有人能给出一个简单的例子,每秒钟更新一个文本框左右?

我想要制作一个飞行的球,并需要每秒计算/更新球的坐标,这就是为什么我需要某种计时器。

我从这里什么也得不到。


当前回答

如果有人感兴趣,我开始尝试创建一个标准对象来运行在活动UI线程上。好像还行。欢迎评论。我想这是可用的布局设计器作为一个组件拖到一个活动。真不敢相信这样的东西竟然不存在。

package com.example.util.timer;

import java.util.Timer;
import java.util.TimerTask;

import android.app.Activity;

public class ActivityTimer {

    private Activity m_Activity;
    private boolean m_Enabled;
    private Timer m_Timer;
    private long m_Delay;
    private long m_Period;
    private ActivityTimerListener m_Listener;
    private ActivityTimer _self;
    private boolean m_FireOnce;

    public ActivityTimer() {
        m_Delay = 0;
        m_Period = 100;
        m_Listener = null;
        m_FireOnce = false;
        _self = this;
    }

    public boolean isEnabled() {
        return m_Enabled;
    }

    public void setEnabled(boolean enabled) {
        if (m_Enabled == enabled)
            return;

        // Disable any existing timer before we enable a new one
        Disable();

        if (enabled) {
            Enable();
        }
    }

    private void Enable() {
        if (m_Enabled)
            return;

        m_Enabled = true;

        m_Timer = new Timer();
        if (m_FireOnce) {
            m_Timer.schedule(new TimerTask() {
                @Override
                public void run() {
                    OnTick();
                }
            }, m_Delay);
        } else {
            m_Timer.schedule(new TimerTask() {
                @Override
                public void run() {
                    OnTick();
                }
            }, m_Delay, m_Period);
        }
    }

    private void Disable() {
        if (!m_Enabled)
            return;

        m_Enabled = false;

        if (m_Timer == null)
            return;

        m_Timer.cancel();
        m_Timer.purge();
        m_Timer = null;
    }

    private void OnTick() {
        if (m_Activity != null && m_Listener != null) {
            m_Activity.runOnUiThread(new Runnable() {
                @Override
                public void run() {
                    m_Listener.OnTimerTick(m_Activity, _self);
                }
            });
        }
        if (m_FireOnce)
            Disable();
    }

    public long getDelay() {
        return m_Delay;
    }

    public void setDelay(long delay) {
        m_Delay = delay;
    }

    public long getPeriod() {
        return m_Period;
    }

    public void setPeriod(long period) {
        if (m_Period == period)
            return;
        m_Period = period;
    }

    public Activity getActivity() {
        return m_Activity;
    }

    public void setActivity(Activity activity) {
        if (m_Activity == activity)
            return;
        m_Activity = activity;
    }

    public ActivityTimerListener getActionListener() {
        return m_Listener;
    }

    public void setActionListener(ActivityTimerListener listener) {
        m_Listener = listener;
    }

    public void start() {
        if (m_Enabled)
            return;
        Enable();
    }

    public boolean isFireOnlyOnce() {
        return m_FireOnce;
    }

    public void setFireOnlyOnce(boolean fireOnce) {
        m_FireOnce = fireOnce;
    }
}

在活动中,我有这样的onStart:

@Override
protected void onStart() {
    super.onStart();

    m_Timer = new ActivityTimer();
    m_Timer.setFireOnlyOnce(true);
    m_Timer.setActivity(this);
    m_Timer.setActionListener(this);
    m_Timer.setDelay(3000);
    m_Timer.start();
}

其他回答

对于那些不能依赖Chronometer的人,我从其中一个建议中创建了一个实用程序类:

public class TimerTextHelper implements Runnable {
   private final Handler handler = new Handler();
   private final TextView textView;
   private volatile long startTime;
   private volatile long elapsedTime;

   public TimerTextHelper(TextView textView) {
       this.textView = textView;
   }

   @Override
   public void run() {
       long millis = System.currentTimeMillis() - startTime;
       int seconds = (int) (millis / 1000);
       int minutes = seconds / 60;
       seconds = seconds % 60;

       textView.setText(String.format("%d:%02d", minutes, seconds));

       if (elapsedTime == -1) {
           handler.postDelayed(this, 500);
       }
   }

   public void start() {
       this.startTime = System.currentTimeMillis();
       this.elapsedTime = -1;
       handler.post(this);
   }

   public void stop() {
       this.elapsedTime = System.currentTimeMillis() - startTime;
       handler.removeCallbacks(this);
   }

   public long getElapsedTime() {
       return elapsedTime;
   }
 }

要使用..,只需这样做:

 TimerTextHelper timerTextHelper = new TimerTextHelper(textView);
 timerTextHelper.start();

 timerTextHelper.stop();
 long elapsedTime = timerTextHelper.getElapsedTime();

你也可以使用动画器:

int secondsToRun = 999;

ValueAnimator timer = ValueAnimator.ofInt(secondsToRun);
timer.setDuration(secondsToRun * 1000).setInterpolator(new LinearInterpolator());
timer.addUpdateListener(new ValueAnimator.AnimatorUpdateListener()
    {
        @Override
        public void onAnimationUpdate(ValueAnimator animation)
        {
            int elapsedSeconds = (int) animation.getAnimatedValue();
            int minutes = elapsedSeconds / 60;
            int seconds = elapsedSeconds % 60;

            textView.setText(String.format("%d:%02d", minutes, seconds));
        }
    });
timer.start();

我认为你可以用Rx方法来做:

 timerSubscribe = Observable.interval(1, TimeUnit.SECONDS)
            .subscribeOn(Schedulers.io())
            .observeOn(AndroidSchedulers.mainThread())
            .subscribe(new Action1<Long>() {
                @Override
                public void call(Long aLong) {
                      //TODO do your stuff
                }
            });

然后取消这个:

timerSubscribe.unsubscribe();

接收定时器 http://reactivex.io/documentation/operators/timer.html

如果你已经有了时间。

public class Timer {
    private float lastFrameChanged;
    private float frameDuration;
    private Runnable r;

    public Timer(float frameDuration, Runnable r) {
        this.frameDuration = frameDuration;
        this.lastFrameChanged = 0;
        this.r = r;
    }

    public void update(float dt) {
        lastFrameChanged += dt;

        if (lastFrameChanged > frameDuration) {
            lastFrameChanged = 0;
            r.run();
        }
    }
}

您希望UI更新发生在已经存在的UI线程中。

最好的方法是使用一个Handler,它使用postDelayed在延迟后运行一个Runnable(每次运行都安排下一次运行);使用removeCallbacks清除回调。

您已经找到了正确的地方,所以再看一遍,也许可以弄清楚为什么代码示例不是您想要的。(请参见从计时器更新UI的同一篇文章)。