放攻击，如果是这样，你必须知道盐)顺便说一句，得到一个字典攻击工具，许多单词，数字等文件，然后创建两行，一行是单词，数字(在字典中)，另一个是单词的散列，并比较散列，如果匹配你得到它…

这是唯一的方法，不用进行密码分析。